Build me a brick wall!

Question

Challenge

I need help building a brick wall! Throw together some code for me using no input and produce the following output wall shown below:

_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__

Now, this wall is exactly 10 characters high and 70 characters wide.

As stated above, no inputs, only code. Least amount of bytes, we have to efficiently build this brick wall. Obviously, this program has to function to get the wall built..? or it obviously won't build itself! Good luck!

Winner

The winner goes to Marinus using the APL language, requiring a whole 12 bytes! https://codegolf.stackexchange.com/a/99028/61857

Thank you everyone for participating!

That's OK. I'll let you know when I have a working interpreter. I'm working on it right now, actually :) — ETHproductions, Commented Nov 10, 2016 at 14:20

SQB · Accepted Answer · 2016-11-09 12:39:43Z

192

Trumpscript, 303 285 244 231 226 bytes

make i 1000005-1000000
as long as,i;:
make i,i - fact;
say "_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|"
say "___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__"!
America is great

I would like to say this is one of the most verbose languages where almost everything fails to compile into a working program.

Apparently whether - works instead of minus is completely up to the interpreter and sometimes works. This time it did so I'm putting it in as golfed.

Abuses the fact Trumpscript is written in Python and therefore fact when used as an integer is one.

Golfing tips welcome.

edited Nov 9, 2016 at 12:39

SQB

8018 silver badges19 bronze badges

answered Nov 8, 2016 at 20:35

Blue

28.6k8 gold badges52 silver badges100 bronze badges

50

\$\begingroup\$ I take it Trumpscript doesn't allow numbers less than 1,000,000? ;-) \$\endgroup\$
– ETHproductions
Commented Nov 8, 2016 at 20:45
3

\$\begingroup\$ you are correct. \$\endgroup\$
– Blue
Commented Nov 8, 2016 at 20:52
2

\$\begingroup\$ Can you use i is 1000005-1000000 and i is i-fact? (Just taken a look at the readme of Trumpscript.) \$\endgroup\$
– AlexRacer
Commented Nov 8, 2016 at 22:31
21

\$\begingroup\$ I'm surprised it allows you to use 1000000. Documentation states All numbers must be strictly greater than 1 million. The small stuff is inconsequential to us.. \$\endgroup\$
– Mad Physicist
Commented Nov 10, 2016 at 20:41
12

\$\begingroup\$ Fact and lies (and other truth/false constants) have a random, time based chance to flip flop (be reversed) during tokenization (see tokenizer.py, search flip_flop) may be why it seemed to not work with minus, when really it had to do with fact at that point in time \$\endgroup\$
– pinkfloydx33
Commented Nov 12, 2016 at 1:21

| Show 4 more comments

marinus · Accepted Answer · 2016-11-08 18:11:35Z

49

APL, 12 bytes

10 70⍴'_|__'

Output:

      10 70⍴'_|__'
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__

answered Nov 8, 2016 at 18:11

marinus

31.2k7 gold badges71 silver badges112 bronze badges

1

\$\begingroup\$ I just noticed this answer as I put my J answer. they're basically the same haha \$\endgroup\$
– Conor O'Brien
Commented Nov 8, 2016 at 18:22
2

\$\begingroup\$ This outputs something else in addition to the ascii wall. Is this allowed? \$\endgroup\$
– Buffer Over Read
Commented Nov 9, 2016 at 16:11
\$\begingroup\$ when using tryapl.org, I got the wall output. what have you received @TheBitByte? \$\endgroup\$
– Dylan
Commented Nov 10, 2016 at 14:34
5

\$\begingroup\$ @Dylan He's probably confused, since the answerer included the program in the output without knowing the REPL nature of APL. \$\endgroup\$
– Conor O'Brien
Commented Nov 10, 2016 at 19:49

Add a comment |

Conor O'Brien · Accepted Answer · 2016-11-08 18:22:04Z

21

J, 12 bytes

10 70$'_|__'

Shapes the string on the right into a 10 by 70 shape. Simple!

answered Nov 8, 2016 at 18:22

Conor O'Brien

40.2k3 gold badges91 silver badges180 bronze badges

Add a comment |

Level River St · Accepted Answer · 2016-11-12 23:41:56Z

18

BBC BASIC, 28 bytes

Tokenised filesize 23 bytes.

