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| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
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answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
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| Code | code:"if (foo != bar)" |
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title:apples body:"apples oranges" |
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Results tagged with restricted-source
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user 2248
Imposes a restriction on the source code used to solve the challenge, for example, having no numbers in the source code.
1
vote
Hello World 0.0!
Python 272 chars
s=ord('O')
a=len('0')
b=a+a
c=b+a
d=c+a
e=d+a
f=e+a
g=f+a
h=g+a
print chr(s-g)+chr(s+g*c+a)+chr(s+g*d+a)+chr(s+g*d+a)+chr(s+h*d)+chr(s-h*f+a)+chr(s+h)+chr(s+h*d)+chr(s+g*e)+chr(s+g*d …
- 599
4
votes
Divide a number by 3 without using *, /, +, -, % operators
Python2.6 (29)(71)(57)(52)(43)
z=len(range(2,abs(x),3))
print (z,-z)[x<0]
print len(range(2,input(),3))
Edit - Just realized that we have to handle negative integers too. Will fix that later
…
- 599