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The challenge involves mathematics in some central way. Also consider using more specific tags, listed in the tag wiki info.
2
votes
Write a program that makes 2 + 2 = 5
C++
This is similar to some other methods, but I think slightly sneakier because at a glance it looks extremely straightforward.
#include "iostream.h"
int main()
{
int TWO = 2 …
2
votes
Write a program that makes 2 + 2 = 5
Whitespace, (looks like C++)
I don't know if this qualifies, but I thought it was fun
raw paste data here.
online interpreter here.
#include<iostream>
int main() {
…
6
votes
Residue Number System
GAP
Some Background: I will admit that when I created this question, so many months ago, I did not have a method for solving the hard part of this question: determining the correct number of primes to …
2
votes
Cofactor Matrices
GAP doesn't really have the same tools to deal with matrices that other math oriented languages do. The only thing really used here is the built in determinant operator. …
27
votes
3
answers
3k
views
Residue Number System
In the vein of large number challenges I thought this one might be interesting.
In this challenge, we will be using the Residue Number System (RNS) to perform addition, subtraction, and multiplicati …
2
votes
XOR multiplication
GAP, 368 Bytes
For mathematicians, this is multiplication in the polynomial ring F_2[x], identifying polynomials with natural numbers by evaluating at x=2 as a polynomial over Z.
Sure, let's do …
3
votes
Find the nth Fibohexaprime
GAP, 204 Bytes
This answer is pretty unremarkable, except that GAP is cool enough to be able to find the next couple fibohexaprimes (and cooler still, it finds these in milliseconds with the given cod …
11
votes
Calculate the number of primes up to n
Rust, 0.37001 sec (12 June 2016)
About 10 times slower than slower than Dennis' C answer, but 10 times faster than his Python entry. This answer is made possible by @Shepmaster and @Veedrac who helped …
74
votes
16
answers
15k
views
Calculate the number of primes up to n
π(n) is the number of primes less than or equal to n.
Input: a natural number, n.
Output: π(n).
Scoring: This is a fastest-code challenge. Score will be the sum of times for the score cases. I wi …