74
\$\begingroup\$

Print integers 0 to 100 (inclusive) without using characters 123456789 in your code.

Separator of numbers can be comma or white space (by default <blank>, <horizontal tabulator>, <newline>, <carriage return>, <form feed> or <vertical tabulator>).

Shortest code wins.

\$\endgroup\$
7
  • 16
    \$\begingroup\$ Many tricks are made possible by allowing 0. Which is what makes this challenge interesting, IMO. \$\endgroup\$
    – Arnauld
    Commented Feb 23, 2021 at 17:08
  • 3
    \$\begingroup\$ I thought "do X without Y" questions weren't allowed anymore. \$\endgroup\$
    – Purple P
    Commented Feb 24, 2021 at 3:34
  • 5
    \$\begingroup\$ @PurpleP They're allowed, but discouraged. Interesting ones are fine. \$\endgroup\$
    – rydwolf
    Commented Feb 25, 2021 at 0:06
  • 16
    \$\begingroup\$ Is there a requirement to stop printing at 100? \$\endgroup\$
    – spuck
    Commented Feb 25, 2021 at 16:44
  • 2
    \$\begingroup\$ Can I use non-ASCII encoding? \$\endgroup\$
    – user100411
    Commented Oct 17, 2021 at 20:36

173 Answers 173

1
2 3 4 5 6
145
\$\begingroup\$

R, 9 bytes

F:volcano

Try it online!

The sequence operator : coerces its arguments to integers. F is the boolean FALSE, which gets coerced to 0. volcano is one of the many built-in datasets (it gives topographic information about Maunga Whau in New Zealand); since it is a matrix, : fetches the value at position [1, 1] which is luckily equal to 100. The code is therefore equivalent to 0:100.

This answer was inspired by a conversation with Giuseppe and Kirill L. in the comments under Giuseppe's R answer.

\$\endgroup\$
8
  • 15
    \$\begingroup\$ I thought Mathematica had weird builtins. Why is volcano specifically about Maunga Whau in New Zealand? \$\endgroup\$ Commented Feb 23, 2021 at 20:27
  • 14
    \$\begingroup\$ @cairdcoinheringaahing This dataset was digitized by Ross Ihaka, a New Zealand statistician and one of the creators of R, who then included it in R as a good example for a contour map. I don't know why he chose that volcano; maybe he lived nearby, or maybe that was just the first map he found! \$\endgroup\$ Commented Feb 23, 2021 at 20:58
  • 3
    \$\begingroup\$ @Giuseppe I tried that, but volcano is the only dataset whose first entry is in \$[100, 101)\$. Using anything else than the first entry leads to at least 9 bytes, even for a dataset with a 3-character name (e.g. sum(BOD) or npk[pi], which don't give 100 anyway). I don't think it can get shorter using this approach. \$\endgroup\$ Commented Feb 24, 2021 at 7:08
  • 10
    \$\begingroup\$ Not that it'd change your byte-count, but you could've just used 0 - the rules only say 1-9 are forbidden... \$\endgroup\$ Commented Feb 24, 2021 at 21:45
  • 4
    \$\begingroup\$ Just impressed by the beauty of this answer! \$\endgroup\$
    – Wasif
    Commented Mar 7, 2021 at 16:47
40
\$\begingroup\$

Python 3: 27 23 20 Bytes

Thanks to caird coinheringaahing for -4 bytes, ovs for -3 bytes

print(*range(*b'e'))

I'm pretty poor at golfing, so there's probably a better way to do this.

TIO

\$\endgroup\$
16
  • 2
    \$\begingroup\$ 23 bytes \$\endgroup\$ Commented Feb 23, 2021 at 15:53
  • 2
    \$\begingroup\$ Hey @DonThousand, I accidentally downvoted your submission, my bad, i was upvoting, but it was a misclick, i have fixed my mistake, sorry again. \$\endgroup\$
    – user100752
    Commented Feb 23, 2021 at 15:55
  • 3
    \$\begingroup\$ You can replace ord('e') with *b'e' for -3 bytes. \$\endgroup\$
    – ovs
    Commented Feb 23, 2021 at 16:01
  • 9
    \$\begingroup\$ Strings with a leading b are objects of type bytes, which behave like lists of integers in many ways. This is doing the same as range(*[101]). \$\endgroup\$
    – ovs
    Commented Feb 23, 2021 at 16:07
  • 2
    \$\begingroup\$ @aneroid - that would be a snippet rather than a function or program, so would need to be lambda:[*range(*b'e')] to comply with site defaults, making it longer than the full program print(*range(*b'e')). \$\endgroup\$ Commented Feb 24, 2021 at 20:30
22
\$\begingroup\$

brainfuck, 138 bytes

>>++++++++++<<++++++[>>>++++++++<<<-]++++++[>>>>++++++++<<<<-]++++++++++>++++++++++<[>[>>.>.+<<.<-]++++++++++>>>----------<+<<<-]>>>>+.-..