WIDTH70P.STRING$(175,"_|__")

WIDTH70 would normally be followed by a newline. It sets the field width to 70. Then we just print 175 copies of the string, which wrap around.

edited Nov 12, 2016 at 23:41

user344

answered Nov 8, 2016 at 18:17

Level River St

26.7k4 gold badges37 silver badges105 bronze badges

2

\$\begingroup\$ Best (ab)use of WIDTH that I have seen :) \$\endgroup\$
– ElPedro
Commented Nov 8, 2016 at 18:46
\$\begingroup\$ This should have "23 bytes" in the header then. \$\endgroup\$
– Adám
Commented Nov 8, 2016 at 20:33
\$\begingroup\$ @Adám Only if the tokenized version is posted as the answer. \$\endgroup\$
– ErikE
Commented Nov 14, 2016 at 7:38

Add a comment |

Mitchell Humphrey · Accepted Answer · 2016-11-13 02:38:44Z

Brainfuck, 171 bytes

+++++[>+++++++++++++++++++<-]+++++++[>>++++++++++++++++++<<-]>>--<<++[>>>+++++<<<-]+++++[>.>.>>+++++++++++++++++[<<<...>.>>-]<.>+++++++++++++++++[<<<...>.>>-]<<<..>>.<<<-]

Brainfuck is fun, here is my submission.

Here is the output:

_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__

Here is a link to try it

https://repl.it/EW2Z/0

Community · Accepted Answer · 2020-06-17 09:04:33Z

WinDbg, 45 bytes

f2000000 L2bc 5f 7c 5f 5f;da/c46 2000000 L2bc

How it works:

f 2000000 L2bc 5f 7c 5f 5f; *Repeat the pattern _|__ (5F 7C 5F 5F) to fill 2BC (700) bytes 
                            *starting at 2000000
da /c46 2000000 L2bc        *Show 2BC (700) ASCII chars starting from 2000000 in lines 
                            *of length 0x46 (70)

Output:

0:000> f2000000 L2bc 5f 7c 5f 5f;da/c46 2000000 L2bc
Filled 0x2bc bytes
02000000  "_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|"
02000046  "___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__"
0200008c  "_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|"
020000d2  "___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__"
02000118  "_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|"
0200015e  "___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__"
020001a4  "_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|"
020001ea  "___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__"
02000230  "_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|"
02000276  "___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__"

Community · Accepted Answer · 2020-06-17 09:04:33Z

10

Pyth, 12 bytes

Code:

jcT*175"_|__

Explanation:

       "_|__    # For the string "_|__"
   *175         # Repeat it 175 times
 cT             # Chop into 10 equal pieces
j               # Join them by newlines

Try it here.

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Nov 8, 2016 at 18:21

Adnan

44.5k6 gold badges82 silver badges246 bronze badges

Add a comment |

xnor · Accepted Answer · 2016-11-08 18:58:47Z

10

Python 2, 37 bytes

s="_|__"*17;print(s+"_|\n__%s\n"%s)*5

Decomposes two rows as 17 copies of _|__, plus another copy interrupted by a newline, plus 17 more copies, plus another newline.

Longer alternatives:

print"%s_|\n__%s\n"%(2*("_|__"*17,))*5

s="_|__"*17;print"%s_|\n__%%s\n"%s%s*5

for i in[0,2]*5:print("_|__"*18)[i:i+70]

print("_|__"*17+"_|\n"+"___|"*17+"__\n")*5

for s in["_|__","___|"]*5:print(s*18)[:70]

s="_|__"*99;exec"print s[:70];s=s[2:];"*10

print("%s"*70+"\n")*10%(175*tuple("_|__"))

edited Nov 8, 2016 at 18:58

answered Nov 8, 2016 at 18:28

xnor

147k26 gold badges279 silver badges652 bronze badges

\$\begingroup\$ Your last alternative is shorter as print(("%s"*70+"\n")*10%(175*(*"_|__",))) in Python 3. \$\endgroup\$
– mbomb007
Commented Nov 8, 2016 at 20:49

Add a comment |

Adnan · Accepted Answer · 2016-11-08 18:22:21Z

8

05AB1E, 13 bytes

Code:

"_|__"175×Tä»

Explanation:

"_|__"         # For the string "_|__"
      175×     # Repeat that 175 times
          Tä   # Split into 10 even pieces
            »  # And join them by newlines

Uses the CP-1252 encoding. Try it online!

edited Nov 8, 2016 at 18:22

answered Nov 8, 2016 at 18:15

Adnan

44.5k6 gold badges82 silver badges246 bronze badges

\$\begingroup\$ -2 by using …_|_Ć and the compressed Ƶм for 175 (I realize the second wasn't available when you posted the answer; not sure about the first). \$\endgroup\$
– Kevin Cruijssen
Commented Jun 30, 2020 at 15:12

Add a comment |

Community · Accepted Answer · 2017-04-13 12:39:05Z

7

PHP, 44 42 41 characters

<?=chunk_split(str_pad(_,700,"|___"),70);

(Just because had no chance to use chunk_split() ever before.)

