Print 0 to 100 without 1-9 characters

Question

Print integers 0 to 100 (inclusive) without using characters 123456789 in your code.

Separator of numbers can be comma or white space (by default <blank>, <horizontal tabulator>, <newline>, <carriage return>, <form feed> or <vertical tabulator>).

Shortest code wins.

Answer 1

Batch, 56 bytes

@set/ax=0xb-0xa
@for /l %%b in (0,%x%,%x%00)do @echo %%b

-61 bytes for @Neil

Answer 2

Red, 36 bytes

repeat n 0 +#"e"[print n +#"a"-#"b"]

Try it online!

Answer 3

C (gcc), 40 39 bytes

Saved a byte thanks to att!!!

f(i){for(i=0;i<'e';)printf("%d ",i++);}

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Answer 4

C++ gcc, 36 bytes

Try it online!

main(){for(;_<'e';)cout<<_++<<'\n';}

Explanation : I globally initialized varible _ so its initial value is 0, now ascii value of e is 101 so I ran the loop till my variable _ is less than 'e', instead of incrementing it inside the for loop I used post increment while printing to save 1 byte

edit: I misread the question and thought 0 is also not allowed :)

Answer 5

APOL, 11 bytes

f(ô p(∈));ô

I would've used ⅎ instead of f, but the rules state that you have to include 0 so the fastest route was to just print 0-99 and slap 100 at the end.

Answer 6

APL, 13 bytes

0,⍳⍎'00',⍨⍕*0

*0 ⍝ Exponential of zero = 1
⍕ ⍝ Convert to symbol '1'
'00',⍨ ⍝ Append two zeros
⍎ ⍝ Convert to number 100
⍳ ⍝ Make sequence from 1 to 100
0, ⍝ Append zero to the left