Try it online!

No numbers is pretty easy, but the golf size is not great... :)

I am sure it can be improved, I am really a beginner in using Brainfuck. I wanted to try it anyway.

How it works:

>>++++++++++<<                LF Char (idx2)
++++++[>>>++++++++<<<-]       Zero char tens (idx3)
++++++[>>>>++++++++<<<<-]     Zero char unit (idx4)
+++++ +++++                   10 counter (tens)
>+++++ +++++<                 10 counter (unit)
[>                            Move to the counter
  [>>.                        Print the tens
    >.+                       Print the unit and increment
     <<.                      Print the LF
       <-]                    Loop 10 times
+++++ +++++                   Restore the counter
>>>----- -----                Restore the digit
  <+                          Increment the tens char
    <<<-]                     Loop everything 10 times
>>>>+.-..                     Print 100 using a cell which is already at char 0
\$\endgroup\$
1
  • 1
    \$\begingroup\$ Welcome to the site, and nice first answer! \$\endgroup\$ Commented Feb 24, 2021 at 10:09
20
\$\begingroup\$

JavaScript (V8), 28 bytes

We cannot write \$100\$ or \$101\$ in hexadecimal with 0's and letters only (0x64 and 0x65 respectively), but we can write \$202\$ (0xCA) and use \$2n<202\$ as the condition of the for loop.

for(n=0;n+n<0xCA;)print(n++)

Try it online!


30 bytes

This version computes \$10^2\$ with the hexadecimal representation of \$10\$.

for(n=0;n<=0xA*0xA;)print(n++)

Try it online!


31 bytes

This version builds the string "100".

for(n=0;n<=-~0+'00';)print(n++)

Try it online!

\$\endgroup\$
1
  • 1
    \$\begingroup\$ The last one could be 1 byte shorter asfor(n=0;n<=0xA+'0';)print(n++). \$\endgroup\$ Commented Feb 27, 2021 at 8:46
19
\$\begingroup\$

Vyxal jHRM, 0 bytes


Try it Online!

Kinda cheating, but whatever.

How?

  # full program
  # H flag presets the stack to 100
  # R flag does range when number is treated as iterable
  # M flag makes range start at 0
  # j flag joins the top of the stack by newlines
\$\endgroup\$
18
\$\begingroup\$

SHENZHEN I/O, 61 bytes, 7¥, 7 Lines

@not
@mov acc dat
@not
tgt acc dat
-mov acc p0
-add x0
slp x0

Outputs 0-100 as simple output, one per time unit. Makes use of the DX300 (XBus <-> Simple Input chip) and LC70G04 (NOT gate), which cost 1¥ each but do not use any power or count as lines of code (the game's measure of code length). These are used to generate a value of 1, which it adds and outputs until it hits 100. The value for 100 is generated using the "not" command, which makes the accumulator 100 if it is value 0, otherwise it sets the acc to 0.

(Not pictured: conversion from simple output to the screen's XBus input, for the visualization.)


SHENZHEN I/O (MCxxxx ASM only), 129 bytes, 8¥, 16 Lines

@not                 | not
@mov acc p0          | mul acc
@mov acc dat         | dgt 0
@not                 | sub p0
add p0               | dgt 0
tgt acc dat          | mul acc
-mov acc x0          | mov acc p0
slp p0               | slx x0

Outputs 0-100 as one XBus output each. Uses only programmable MCxxxx chips, no logic gates or other components. Generates value 1 in a pretty interesting way:

not     # acc = 100
mul acc # 100 * 100 = 999 (max value)
dgt 0   # digit 0 of 999 = 9
sub p0  # 9 - 100 = -91
dgt 0   # digit 0 of -91 = -1
mul acc # -1 * -1 = 1

enter image description here

\$\endgroup\$
17
\$\begingroup\$

Raku, 10 bytes

put 0..Ⅽ

Try it online!

here is the Unicode character ROMAN NUMERAL ONE HUNDRED.