Thanks to:

user59178 for suggesting to use str_pad() (-1 character)

Sample run:

bash-4.3$ php <<< '<?=chunk_split(str_pad(_,700,"|___"),70);'
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__

edited Apr 13, 2017 at 12:39

CommunityBot

1

answered Nov 8, 2016 at 18:12

manatwork

20.7k5 gold badges51 silver badges81 bronze badges

\$\begingroup\$ bytes, not character count. \$\endgroup\$
– Dylan
Commented Nov 8, 2016 at 19:40
2

\$\begingroup\$ Same. I use no multibyte characters. \$\endgroup\$
– manatwork
Commented Nov 8, 2016 at 19:41
9

\$\begingroup\$ Crossed out 44 is still regular 44 ;( \$\endgroup\$
– pajonk
Commented Nov 8, 2016 at 20:05
2

\$\begingroup\$ @pajonk, Fixed with PPCG - Crossed Out 44 user style on my machine: i.sstatic.net/czn5h.png \$\endgroup\$
– manatwork
Commented Nov 8, 2016 at 20:26
\$\begingroup\$ You can save a byte by using str_pad instead of str_repeat, largely because _ is treated as a constant with value _. \$\endgroup\$
– user59178
Commented Nov 9, 2016 at 9:21

Add a comment |

karpfen · Accepted Answer · 2016-11-23 17:14:09Z

7

Vim, 30 24 19 keystrokes

18a___|<esc>YP2x}h.yk4P

Thanks to DrMcMoylex and nmjcman101 for saving valuable keystrokes!

edited Nov 23, 2016 at 17:14

answered Nov 9, 2016 at 15:51

karpfen

1815 bronze badges

1

\$\begingroup\$ Nice answer, welcome to the site! Some tips: 1) a takes a count, so you could do 18a___|<esc> instead of making the macro. 2) <cr> in normal mode is equivalent to j0, so you could take one byte off your second macro. \$\endgroup\$
– DJMcMayhem
Commented Nov 9, 2016 at 16:07
\$\begingroup\$ Cool, thanks for the tips! \$\endgroup\$
– karpfen
Commented Nov 9, 2016 at 16:15
1

\$\begingroup\$ I golfed your solution a bit for fun. Formatting the wall before copy/pasting saves all the bytes of not making a macro: 18a___|<esc>YP2x}h.yk5P is 19 bytes. \$\endgroup\$
– nmjcman101
Commented Nov 23, 2016 at 16:44
\$\begingroup\$ Nice, I'll update the answer! I'll just replace the second to last key with 4, otherwise the wall is getting too high :) \$\endgroup\$
– karpfen
Commented Nov 23, 2016 at 17:12

Add a comment |

Community · Accepted Answer · 2020-06-17 09:04:33Z

6

Perl, 47 34 29 bytes

$_="_|__"x175;say for/.{70}/g

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Nov 8, 2016 at 18:10

Gabriel Benamy

2,91712 silver badges16 bronze badges

\$\begingroup\$ You can golf it down to 29 : say for("_|__"x175)=~/.{70}/g \$\endgroup\$
– Dada
Commented Nov 8, 2016 at 18:22
\$\begingroup\$ For some reason, that used to produce no output every time I tried it, but I found another solution in as many bytes. Thank you though! \$\endgroup\$
– Gabriel Benamy
Commented Nov 8, 2016 at 18:39
\$\begingroup\$ Well, the code I suggested does produce a valid output... Maybe you forgot the parenthesis around "_|__"x175 or something like that? \$\endgroup\$
– Dada
Commented Nov 8, 2016 at 18:47
\$\begingroup\$ I think that's what it is. I figured parentheses had to go somewhere, I just couldn't figure out where, lol \$\endgroup\$
– Gabriel Benamy
Commented Nov 8, 2016 at 18:48
\$\begingroup\$ Huhu, hard to remember the precedence of every operator (=~ has a higher precedence than x)! \$\endgroup\$
– Dada
Commented Nov 8, 2016 at 18:50

| Show 1 more comment

Community · Accepted Answer · 2020-06-17 09:04:33Z

5

Perl, 31 bytes

say+($@="_|__"x17,"_|
__$@
")x5

You'll need -E flag to run it :

perl -E 'say+($@="_|__"x17,"_|
__$@
")x5'

