-7
\$\begingroup\$

Write a series of programs in the same language that print “Hello, world!” using n distinct source characters, where n is in [1..10] inclusive (“distinct” meaning that duplicate characters are ignored from character count). The winner is the solution with the most programs, each with distinct n. I suggest making one solution per language, which is treated like a wiki.

Further rules:

  • Case-sensitive ('H' and 'h' are distinct characters)
  • In case-insensitive languages, all non-string-literal characters are assumed to be uppercase.
  • EDIT: No characters ignored by the compiler (comments)
  • Output must be exactly “Hello, world!” (without quotes) - no variations in punctuation or case, and no newline.
  • “Output” can mean either value of the expression or output to stdout.
  • Esoteric programming languages are very much allowed.
  • EDIT: The language must already exist (as of this question being asked).
  • If anyone gets all of [1..10], they are the accepted winner.

Here's a polyglot example:

'Hello, world'

It scores 11 (and thus is not part of a solution) because it includes distinct characters:

'Helo, wrd!
Improve this question
\$\endgroup\$
1
  • \$\begingroup\$ "Esoteric programming languages are very much allowed." Yet you have implicitly disallowed brainfuck and the HQ9+ 'family' \$\endgroup\$
    – Kendall Frey
    Commented Mar 8, 2014 at 23:06

6 Answers 6

Reset to default
6
\$\begingroup\$

DC: 2, 3, 4, 5, 6, 7, 8, 9 and 10 distinct characters

Seeing as the value of an expression is accepted as valid, this should qualify for 2 distinct characters (newlines added for legibility):

1111111111111111111111111111111+
1111111111111111111111111111111+
1111111111111111111111111111111+
1111111111111111111111111111111+
1111111111111111111111111111111+
11111111111111111111111111111+1+
11111111111111111111111111111+1+
1111111111111111111111111111+11+
1111111111111111111111111111+11+
11111111111111111111111111+1111+
11111111111111111111111111+1111+
1111111111111111111111111+11111+
11111111111111111111111+1111111+
11111111111111111111111+1111111+
1111111111111111111111+11111111+
1111111111111111111111+11111111+
1111111111111111111111+11111111+
111111111111111111111+111111111+
111111111111111111111+111111111+
111111111111111111111+111111111+
11111111111111111111+1111111111+
11111111111111111111+1111111111+
11111111111111111111+1111111111+
11111111111111111111+1111111111+
11111111111111111111+1111111111+
11111111111111111111+1111111111+
1111111111111111111+11111111111+
1111111111111111111+11111111111+
1111111111111111111+11111111111+
11111111111111111+1111111111111+
11111111111111111+1111111111111+
11111111111111111+1111111111111+
11111111111111111+1111111111111+
11111111111111111+1111111111111+
11111111111111111+1111111111111+
1111111111111111+11111111111111+
1111111111111111+11111111111111+
1111111111111111+11111111111111+
1111111111111111+11111111111111+
1111111111111111+11111111111111+
1111111111111111+1111111111111+
1111111111111111+1111111111111+
111111111111111111+11111111111+
1111111111111111111+1111111111+
1111111111111111111+1111111111+
1111111111111111111+1111111111+
11111111111111111111111+111111+
11111111111111111111111+111111+
11111111111111111111111+111111+
11111111111111111111111+111111+
11111111111111111111111+111111+
1111111111111111111111111+1111+
1111111111111111111111111+1111+
11111111111111111111111111+111+
111111111111111111111111111+11+
111111111111111111111111111+11+
111111111111111111111111111111+
11111111111111111111111111111+
11111111111111111111111111111+
11111111111111111111111111111+
11111111111111111111111111111+
1111111111111111111111111+
1111111111111111111111111+
11111111111111111111111+
1111111111111111111111+
1111111111111111111111+
1111111111111111111111+
111111111111111111111+
111111111111111111111+
111111111111111111111+
111111111111111111111+
111111111111111111+
111111111111111111+
111111111111111111+
1111111111111111+
1111111111111111+
111111111111111+
111111111111111+
111111111111111+
111111111111111+

The above is equal to Hello, world!, which can be seen by printing it with P. Note that it yields an error, as the first plus sign doesn't have two values on the stack to work with, but that doesn't change the value of the expression (as the error doesn't stop the execution). Replace the first plus sign with a space for the solution with 3 distinct characters.