Any other Unicode character with a defined value of 100 could be used:

௱: TAMIL NUMBER ONE HUNDRED
൱: MALAYALAM NUMBER ONE HUNDRED
፻: ETHIOPIC NUMBER HUNDRED
ⅽ: SMALL ROMAN NUMERAL ONE HUNDRED
佰: CJK UNIFIED IDEOGRAPH-4F70
百: CJK UNIFIED IDEOGRAPH-767E
陌: CJK UNIFIED IDEOGRAPH-964C

All are three UTF-8 bytes long, like .

\$\endgroup\$
5
  • \$\begingroup\$ Anytime you have 0..foo, you can use ^foo. So you can get 8 bytes with put ^Ⅽ \$\endgroup\$ Commented Feb 24, 2021 at 3:08
  • \$\begingroup\$ @user0721090601 Incorrect. ^foo is the same as 0..(foo-1), not 0..foo. \$\endgroup\$
    – Sean
    Commented Feb 24, 2021 at 3:54
  • \$\begingroup\$ Ack, duh. Ignore me \$\endgroup\$ Commented Feb 24, 2021 at 4:13
  • \$\begingroup\$ Are there any Unicode characters with a defined value of 101? If so, puts ^ then the character would save bytes \$\endgroup\$ Commented Mar 5, 2021 at 0:51
  • \$\begingroup\$ @cairdcoinheringaahing I checked that before posting my answer, but there aren't any. Not too surprising, really. \$\endgroup\$
    – Sean
    Commented Mar 5, 2021 at 1:02
17
\$\begingroup\$

Jelly, 2 bytes

³Ż

Try it online!

Outputs a list. If the separator must be a single character, 3 bytes

How it works

³ŻK - Main link. Takes no arguments
³   - Yield 100
 Ż  - Range from 0 to 100
  K - Join by spaces (optional)
\$\endgroup\$
11
  • 5
    \$\begingroup\$ wtf happens here xD \$\endgroup\$
    – azro
    Commented Feb 23, 2021 at 18:15
  • 20
    \$\begingroup\$ Languages designed to be used in code golf kinda ruin the aesthetics of code golf. I prefer to see mad-squeezing of daily used languages that are legitimately used in real production environments, instead. \$\endgroup\$ Commented Feb 24, 2021 at 16:07
  • 4
    \$\begingroup\$ @MartinBraun In most challenges (I.e. those more complex than this), creating a competitive answer in a golfing language is just as difficult as doing so in a “real” language. You’ll see that I helped golf the Python answer just above (sorting by votes), and I can tell you that was just as simple as writing this answer \$\endgroup\$ Commented Feb 24, 2021 at 16:11
  • 7
    \$\begingroup\$ @MartinBraun This opinion has been shared a gazillion times on meta. The consensus is, just look at other answers. The R answer in particular is quite beautiful. \$\endgroup\$ Commented Feb 24, 2021 at 17:16
  • 2
    \$\begingroup\$ @Sanctus It is 2 bytes. More specifically, it is the hex bytes 83 D2 (and 4B for the 3 byte version). Jelly uses a custom code page to encode its programs in order to make them more "readable", but if you fed a raw byte stream of those two bytes into the Jelly interpreter, it would produce the same output \$\endgroup\$ Commented Feb 26, 2021 at 15:45
14
\$\begingroup\$

R, 11 bytes

F:(0xA*0xA)
F:0xA^(T+T)

Try it online!

Uses this tip.

Still being beaten by some volcano in New Zealand, though...

Old answer:

R, 16 bytes

F:paste0(+T,0,0)

Try it online!

Thanks to Kirill L. for correcting an error.

R's ASCII=>byte function is utf8ToInt, which unfortunately has an 8 in it. Luckily, : will attempt to coerce its arguments to numeric types, so we construct 100 by pasting together +F (which coerces its value to 0) and two 0s. This would also work, though longer, without a 0 as F:paste(+T,+F,+F,sep="").

Possibly there's a very short builtin dataset with a sum that's close to 100, though I haven't been able to find one.

\$\endgroup\$
8
  • \$\begingroup\$ I believe according to the task, you should start with F rather than T. \$\endgroup\$
    – Kirill L.
    Commented Feb 23, 2021 at 17:19
  • \$\begingroup\$ 9 bytes (but yours is much more elegant!) \$\endgroup\$ Commented Feb 23, 2021 at 17:31
  • \$\begingroup\$ @KirillL. oh yes, my mistake. Thanks. \$\endgroup\$
    – Giuseppe
    Commented Feb 23, 2021 at 17:44
  • 2
    \$\begingroup\$ @Giuseppe, yeah, but F:sum(T|Nile) is still only 13 bytes. \$\endgroup\$
    – Kirill L.
    Commented Feb 23, 2021 at 17:48
  • 1
    \$\begingroup\$ I found out that the volcano dataset leads to a 9 byte answer, which I posted instead. \$\endgroup\$ Commented Feb 23, 2021 at 19:34
12
\$\begingroup\$

Retina 0.8.2, 33 26 24 bytes


,,

,,,,,,
,
,,,,,

$.`

Try it online! Explanation: The first stage inserts two commas, which the second stage increases to 20 (it's complicated). The third stage multiplies by 5 to give 100. The last stage then inserts the number of commas so far at each position.