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Nov 8, 2016 at 18:17

Dada

8,5131 gold badge17 silver badges43 bronze badges

\$\begingroup\$ Thought of a slightly different approach for 29 bytes: say for("_|__"x175)=~/.{70}/g :). I do like the trick you employed there though! \$\endgroup\$
– Dom Hastings
Commented Nov 9, 2016 at 12:23
\$\begingroup\$ @DomHastings huhu, I wrote the exact same code in the comments of Gabriel Benamy's answer! \$\endgroup\$
– Dada
Commented Nov 9, 2016 at 15:11
\$\begingroup\$ D'oh! Didn't see that one! Also then saw it's been used a lot in other answers.. Oh well! \$\endgroup\$
– Dom Hastings
Commented Nov 9, 2016 at 15:13
\$\begingroup\$ @DomHastings Yea, I didn't thought of it at first, and it was already in Gabriel's answer, so that's why I didn't update my answer after ;) \$\endgroup\$
– Dada
Commented Nov 9, 2016 at 15:22

Add a comment |

DJMcMayhem · Accepted Answer · 2016-11-08 20:43:48Z

5

V, 24, 16 bytes

175i_|__ò70|lé

Try it online! This contains <esc> characters (0x1B) so here is a hexdump:

0000000: 3137 3569 5f7c 5f5f 1bf2 3730 7c6c e90a  175i_|__..70|l..

8 bytes indirectly saved thanks to Jordan!

edited Nov 8, 2016 at 20:43

answered Nov 8, 2016 at 18:12

DJMcMayhem

59.6k17 gold badges196 silver badges348 bronze badges

\$\begingroup\$ 19 bytes: v.tryitonline.net/… I couldn't figure out how to use the .\{-} shortcut mentioned in the V docs, though. \$\endgroup\$
– Jordan
Commented Nov 8, 2016 at 19:52
\$\begingroup\$ @Jordan Wow, very nice! The \{-} shortcut wouldn't work anyway, since you can't change the number inside. However, you could set the high bit on the \{ to get this instead. Feel free to post that as an answer. \$\endgroup\$
– DJMcMayhem
Commented Nov 8, 2016 at 20:31
\$\begingroup\$ Ah, that makes sense. Posted here: codegolf.stackexchange.com/a/99070/11261 \$\endgroup\$
– Jordan
Commented Nov 8, 2016 at 20:35
\$\begingroup\$ Damn I still need to grok this language: 25 bytes \$\endgroup\$
– statox
Commented Nov 9, 2016 at 13:12

Add a comment |

Jordan · Accepted Answer · 2016-11-08 22:48:59Z

5

V, 18 bytes

-1 byte thanks to DJMcMayhem.

175i_|__<Esc>Ó.û70}/°ò

Here it is with unprintable characters in xxd format:

0000000: 3137 3569 5f7c 5f5f 1bd3 2efb 3730 7d2f  175i_|__....70}/
0000010: b0f2                                     ..

Try it online!

edited Nov 8, 2016 at 22:48

answered Nov 8, 2016 at 20:35

Jordan

11.3k1 gold badge33 silver badges55 bronze badges

\$\begingroup\$ Nice, I am no longer the only person who has used V! Now I'm going to have to see if I can take the lead back, haha \$\endgroup\$
– DJMcMayhem
Commented Nov 8, 2016 at 20:39

Add a comment |

Community · Accepted Answer · 2020-06-17 09:04:33Z

5

MATL, 15 bytes

'_|__'700:)70e!

Of course, you can Try it online! Explanation:

'_|__' % Put a brick on the stack
700    % 700 times
:)     % Makes a happy mason...
70e!   % Secret freemason code

OK, actually, it works as follows:

'_|__' % Put the first bit of the string on the stack
700:   % Put 1, 2, ..., 700 on the stack as array
)      % Index into the string, modularly. Result: '_|___|__ ... __'
70e    % Reshape into 70 rows (and consequently, 10 columns)
!      % Transpose to get the desired output.

