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The challenge involves mathematics in some central way. Also consider using more specific tags, listed in the tag wiki info.

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Identify the Conic Section

Matlab, 154 bytes p=input();c=null([p.^2 prod(p,2) p 1+p(:,1)*0]),s={'circle' 'ellipse' 'parabola' 'hyperbola'};s{3+sign(c(3)^2-4*c(1)*c(2))-~max(abs(c(3)),abs(c(1)-c(2)))} Saved some bytes thanks …
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3 votes

Derivative at the Edge

MATL, 21 15 bytes 2/d1)6Mh8Mt0)h+ TryItOnline Halves the input vector, and takes successive differences, to give d=[i(2)-i(1) i(3)-i(2) ... i(end)-i(end-1)]/2 and then makes two modified vectors, …
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2 votes

Where should I put my restaurant?

MATLAB, 42 If it is OK to take input as I=[5.7 3.2 8.9 8.1] then this statement fminunc(@(y)sum(hypot(I(:,1),I(:,2)-y)),0) returns 5.113014445748538. Shamelessly stealing Thomas Kwa's meth …
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  • 1,316
3 votes

Find the number in the Champernowne constant

MATL, 22 bytes it10+:Yst' '=~)wYsXf1) Take the input (i), make the vector 1 to input+10 (10+:), converts the vector to a string (Ys), and remove the spaces, which is painful, (t' '=~)). Then, conve …
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12 votes

Smallest integers after N divisible by 2, 3, and 4

MATL, 8 bytes Qt_2:4\+ Uses Denis' Jelly algorithm, I'm surprised it's the same length! Try it online, or, verify all test cases. Q % takes implicit input and increments by one t_ % duplicat …
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1 vote

Divisor reduction

MATL, 13 bytes tX`t:\ztt]Nq& Try it online Explanation: t % Duplicate input X` ] % while loop, consumes 1 input t:\z % calculates n-d(n), by counting number no …
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4 votes

Two steps forward and one step back

MATL, 7 bytes Uses the 3*n-4*(n>1) formula. Multiply input by 3 (3*), push input again (G) and decrement it (q). If the result is not zero (?) then subtract 4 from the result (4-). 3*Gq?4- Try it …
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6 votes

Output the Juggler sequence

MATL, 13 12 bytes `tt2\.5+^ktq Try it online! Explanation ` % do...while loop tt % duplicate top of stack twice, takes implicit input on first iteration 2\ % take a_k mod 2 .5+^ % adds …
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1 vote

Solve an algebraic expression

Matlab, 61 bytes x=[1 0];a=eval([strrep(input(''),'=','-(') ')']);a(2)/diff(a) Uses the same algorithm as Ton Haspel to solve the equation. Replaces the = by -( and adds a ) at the end to make the …
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