\$\endgroup\$
6
  • \$\begingroup\$ Nice! You can golf it a bit by computing 100 as 4*5*5 tio.run/##K0otycxL/P@fSwcIuHTAFILmUtFL@P8fAA \$\endgroup\$
    – Leo
    Commented Feb 23, 2021 at 21:49
  • 1
    \$\begingroup\$ @Leo You should have used 0514150 commas for a nice symmetry! \$\endgroup\$
    – Neil
    Commented Feb 23, 2021 at 23:30
  • 1
    \$\begingroup\$ @Leo (Although as it happens I found a shorter solution, which I then verified using a Python script. The only other solution with the same length simply has the first two stages swapped.) \$\endgroup\$
    – Neil
    Commented Feb 23, 2021 at 23:40
  • \$\begingroup\$ As per specification you may not use commas (,). \$\endgroup\$ Commented Sep 6, 2023 at 16:00
  • \$\begingroup\$ @KaiBurghardt I think that's just the way the list of excluded digits is formatted. But you can replace the commas with spaces or s to get an alternative program if you so wish. \$\endgroup\$
    – Neil
    Commented Sep 6, 2023 at 17:21
9
\$\begingroup\$

C (gcc), 38 bytes

f(i){for(i=0;printf("%d ",i++)&'#';);}

Try it online!

Without using digit 0, it would be 39 bytes: i;main(){for(;printf("%d ",i++)&'#';);}

\$\endgroup\$
5
  • \$\begingroup\$ i as a global defaults to 0 saving a couple characters. Just change your main call to f in your example/ \$\endgroup\$ Commented Feb 24, 2021 at 20:58
  • \$\begingroup\$ Actually took I it further and made it recursive for a 2 more characters saved: \$\endgroup\$ Commented Feb 24, 2021 at 21:10
  • \$\begingroup\$ where did you learn this level of programming i don't even understand it \$\endgroup\$ Commented Feb 25, 2021 at 7:59
  • 2
    \$\begingroup\$ @vijaykumar printf returns how many bytes are printed. '#' is as same as number 35 (ASCII 35 for "#"). That's all you need to know to make it work. \$\endgroup\$
    – tsh
    Commented Feb 25, 2021 at 8:08
  • \$\begingroup\$ Capital C would also work - 64+3 = 'C' :) \$\endgroup\$ Commented Feb 25, 2021 at 19:21
9
\$\begingroup\$

Zsh, 12 bytes

seq 0 $[##d]

Attempt This Online!

  • seq: count
    • from 0
    • $[##d]: to the character value of d

Alternative:

Zsh, 12 bytes

!
seq 0 $?00

Attempt This Online!

! does nothing, but fails with exit code 1; $? then retrieves the exit code.

\$\endgroup\$
8
\$\begingroup\$

Bash, 25 23 bytes

seq 0 $(printf %d "'d")

Try it online!

-2 thanks to @manatwork

\$\endgroup\$
5
  • 8
    \$\begingroup\$ Using $(..) is good coding habit, but is longer than `..`. And no need to quote ”%d” as contains nothing special. In change the “'d” contains character with special meaning, but only one, so escaping it with \ is shorter. Try it online! \$\endgroup\$
    – manatwork
    Commented Feb 23, 2021 at 16:23
  • 2
    \$\begingroup\$ What is happening with the 'd? I assume printf is interpreting it as its ascii numeric value but I don't see it mentioned in the docs. \$\endgroup\$
    – Jonah
    Commented Feb 23, 2021 at 16:25
  • \$\begingroup\$ @manatwork thanks! \$\endgroup\$
    – Wasif
    Commented Feb 23, 2021 at 16:27
  • 1
    \$\begingroup\$ How weird, @Jonah. I can't find where I learned about that feature. Only found in the printf specification's Examples section. Maybe Wasif knows a better documentation. \$\endgroup\$
    – manatwork
    Commented Feb 23, 2021 at 16:35
  • 2
    \$\begingroup\$ @Jonah found it few days ago here, Actually I don't know a lot of documentation on bash \$\endgroup\$
    – Wasif
    Commented Feb 23, 2021 at 16:44
8
\$\begingroup\$

PowerShell, 16 12 bytes

-4 bytes thanks to @mazzy!