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Nov 8, 2016 at 20:45

Sanchises

9,5261 gold badge36 silver badges61 bronze badges

\$\begingroup\$ Well done! And your smiley is better than mine \$\endgroup\$
– Luis Mendo
Commented Nov 8, 2016 at 21:18
\$\begingroup\$ @LuisMendo Really, using smileys could be considered a design pattern in MATL. xD Perhaps you could have :) on C... but that would be your last 1-byte code point gone (or is there another reason C is not used?) \$\endgroup\$
– Sanchises
Commented Nov 8, 2016 at 21:39
\$\begingroup\$ You want to get rid of the smiley?? :-P \$\endgroup\$
– Luis Mendo
Commented Nov 8, 2016 at 22:30

Add a comment |

Kade · Accepted Answer · 2016-11-16 13:43:49Z

5

Python 2, 46 44 Bytes

Just using string multiplication to build the string, and slicing to get the right bits :)

k='_|__'*18
print'\n'.join([k[:70],k[2:]]*5)

^{thanks to Antony Hatchkins for saving two bytes :)}

edited Nov 16, 2016 at 13:43

answered Nov 8, 2016 at 18:26

Kade

7,87324 silver badges53 bronze badges

\$\begingroup\$ Could be 2 bytes less: print'\n'.join([k[:70],k[2:]]*5) \$\endgroup\$
– Antony Hatchkins
Commented Nov 14, 2016 at 7:24
\$\begingroup\$ @AntonyHatchkins Thanks! \$\endgroup\$
– Kade
Commented Nov 16, 2016 at 13:43

Add a comment |

Community · Accepted Answer · 2020-06-17 09:04:33Z

4

Jelly, 14 bytes

“_|__”ṁ700s70Y

TryItOnline!

How?

“_|__”ṁ700s70Y - Main link: no arguments
“_|__”         - literal ['_','|','_','_']
      ṁ700     - mould like something 700 long
          s70  - split into chunks of length 70
             Y - join with line feeds

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Nov 8, 2016 at 18:14

Jonathan Allan

110k7 gold badges65 silver badges282 bronze badges

1

\$\begingroup\$ By definition, Jelly cannot be longer than J. \$\endgroup\$
– Adám
Commented Nov 8, 2016 at 20:34
\$\begingroup\$ I did something similar without the peculiar ṁ: “_|__”ẋ175œs⁵Y (14 bytes) \$\endgroup\$
– Erik the Outgolfer
Commented Nov 13, 2016 at 11:34

Add a comment |

AdmBorkBork · Accepted Answer · 2016-11-08 21:26:12Z

4

PowerShell v2+, 34 30 bytes

'_|__'*175-split"(.{70})"-ne''

Stupid regex matching algorithm requiring the -ne'' ... wastes five bytes!

'_|__'*175-split"(.{70})"-ne''
'_|__'*175                     # Repeat this string 175 times
          -split"       "      # Split on this regex pattern:
                  .{70}        # Match any character 70 times
                 (     )       # Encapsulated in parens so we keep the regex results
                         -ne'' # But don't select the empty strings
                               # Output with newlines via Write-Output is implicit

Saved 4 bytes thanks to Conor!

edited Nov 8, 2016 at 21:26

answered Nov 8, 2016 at 18:59

AdmBorkBork

43.5k5 gold badges103 silver badges284 bronze badges

\$\begingroup\$ Would .{70} be any shorter for teh regex? \$\endgroup\$
– Conor O'Brien
Commented Nov 8, 2016 at 21:00
\$\begingroup\$ split works like that in other languages - you always get the unmatched portions whether you want them or not. Some languages have a match operator that can be used to return an array of only matching results, but I don't see a PowerShell equivalent for that. \$\endgroup\$
– Neil
Commented Nov 9, 2016 at 10:23
\$\begingroup\$ @Neil Performing 'abc'-split'(.)' will return ('','a','','b','','c',''). There's nothing unmatched, but due to how the algorithm processes through the input string, you get empty strings back. See here. \$\endgroup\$
– AdmBorkBork
Commented Nov 9, 2016 at 13:33
\$\begingroup\$ Yes, and I'm saying you shouldn't be surprised by that result, because that's what split's supposed to do. \$\endgroup\$
– Neil
Commented Nov 9, 2016 at 14:01
\$\begingroup\$ @Neil Surprised? No, not really. Doesn't mean I have to be happy about it, though. :D \$\endgroup\$
– AdmBorkBork
Commented Nov 9, 2016 at 14:08

Add a comment |

Community · Accepted Answer · 2020-06-17 09:04:33Z

C, 131 115 113 103 97 95 Bytes

i,j;main(){for(;i<10;puts(i++&1?"|__":"|"))for(j=0;j<18-(i&1);printf(&"|___"[j++?0:i&1?1:3]));}

Time to start golfing this...

