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OIL, 12 bytes Can handle infinite input, but the input has to be newline-terminated (any other way isn't possible in OIL currently). 5 9 4 9 11 6

Aceto, 5 bytes When reading input, Aceto always waits for a newline, meaning input has to be \n-terminated. pn r< In the current version, EOF will crash the program, but that only prints to STDERR.

Aceto, 38 bytes cC|d dXpc =`I& LM-1I d@7F& €92- r4*2 Explanation We first read the input string and explode it (€, put the characters on the stack). …

Aceto, 21 17 bytes ,p p '@'p pQ$d r- I'm sure we can fit this into a 4x4, but I just couldn't do it.. Reads a value, splits it on whitespace, "unqueues" it (a b c -> c a b), prints the first element, …

Aceto, 16 12 9 bytes =01` ,'pO Run with -F to see immediate output (but works without). Explanation: We read a character, then push the character 0 on the stack and test for equality: =0 ,' If equal …

Aceto, 5 bytes Trivial in Aceto: p ,'O Reads a character, pushes a space, prints it, and goes back to the start.

Aceto, 8 bytes >v np rk Uses sticky mode to avoid having to duplicate the string. …

OIL, 12 bytes 5 4 11 6 2 Read a value into the 0th line, print the value in the 0th line, print a newline, then jump to line 2.

Aceto, 8 7 6 bytes ,!`XpO Explanation: Read a character (,), negate it (!) and conditionally exit. Print the zero on top of the stack (p) and go back to the beginning. Run with -F to see the effect i …

Python 3, 211 208 195 bytes lambda S,p="()<>[]{}qpbd\/",s=" !\"'+*-.:=AHIMOTUVWXY^_ovwx|":(S==S.translate({ord(s[2*x]):s[2*x+1]for s in(p,p[::-1])for x in range(7)})[::-1])*(~len(S)%2*s[len(S)//2]in s …

OIL, 52 49 bytes noncompeting Note: The second line contains a space character. 5 12 0 23 10 24 3 7 10 4 24 4 1 8 11 1 11 6 6 5 I explode the input string, then print each character and then a space …

We duplicate the empty string, read a single character (,), duplicate that character, and move it to the original stack ({). … Still on the right stack, we compare the top two values (the empty string and our character) and use the conditional mirror to jump to the right edge if they are equal: =|. …

Python 3, 117 112 105 100 98 76 62 61 59 bytes def p(s):x=next(s);yield from[x]*(x>"-")or[*p(s),*p(s),"-"] Changelog: removed linebreaks where possible (-5 bytes) lambda instead of a full functio …

Aceto: 5 bytes ,dppO Doesn't work on TIO, because it hangs indefinitely. Buffering might prevent you from seeing the result, run with -F to immediately flush all output.

rM@dp Explanation We read a string and €xplode it, push the stack length and Memorize that. Then, after setting the exception catch point (@), we always duplicate the top stack element, negate (!) … it, and m|rror horizontally if we get a truthy value (string has ended; we popped a 0). Otherwise, we get the ordinal of the character, Load the memorized value and do modulo (%). …