0..(0xa*0xa)

Try it online!

\$\endgroup\$
4
  • 1
    \$\begingroup\$ Try it online! \$\endgroup\$
    – mazzy
    Commented Feb 23, 2021 at 22:12
  • \$\begingroup\$ @mazzy thanks! I feel silly for having missed that, lol \$\endgroup\$ Commented Feb 24, 2021 at 16:36
  • 1
    \$\begingroup\$ You beat me to it! \$\endgroup\$ Commented Feb 25, 2021 at 15:34
  • \$\begingroup\$ Why not just enter 0..100 \$\endgroup\$
    – Can.U
    Commented Nov 1, 2023 at 6:00
8
\$\begingroup\$

PHP, 30 bytes

First time golfing, I hope I posted this right!

while($q<ord(e))echo+$q++,' ';

Try it online!


Thanks to manatwork and Dewi Morgan's suggestions to improving the code! From 34 to 30 bytes!

The code revisions are in the edit history, removed here so it looks cleaner!

\$\endgroup\$
6
  • 2
    \$\begingroup\$ Welcome to Code Golf! Nice first answer. (Don't worry, you posted it correctly :p) \$\endgroup\$
    – rydwolf
    Commented Feb 24, 2021 at 6:07
  • 1
    \$\begingroup\$ Unfortunately your solution doesn't output 0. While fixing it, you could reduce its size by removing the single quotes, the braces and the parenthesis around echo's argument. I would suggest this: Try it online! \$\endgroup\$
    – manatwork
    Commented Feb 24, 2021 at 6:08
  • 1
    \$\begingroup\$ Nice! The space before quotes can go, too :) \$\endgroup\$ Commented Feb 25, 2021 at 16:35
  • 1
    \$\begingroup\$ Thinking about it, you can also get rid of the third clause if you postincrement and concatenate the variable to the space : `for($q=0;$q<ord(e);)echo$q++." "; Shame none of the permitted separators are characters so they could be unquoted. \$\endgroup\$ Commented Feb 25, 2021 at 16:50
  • 1
    \$\begingroup\$ And we only need the 4 chars $q=0 because null isn't being cast to an int. We can cast to an int to avoid it, but (int) takes 5 bytes. But adding 0 casts to 0, and we can only do that in 2 bytes, though we need to re-add the space after the echo, so it's effectively 3. Still saves us a byte, though! while($q<ord(e))echo 0+$q++." "; (while has the same bytecount as for with just the middle clause used). \$\endgroup\$ Commented Feb 25, 2021 at 17:22
8
+50
\$\begingroup\$

Factor, 46 23 bytes

-23 bytes thanks to Bubbler

0xa sq [0,b] [ . ] each

Try it online!

I've never written anything in Factor before, but it's a surprisingly fun language.

\$\endgroup\$
1
  • 2
    \$\begingroup\$ Thanks for picking up Factor! Lots of golfs are possible on this code. 1) You don't need to dup the 100 in the first place, and then you won't have anything to drop at the end. 2) A range is a sequence, so you can run each on it without >array. 3) There are multiple ways to get the constant 100, such as CHAR: d or 0xa sq. If you want, drop by the Factor chatroom, and I'll explain things further :) \$\endgroup\$
    – Bubbler
    Commented Mar 2, 2021 at 8:35
8
\$\begingroup\$

dc, 13 characters

Thanks to

  • Daemon for reusing stack depth instead of getting it again, to use shorter operator (-1 character)
[zpdA0>x]dsxx

Try it online!

dc, 14 characters

Thanks to

  • Digital Trauma for the twist in using the stack depth efficiently (-2 characters)
[zpzA0!<m]dsmx

Try it online!

dc, 16 characters

0[pz+dA0>i]dsixp

Sample run:

bash-5.0$ dc -e '0[pz+dA0>i]dsixp' | head
0
1
2
3
4
5
6
7
8
9

Try it online!

\$\endgroup\$
2
  • \$\begingroup\$ Similar idea, same score \$\endgroup\$ Commented Feb 23, 2021 at 20:41
  • 1
    \$\begingroup\$ Thanks @DigitalTrauma. I tried that too earlier, but only now, seeing your suggestion I found the more efficient way. \$\endgroup\$
    – manatwork
    Commented Feb 23, 2021 at 20:54
7
\$\begingroup\$

Ruby 22 bytes 12 bytes - thanks to @manatwork

p *0..?d.ord

Try it online!