_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__

\$\begingroup\$ 81 bytes \$\endgroup\$
– ceilingcat
Commented Aug 4, 2020 at 21:29 — ceilingcat, Commented Aug 4, 2020 at 21:29

Luis Mendo · Accepted Answer · 2016-11-08 18:46:39Z

3

MATL, 16 bytes

'___|'10:E!70:+)

Try it online!

'___|'   % Push this string
10:E!    % Push [2; 4; 6; ...; 20] (10×1 column vector)
70:      % Push [1, 2, 3, ..., 70] (1×70 row vector)
+        % Add. Gives a 10×70 matrix of all pairwise additions
)        % Index (modular, 1-based) into the string

edited Nov 8, 2016 at 18:46

answered Nov 8, 2016 at 18:41

Luis Mendo

105k9 gold badges135 silver badges372 bronze badges

\$\begingroup\$ Beat you with an entire byte: codegolf.stackexchange.com/a/99073/32352 \$\endgroup\$
– Sanchises
Commented Nov 8, 2016 at 20:46

Add a comment |

Community · Accepted Answer · 2017-04-13 12:39:03Z

3

CJam, 15 bytes

"_|__"175*70/N*

Try it online!

Port of Adnan's 05AB1E answer.

"_|__"             e# Push this string
      175*         e# Repeat 175 times
          70/      e# Split in pieces of size 70
             N*    e# Join by newlines

edited Apr 13, 2017 at 12:39

CommunityBot

1

answered Nov 8, 2016 at 18:44

Luis Mendo

105k9 gold badges135 silver badges372 bronze badges

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Juan · Accepted Answer · 2016-11-08 20:01:50Z

3

Javascript REPL, 45 bytes

"_|__".repeat(175).match(/.{70}/g).join("\n")

edited Nov 8, 2016 at 20:01

answered Nov 8, 2016 at 19:36

Juan

4592 silver badges7 bronze badges

1

\$\begingroup\$ Welcome to PPCG! This should be marked as "JavaScript REPL" or similar, as this doesn't print anything at all outside of an interactive console environment. \$\endgroup\$
– Martin Ender
Commented Nov 8, 2016 at 19:41
1

\$\begingroup\$ Isn't this 45 bytes? \$\endgroup\$
– acrolith
Commented Nov 8, 2016 at 19:50
\$\begingroup\$ @daHugLenny you are right, I counted \n as a single byte \$\endgroup\$
– Juan
Commented Nov 8, 2016 at 20:02
\$\begingroup\$ where is the console.log ? \$\endgroup\$
– cardeol
Commented Nov 9, 2016 at 12:49
1

\$\begingroup\$ As long as you are using ES6 (I think it is) you can use template strings, so join("\n") becomes join<backtick><literal newline><backtick> \$\endgroup\$
– Stephen
Commented Jul 24, 2017 at 17:17

Add a comment |

ETHproductions · Accepted Answer · 2016-11-08 23:11:30Z

3

JavaScript (ES6), 48 bytes

f=(n=350)=>n?(n%35?'_':`
_`)+"|_"[n%2]+f(n-1):""

Because recursion.

edited Nov 8, 2016 at 23:11

answered Nov 8, 2016 at 23:03

ETHproductions

50.1k6 gold badges94 silver badges240 bronze badges

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rjmunro · Accepted Answer · 2016-11-09 11:08:46Z

3

Bash, 44, 41, 40 bytes

printf _\|__%.0s {1..175}|egrep -o .{70}

The printf makes a single line 700 characters long, the egrep matches it 70 characters at a time.

edited Nov 9, 2016 at 11:08

answered Nov 9, 2016 at 11:02

rjmunro

1914 bronze badges

Add a comment |

nph · Accepted Answer · 2021-05-15 23:50:00Z

3

///, 43 bytes

/a/___|//b/aaccccc//c/aaa//d/_|b
b__
/ddddd

Try it online!

answered May 15, 2021 at 23:50

nph

7535 silver badges14 bronze badges

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Community · Accepted Answer · 2020-06-17 09:04:33Z

2

Befunge-98, 63 bytes

'_\:3+4%0`!> #0 #\ #|' $ #\_\,1+:7a*%0`!> #0 #, #a_:7aa**\`!#@_

TryItOnline!

