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user:1234 user:me (yours) |
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answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
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title:apples body:"apples oranges" |
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Results tagged with integer
Search options not deleted
user 74571
For challenges involving the manipulation of integers.
2
votes
How quickly can you type this unary string?
Python3, 327 bytes
R=range
def f(n):
q,s,r=[(0,0)],[],[]
for a,c in q:
if a==n:r+=[c];continue
if r and c>=min(r):continue
if a<3:q+=[(a+1,c+1)]
else:
U=[(a+1,c+1)]
for i in R(3,min(a, …
- 7,711
1
vote
Manipulate integers to zero
Python3, 292 bytes
lambda v:0 in[*f(v)]
R=range
def f(v):
k=[v]
for i in R(len(v)):
for j in R(i+1,len(v)+1):
if j-1>1 and j-i<len(v):
for t in f(v[i:j]):k+=[v[:i]+[t]+v[j:]]
for i in k:
…
- 7,711
4
votes
Is it a Frog List?
Python3, 498 bytes:
E=enumerate
def V(x,l):r=len(K:=set({x[i+1]-a for i,a in E(x)if i+1<len(x)}));return r==1and max(x)+max(K)>=len(l)
T=lambda x:[*filter(None,x)]
P=sorted
def f(l):
if len(T(l))==1: …
- 7,711
3
votes
Find a matrix whose sliding sum is the input
Python3, 556 bytes:
from itertools import*
R=range
D=lambda l,y:l*y-(y-1)*(l-1)
def O(V,v):
c=0
while c:=c+1:
for i in product(*[[R(-c,c+1),[a]][b]for a,b in V]):
if sum(i)==v:return[*i]
def f( …
- 7,711
1
vote
Line Islands in a Word Search
Python3, 560 bytes:
lambda w:len({str(i[0])for i in g(w)})
S=lambda a:[(t:=(a[1][0]-a[0][0])/([1,(k:=a[1][1]-a[0][1])][k!=0])*(k>0)),[a[0][1],t*-1*a[0][1]+a[0][0]][k!=0]]
M=lambda j,k:[(x:=(k[1]-j[1]) …
- 7,711
5
votes
How-many-bonacci-like is this sequence?
Python3, 102 bytes:
lambda x,c=0:(v(x,c)and c)or(x and f(x,c+1))
v=lambda x,i:len(x)<=i or(sum(x[:i])==x[i]and v(x[1:],i))
Try it online!
- 7,711