4 distinct characters:

11dd1d+++ddd++dP+1dd+d+++dP1ddd++d+++ddPP111dddP11d+d+P1d+d+d+dd+d+P+PP1dd+++PPdd++ddd++1+PP

The rest:

2i1001000011001010110110001101100011011110010110000100000011101110110111101110010011011000110010000100001P
3i12000022021201222010112112220012020100011020212102102112221212020P
4i1020121112301230123302300200131312331302123012100201P
5i100103122130403124020421012422302411143103141P
6i2324032511514252112222553531220321252053P
7i2106632145606024426126104063251063041P
Improve this answer
\$\endgroup\$
4
\$\begingroup\$

Brainfuck, n=2, 3, 4, 5, 6, 7, 8

Case n=2: (new lines added for readability)

++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++.
+++++++++++++++++++++++++++++.
+++++++..
+++.
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
+++++++++++++++++++++++++++++++++.
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++.
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
+++++++++.
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++++++.
+++.
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++++++++.
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++++++.
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
+++++++++++++++++++++++++++++++++.

Case n=2 will be our basis.

For case n=3: we add - to the end of the n=2 source.

For case n=4: we add -> to the end of the n=2 source.

For case n=5: we add ->< to the end of the n=2 source.

For case n=6: we add [><] to the beginning of the n=2 source.

For case n=7: we add [><-] to the beginning of the n=2 source.

For case n=8: we add [><,-] to the beginning of the n=2 source.

Note: if you allow comments to be counted, add a anywhere for n=9 and add ab anywhere for n=10.

Improve this answer
\$\endgroup\$
4
\$\begingroup\$

Emacs Lisp: One expression that returns "Hello, World!"

Exactly 10 distinct characters: [s, t, r, i, n, g, ), (, *, +]

(string

(*(+(*)(    *))(+(*(
*(+(*)(*    ))(+(*)(
*))))(*(    +(*)(*)(
*)(*))(*(*(+(*)(*))(
+(*)(*))(+(*)(*)))))
))(+(*)(    *(+(+(*)
(*))(+(*    )(*))))(
*(+(*)(*    ))(+(*)(

*))(+(*)(*))(+(*)(*)
)(+(*)(*)))(*(*(+(*)
(*))(+(*
)(*))(+(*)(*)))(+(*)
(*))(+(*)(*))(+(*)(*
))))(+(*
(+(*)(*))(+(*)(*)))(
*(+(*)(*))(+(*)(*))(

+(+(*)(*
))))(*(+
(*)(*))(
+(*)(*))
(+(*)(*)
)(+(*)(*
))(+(*)(*)))(*(*(+(*
)(*))(+(*)(*))(+(*)(

*)))(+(*
)(*))(*(
+(*)(*))
(+(*)(*)
))))(+(*
(+(*)(*)
)(+(*)(*)))(*(+(*)(*
))(+(*)(*))(+(+(*)(*

))))(*(+(*)(*))(+(*)
(*))(+(*)(*))(+(*)(*
))(+(*)(    *)))(*(*
(+(*)(*)    )(+(*)(*
))(+(*)(    *)))(+(*
)(*))(*(    +(*)(*))
(+(*)(*)))))(+(+(*)(
*)(*))(*(+(*)(*))(+(

*)(*))  (+(*  )(*)))
(*(+(*  )(*)  )(+(*)
(*)))(  *(+(  *)(*))
(+(*)(  *))(  +(*)(*
))(+(*  )(*)  )(+(*)
(*)))(  *(*(  +(*)(*
))(+(*)(*))(+(*)(*))
)(+(*)(*))(*(+(*)(*)

)(+(*)(*)))))(+(*)(*
)(*(+(*)(*))(*(+(*)(
*))(+(*)    (*))))(*
(+(*)(*)    (*)(*))(
*(*(+(*)    (*))(+(*
)(*))(+(    *)(*))))
)(*)(*))(+(*(*(+(*)(
*))(+(*)(*)))(*(+(*)

(*))(+(*)(*))(+(*)(*
)))))(+(*(*(+(*)(*))
(+(*)(*)    )(+(*)(*
))))(+(*    )(*)(*))
(*(+(*)(*))(+(*)(*))
(+(*)(*)   ))(*(+(
*)(*))(+    (*)(*))
)(*(+(*)     (*))(+(