\$\endgroup\$
2
  • 1
    \$\begingroup\$ A splat * operator will do it instead of .to_a: p *0..?d.ord \$\endgroup\$
    – manatwork
    Commented Feb 23, 2021 at 16:00
  • 2
    \$\begingroup\$ You can switch to Ruby 1.8 and remove the .ord \$\endgroup\$
    – pxeger
    Commented Feb 23, 2021 at 20:02
7
\$\begingroup\$

Vyxal, jH, 1 byte

ʀ

Try it Online!

Flags for the win. The H flag presets the stack to 100, generate range 0 to 100 and then j flag joins on newlines. The flag was around before this challenge too.

\$\endgroup\$
3
  • \$\begingroup\$ This seems to give the wrong output \$\endgroup\$
    – user7467
    Commented Feb 23, 2021 at 22:00
  • \$\begingroup\$ @Anush its fixed \$\endgroup\$
    – lyxal
    Commented Feb 24, 2021 at 1:53
  • \$\begingroup\$ +1, first reaction someone seeing this will be "OMGWTFBBQ wat happens here" XD \$\endgroup\$
    – Wasif
    Commented Jun 7, 2021 at 12:19
7
\$\begingroup\$

Perl, 20, 13, 12, 16 bytes

say for 0..ord d 

Try it online!

\$\endgroup\$
7
  • \$\begingroup\$ You can get rid of $,=",";, but you need ord('d') for it to work. \$\endgroup\$
    – Sake
    Commented Feb 23, 2021 at 16:03
  • 1
    \$\begingroup\$ @PaulPicard: unquoted dee works here (perl v5.32.0), e.g. perl -E 'say 0..ord(d)' \$\endgroup\$
    – Thor
    Commented Feb 23, 2021 at 16:08
  • 2
    \$\begingroup\$ You can remove the parenthesis. \$\endgroup\$
    – manatwork
    Commented Feb 23, 2021 at 16:11
  • \$\begingroup\$ Without the comma, this doesn't meet the challenge specification to have a separator between numbers. say for 0..ord d would meet the rules. \$\endgroup\$
    – Xcali
    Commented Feb 24, 2021 at 0:01
  • \$\begingroup\$ @Xcali: indeed, thanks \$\endgroup\$
    – Thor
    Commented Feb 24, 2021 at 5:18
7
\$\begingroup\$

Zsh, 16 bytes

echo {0..$[##d]}

Try it online!

Only builtins, so no seq


For fun, here's a 17 byte answer without 0:

echo {$?..$[##d]}

Try it online!

Also $! or $# will work as 0 replacements.

\$\endgroup\$
1
  • \$\begingroup\$ Coreutils solution for 14B: jot - 0 $[##d] \$\endgroup\$
    – roblogic
    Commented Nov 10, 2021 at 1:55
7
\$\begingroup\$

Bash, 18 16 14 bytes

seq 0 $[++x]00

Try it online!

Thanks @manatwork for -2, @Jonah for -2

\$\endgroup\$
3
  • \$\begingroup\$ You don't need the braces. \$\endgroup\$
    – manatwork
    Commented Feb 27, 2021 at 2:53
  • \$\begingroup\$ Welcome to Code Golf! Nice first answer. \$\endgroup\$
    – rydwolf
    Commented Feb 27, 2021 at 4:14
  • \$\begingroup\$ seq 0 $[++x]00 for 14. \$\endgroup\$
    – Jonah
    Commented Feb 28, 2021 at 3:43
7
\$\begingroup\$

Perl 5 (ppencode-compatible), 64 bytes

You didn't clarify that I must separate each with exactly one character, so here it is mine.

print length uc xor s qq q xor print while length ne ord qw q eq

Try it online!

Explained

   # print(length) did not work for zero as $_ is not defined at then
   print length uc xor
   s qq q xor
   # delimiter
   print
while
   # equals to: length ne 101
   length ne ord qw q eq
\$\endgroup\$
7
\$\begingroup\$

Bash, 15

seq `dc<<<A0Kf`

Try it online!

  • 1 byte saved, thanks to @manatwork.

Previous answer:

Pure Bash (no external utilities), 23

  • 9 bytes saved thanks to @ArcticKona.
eval echo {0..$[++x]00}

Try it online!