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Nov 8, 2016 at 18:28

Brian Gradin

5695 silver badges9 bronze badges

Add a comment |

Community · Accepted Answer · 2020-06-17 09:04:33Z

2

///, 51 bytes

If a trailing newline is allowed:

/e/aaaa//a/_|__//b/eeeea_|//c/__eeeea//d/b
c
/ddddd

Try it online!

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Nov 8, 2016 at 19:47

acrolith

3,9681 gold badge24 silver badges41 bronze badges

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Community · Accepted Answer · 2020-06-17 09:04:33Z

2

Pyke, 12 bytes

w�"_|__"*TfX

where � is the literal byte 163.

Try it here! (w� replaced with literal)

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Nov 8, 2016 at 20:42

Blue

28.6k8 gold badges52 silver badges100 bronze badges

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Level River St · Accepted Answer · 2016-11-08 22:25:53Z

2

Ruby, 30 bytes

Thanks to manatwork for this solution

puts ("_|__"*175).scan /.{70}/

Ruby, 39 bytes

10.times{|i|puts ("_|__"*18)[i%2*2,70]}

edited Nov 8, 2016 at 22:25

answered Nov 8, 2016 at 18:37

Level River St

26.7k4 gold badges37 silver badges105 bronze badges

2

\$\begingroup\$ The generate-all-then-split approach is shorter here too: puts ("_|__"*175).scan /.{70}/. \$\endgroup\$
– manatwork
Commented Nov 8, 2016 at 19:15
\$\begingroup\$ @manatwork thanks a lot! I rarely think of using scan as I´m not that comfortable with regexes. You know you could have posted that as your own answer... \$\endgroup\$
– Level River St
Commented Nov 8, 2016 at 22:27

Add a comment |

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91 Answers 91

Trumpscript, 303 285 244 231 226 bytes

APL, 12 bytes

J, 12 bytes

BBC BASIC, 28 bytes

Brainfuck, 171 bytes

WinDbg, 45 bytes

Pyth, 12 bytes

Python 2, 37 bytes

05AB1E, 13 bytes

PHP, 44 42 41 characters

Vim, 30 24 19 keystrokes

Perl, 47 34 29 bytes

Perl, 31 bytes

V, 24, 16 bytes

V, 18 bytes

MATL, 15 bytes

Python 2, 46 44 Bytes

Jelly, 14 bytes

How?

PowerShell v2+, 34 30 bytes

C, 131 115 113 103 97 95 Bytes

MATL, 16 bytes

CJam, 15 bytes

JavaScript (ES6), 48 bytes

Bash, 44, 41, 40 bytes

///, 43 bytes

Befunge-98, 63 bytes

///, 51 bytes

Pyke, 12 bytes

Ruby, 30 bytes

Ruby, 39 bytes

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Build me a brick wall!

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Winner

91 Answers 91

Trumpscript, 303 285 244 231 226 bytes

APL, 12 bytes

J, 12 bytes

BBC BASIC, 28 bytes

Brainfuck, 171 bytes

WinDbg, 45 bytes

Pyth, 12 bytes

Python 2, 37 bytes

05AB1E, 13 bytes

PHP, 44 42 41 characters

Vim, 30 24 19 keystrokes

Perl, 47 34 29 bytes

Perl, 31 bytes

V, 24, 16 bytes

V, 18 bytes

MATL, 15 bytes

Python 2, 46 44 Bytes

Jelly, 14 bytes

How?

PowerShell v2+, 34 30 bytes

C, 131 115 113 103 97 95 Bytes

MATL, 16 bytes

CJam, 15 bytes

JavaScript (ES6), 48 bytes

Bash, 44, 41, 40 bytes

///, 43 bytes

Befunge-98, 63 bytes

///, 51 bytes

Pyke, 12 bytes

Ruby, 30 bytes

Ruby, 39 bytes

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