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Python 2 - 59 Supply the string as the variable n import re;print re.sub('\d+',lambda x:`int(x.group())+1`,n) …

Javascript I know this isn't code golf, but I want to golf it anyway. :) var r=new XMLHttpRequest r.open("GET","https://gist.githubusercontent.com/mshafrir/2646763/raw/f2a89b57193e71010386a7397 …

Python 3, 148 bytes import re print(all(i in open("most used.txt").read().lower().split(' ')for i in re.sub("[^a-z ']+","",input().replace("-"," ").lower()).split(" "))) Outputs True and False Exa …

Python 3, 88 bytes Thanks @WorldSEnder s=" ";n=s+input()+s b=len(n) h="#";x=h*(b+2);y=h+s*b+h;z="\n" print(x+z+y+z+h+n+h+z+y+z+x) Example I/O: This is a test ################## # # …

JavaScript, 47 bytes Nice and simple. Edit: Now complies with the rules function f(g){if(g=="google")a;return g.length} Testing Error thrown function f(g){if(g=="google")a;return g.length} …

Python 2, 52 bytes import sys;print''.join(sys.stdin.readlines()[::-1])

Fourier, 32 bytes I~zo115a-3avaa-4a121az+2o109a-8a Still using @isaacg's golfing algorithm ;)

Fourier, 27 bytes 92~SI~N%2{1}{47~S}N(Sai^~i) Try it online!

Python 3, 104 bytes Meh. n='\n';lambda x,y:x+n+n.join(x[:-i]for i in range(1,len(x)-1))+n+n.join(y[:i]for i in range(1,len(y)+1)) Thanks to @DJMcMayhem for golfing 21 bytes off. Ideone it!

Python 3, 47 bytes Thanks to @deustice lambda s:''.join(s[:i]for i in range(len(s)+1)) Ideone it!

Python 3, 214 bytes import time,random o,f=list(input()),list(input()) F=len(f);O=len(o);o+=[" "]*(F-O);f+=[" "]*(O-F);p=-1;l=[p] while o!=f: while p in l:p=random.randrange(max(F,O)) l+=[p];o[p]=f …

When inputting a string, enclose it in quotation marks Explanation: I - Push input to stack "\d+$" - Push string to stack - - Remove characters from first string which match the regex I … - Push input to stack + - Append to the first string P - Print top item of stack …

Loops through each character in the string, inverting each character. … Explanation: I - Push input to stack ~s - Store the top of the stack in the variable s L - Pop string off the top and push its length ( - Pop off the stack and repeat code between brackets until stack …

Uses the regex [aeiouAEIOU] to remove the vowels from the input string. …

Python 3, 54 bytes Thanks Python for having a built-in function for this task! :D import os;print(os.path.commonprefix(input().split())) Takes input as two words separated by a space such as gloss …