\$\endgroup\$
7
  • \$\begingroup\$ Your newest solution skips “0” because you missed a space between seq's parameters. Sorry, that looks like +1 character. ☹ \$\endgroup\$
    – manatwork
    Commented Feb 23, 2021 at 20:28
  • \$\begingroup\$ @manatwork oops - yes, thanks - fixed. \$\endgroup\$ Commented Feb 23, 2021 at 20:30
  • 1
    \$\begingroup\$ As apology, here is a 15 character one, still based on your idea: seq `dc<<<A0Kf`. \$\endgroup\$
    – manatwork
    Commented Feb 23, 2021 at 20:31
  • \$\begingroup\$ @manatwork - thanks! \$\endgroup\$ Commented Feb 23, 2021 at 20:43
  • 1
    \$\begingroup\$ for pure bash try eval echo {0..$[++x]00} \$\endgroup\$ Commented Oct 29, 2021 at 7:40
7
\$\begingroup\$

PICO-8, 50 45 bytes

i=0-#"0"repeat i+=#"0"?i
until#tostr(i)>#"00"

-5 bytes by replacing print with its shorthand, ?.

Demo (50 byte version; 45 byte version has same output):

i=0-#"0"repeat i+=#"0"print(i)until#tostr(i)>#"00"

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1
  • 3
    \$\begingroup\$ Glad to see some PICO-8 on CGCC! It's such a fun little engine to tinker around with. \$\endgroup\$ Commented Nov 3, 2021 at 8:50
7
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Javascript, 48 bytes

for(a of Array("e".charCodeAt()).keys())alert(a)

Can be shorter, if you allow in reverse (36 chars)

for(i="e".charCodeAt();--i;)alert(i)
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3
  • \$\begingroup\$ Your 50 bytes solution doesn't output 0. To fix it just remove that unnecessary pre-incrementation and change the "d" to "e". \$\endgroup\$
    – manatwork
    Commented Feb 27, 2021 at 22:22
  • \$\begingroup\$ @manatwork i thought we didnt have to print 0, at the time i wrote the solution. I'll fix it :) thanks \$\endgroup\$
    – user100752
    Commented Feb 28, 2021 at 16:52
  • \$\begingroup\$ 40 forward \$\endgroup\$
    – l4m2
    Commented Mar 28, 2022 at 19:20
7
+25
\$\begingroup\$

Python, 25 23 bytes

print(*range(ord('e')))

-2 by Steffan, remove first parameter (0) from call to range

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2
  • 1
    \$\begingroup\$ The 0, is not needed \$\endgroup\$
    – naffetS
    Commented Jul 7, 2022 at 19:54
  • 1
    \$\begingroup\$ Thanks a lot! I'll use it. \$\endgroup\$
    – Eric Xue
    Commented Jul 8, 2022 at 1:41
6
\$\begingroup\$

GNU Octave, 14, 5 bytes

0:'d'

TIO by Giuseppe

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3
  • 1
    \$\begingroup\$ I think just 0:'d' should work. \$\endgroup\$
    – Giuseppe
    Commented Feb 23, 2021 at 16:14
  • \$\begingroup\$ @Giuseppe: nice one \$\endgroup\$
    – Thor
    Commented Feb 23, 2021 at 16:17
  • 2
    \$\begingroup\$ Also, Octave is on TIO if you want to add a link :-) \$\endgroup\$
    – Giuseppe
    Commented Feb 23, 2021 at 16:19
6
\$\begingroup\$

05AB1E, 2 bytes

тÝ

Try it online!

Outputs a list. If the separator must be a single character, 3 bytes

How it works

тÝ» - Full program
т   - Push 100
 Ý  - Range from 0 to 100
  » - Join with newlines (optional)
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6
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Deadfish~, 2071 / 8 / 7 bytes