*)(*))(+
(*)(*))(
+(*)(*))
(+(*)(*)
))(*(*(+
(*)(*))(
+(*)(*))(+(*)(*)))(+
(*)(*))(*(+(*)(*))))

)(+(+(*)(*)(*))
(*(+(*)(*))(+(*)(*))
(+(*)(*)    ))(*(+(*
)(*))(+(    *)(*)))(
*(+(*)(*    ))(+(*)(
*))(+(*)    (*))(+(*
)(*))(+(*)(*)))(*(*(
+(*)(*))(+(*)(*

))(+(*)(
*)))(+(*
)(*))(*(
+(*)(*))
(+(*)(*)
))))(+(*

)(*)(*(+

(*)(*))(+(*)(*)))(*(+(*)(*))(+
(*)(*)))(*(+(*)(*))(+(*)(*))(+
(+(*)(*))))(*(+(*)(*))(+(*)(*)
)(+(*)(*))(+(*)(*))(+(*)(*)))(
*(*(+(*)(*))(+(*)(*))(+(*)(*))
)(+(*)(*))(*(+(*)(*))(+(*)(*))
)))(+(*(+(*)(*))(+(*)(*)))(*(+
(*)(*))(+(*)(*))(+(+(*)(*))))(
*(+(*)(*))(+(*)(*))(+(*)(*))(+
(*)(*))(+(*)(*)))(*(*(+(*)(*))
(+(*)(*))(+(*)(*)))(+(*)(*))(*
(+(*)(*))(+(*)(*)))))(+(+(*)(*
))(+(*)(*))(*(+(*)(*))(+(*)(*)
)(+(*)(*))(+(*)(*))(+(*)(*)))(
*(*(+(*)(*))(+(*)(*))(+(*)(*))
)(+(*)(*))(+(*)(*))(+(*)(*))))
(+(*)(*(*(+(*)(*))(+(*)(*)))(*
(+(*)(*))(+(*)(*))(+(*)(*))))))
Improve this answer
\$\endgroup\$
3
\$\begingroup\$

H9+

H
H0
H01
H012
H0123
H01234
H012345
H0123456
H01234567
H012345678
Improve this answer
\$\endgroup\$
7
  • \$\begingroup\$ This is awkward. Wait, is the output exactly “Hello, world!”? What implementation are you using? \$\endgroup\$
    – mudri
    Commented Mar 8, 2014 at 22:34
  • \$\begingroup\$ Yes, I'm pretty sure that's the exact output. I didn't run it, because I don't know of any online (read: convenient) interpreter. \$\endgroup\$
    – Kendall Frey
    Commented Mar 8, 2014 at 22:43
  • \$\begingroup\$ This one doesn't give the correct answer. Please find one that does and run it yourself. \$\endgroup\$
    – mudri
    Commented Mar 8, 2014 at 22:57
  • \$\begingroup\$ @JamesWood, this is exactly what you would have expected if you'd looked at any of the other Hello World questions before posting your one. \$\endgroup\$
    – Peter Taylor
    Commented Mar 8, 2014 at 22:57
  • \$\begingroup\$ @JamesWood I've called out a question on account of that intepreter. It is (and I was) wrong. :) Also note, it's for HQ9+, which apparently doesn't ignore non-instruction symbols. \$\endgroup\$
    – Kendall Frey
    Commented Mar 8, 2014 at 23:00
0
\$\begingroup\$

Actually, 10 bytes

HIKLPTUVZ]

Try it online!

All prefixes of the program output Hello, World!:

H
HI
HIK
HIKL
HIKLP
HIKLPT
HIKLPTU
HIKLPTUV
HIKLPTUVZ
HIKLPTUVZ]
Improve this answer
\$\endgroup\$
0
\$\begingroup\$

99, 3 to 10 distinct chars

999 9 9
99 99999999 999 9
99
99 99999 9 999 9
99
99 99 999 999999
99
99
99 9999999 9999 999 9
99
99 99 9999999 9 999 9 999 9 999 9
99
99 99 999999 9 999999 9
99
9999
99 99999 999 999999 999 9
99
99 9999999 9999 9 999 9
99
99 99 999999 9
99
99 99 999999 999 9
99
99 99999 9999999 9
99

Try it online!

This is just standard 99.

For the rest, replace the 999 with 9a99, 9ab99, etc.

Improve this answer
\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.