2071 bytes

o{i}c{d}io{i}dc{d}iio{i}ddc{d}iiio{i}dddcddddddoiiiiiicdddddoiiiiicddddoiiiicdddoiiicddoiicdoicociodciioddciiiodddciiiioddddciiiiiodddddciiiiiioddddddc{i}dddo{d}iiic{i}ddo{d}iic{i}do{d}ic{i}o{d}c{i}io{d}dc{i}iio{d}ddc{i}iiio{d}dddc{i}iiiio{d}ddddc{i}iiiiio{d}dddddc{i}iiiiiio{d}ddddddc{i}{i}dddo{d}{d}iiic{i}{i}ddo{d}{d}iic{i}{i}do{d}{d}ic{i}{i}o{d}{d}c{i}{i}io{d}{d}dc{i}{i}iio{d}{d}ddc{i}{i}iiio{d}{d}dddc{i}{i}iiiio{d}{d}ddddc{i}{i}iiiiio{d}{d}dddddc{i}{i}iiiiiio{d}{d}ddddddc{i}{i}{i}dddo{d}{d}{d}iiic{i}{i}{i}ddo{d}{d}{d}iic{i}{i}{i}do{d}{d}{d}ic{i}{i}{i}o{d}{d}{d}c{i}{i}{i}io{d}{d}{d}dc{i}{i}{i}iio{d}{d}{d}ddc{i}{i}{i}iiio{d}{d}{d}dddc{i}{i}{i}iiiio{d}{d}{d}ddddc{i}{i}{i}iiiiio{d}{d}{d}dddddc{i}{i}{i}iiiiiio{d}{d}{d}ddddddc{{i}dddddd}dddo{{d}iiiiii}iiic{{i}dddddd}ddo{{d}iiiiii}iic{{i}dddddd}do{{d}iiiiii}ic{{i}dddddd}o{{d}iiiiii}c{{i}dddddd}io{{d}iiiiii}dc{{i}dddddd}iio{{d}iiiiii}ddc{{i}dddddd}iiio{{d}iiiiii}dddc{{i}dddddd}iiiio{{d}iiiiii}ddddc{{i}dddddd}iiiiio{{d}iiiiii}dddddc{{i}dddddd}iiiiiio{{d}iiiiii}ddddddc{{i}ddddd}dddo{{d}iiiii}iiic{{i}ddddd}ddo{{d}iiiii}iic{{i}ddddd}do{{d}iiiii}ic{{i}ddddd}o{{d}iiiii}c{{i}ddddd}io{{d}iiiii}dc{{i}ddddd}iio{{d}iiiii}ddc{{i}ddddd}iiio{{d}iiiii}dddc{{i}ddddd}iiiio{{d}iiiii}ddddc{{i}ddddd}iiiiio{{d}iiiii}dddddc{{i}ddddd}iiiiiio{{d}iiiii}ddddddc{{i}dddd}dddo{{d}iiii}iiic{{i}dddd}ddo{{d}iiii}iic{{i}dddd}do{{d}iiii}ic{{i}dddd}o{{d}iiii}c{{i}dddd}io{{d}iiii}dc{{i}dddd}iio{{d}iiii}ddc{{i}dddd}iiio{{d}iiii}dddc{{i}dddd}iiiio{{d}iiii}ddddc{{i}dddd}iiiiio{{d}iiii}dddddc{{i}dddd}iiiiiio{{d}iiii}ddddddc{{i}ddd}dddo{{d}iii}iiic{{i}ddd}ddo{{d}iii}iic{{i}ddd}do{{d}iii}ic{{i}ddd}o{{d}iii}c{{i}ddd}io{{d}iii}dc{{i}ddd}iio{{d}iii}ddc{{i}ddd}iiio{{d}iii}dddc{{i}ddd}iiiio{{d}iii}ddddc{{i}ddd}iiiiio{{d}iii}dddddc{{i}ddd}iiiiiio{{d}iii}ddddddc{{i}dd}dddo{{d}ii}iiic{{i}dd}ddo{{d}ii}iic{{i}dd}do{{d}ii}ic{{i}dd}o{{d}ii}c{{i}dd}io{{d}ii}dc{{i}dd}iio{{d}ii}ddc{{i}dd}iiio{{d}ii}dddc{{i}dd}iiiio{{d}ii}ddddc{{i}dd}iiiiio{{d}ii}dddddc{{i}dd}iiiiiio{{d}ii}ddddddc{{i}d}dddo{{d}i}iiic{{i}d}ddo{{d}i}iic{{i}d}do{{d}i}ic{{i}d}o{{d}i}c

Try it online!

8 bytes (if you consider Hello, world! a valid separator)

o{{iow}}

Try it online!

7 bytes (If you don't care about seperators)

o{{io}}

Try it online!

Never thought I'd see deadfish be shorter than, well, anything except Unary.

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4
  • \$\begingroup\$ Damn it. Rewriting. \$\endgroup\$
    – emanresu A
    Commented Feb 24, 2021 at 3:30
  • \$\begingroup\$ @Razetime Remebered w doesn't care about accumulator. \$\endgroup\$
    – emanresu A
    Commented Feb 24, 2021 at 3:32
  • \$\begingroup\$ "Hello, World!" is not a valid separator. \$\endgroup\$ Commented Feb 24, 2021 at 4:10
  • 1
    \$\begingroup\$ Haha reading up on Deadfish~ I realized that exact 7 byte program... but you beat me to it! I actually wrote a Deadfish interpreter for Code Golf that automatically had spaces between output, just because the BASIC interpreter put them there. 😄 Perfect for than program! \$\endgroup\$ Commented Mar 7, 2021 at 16:30
1
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