Build me a brick wall!

Question

Challenge

I need help building a brick wall! Throw together some code for me using no input and produce the following output wall shown below:

_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__

Now, this wall is exactly 10 characters high and 70 characters wide.

As stated above, no inputs, only code. Least amount of bytes, we have to efficiently build this brick wall. Obviously, this program has to function to get the wall built..? or it obviously won't build itself! Good luck!

---

Winner

The winner goes to Marinus using the APL language, requiring a whole 12 bytes! https://codegolf.stackexchange.com/a/99028/61857

---

Thank you everyone for participating!

Answer 1

Haskell, 56 47 bytes

unlines$[1..5]>>take 70.cycle<$>["_|__","___|"]

Answer 2

R, 78 bytes

    strwrap(gsub('(.{70})','\\1 ',paste(rep('___|',175),collapse='')),70)

How?

    x=paste(rep('___|',175),collapse='')   #Creates string on 1 line
    y=gsub('(.{70})','\\1 ',x)             #Adds spaces every 70 characters
    z=strwrap(y,70)                        #Creates a new line every space
    z                                      #Print the finished product

Answer 3

C, 61 bytes

TCC Version

main(i){for(;i+699;)printf("\n%c"+(--i%70||!i),"___|"[i&3]);}

GCC Version

main(i){for(;i+699;)printf("\n%c"+(i%70||!i),"___|"[--i&3]);}

Answer 4

Befunge-93, 42 bytes

:4%1g,1+:"F"%!#v_0#@_
_|__~>:+#5,#:4#<1g*`^

Try it online!

Answer 5

bash 36 Byte

printf '_|__%.0s' {1..175}|fold -w70

OUtput:

_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__

Answer 6

Retina, 23 21 20 bytes

175$*_

_|_
!`.{70}

Try it online

Answer 7

Python 3, 40 bytes

p="_|__"*17
print((p+"_|\n__"+p+"\n")*5)

Answer 8

JavaScript (Node.js), 45 bytes

_=>`_|__`.repeat(175).match(/.{70}/g).join`
`

Try it online!

Explanation :

_ =>                    // lambda function (argument passed to save a byte)
    `_|__`              // simple enough
    .repeat(175)        // repeat the above mentioned shape 175 times
    .match(/.{70}/g)    // simple regexp to match a shape 70 (something :) ) long 
    .join`\n`           // and join them on a new line

---

Simple enough.

Alternate version :

JavaScript (Node.js), 714 bytes

_=>`_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__`

Try it online!

No explanation required. Simple hard coded.

Answer 9

Jelly, 13 bytes

70:þ⁵“_|__”ṁY

Try it online!

The dyad given to þ doesn't matter so long as it outputs a scalar, so I chose : solely for aesthetic purposes.

   þ             Take the rangifying outer product
  :              by integer division
70               of 70
    ⁵            and 10,
     “_|__”ṁ     mold "_|__" like it,
            Y    and join on newlines.

Answer 10

05AB1E, 11 bytes

…_|_ĆƵм×Tä»

Try it online!

         ä   # split...
…            # three char string...
 _|_         # literal...
    Ć        # concatenated with its first character...
       ×     # repeated...
      м      # numeric literal...
     Ƶ       # converted from base 255 to decimal plus 101...
       ×     # times...
         ä   # into...
        T    # 10...
         ä   # equal pieces...
          »  # by newlines
             # implicit output

Answer 11

Python 2, 50 48 bytes

for b in range(10):print('_|__'*175)[b*70:][:70]

2 saved with thanks to @xnor but also thanks to @Shebang for the suggestion :)

Answer 12

Jolf, 17 bytes

RZc*"_|__"Τ755@FS

Try it here!

Explanation

RZc*"_|__"Τ755@FS
   *"_|__"         repeat this string:
          Τ755      7*5*5 = 175 times
 Zc           @F   chop into groups of 70 (F's charcode)
R               S  join by newlines

Answer 13

SOML, 16 bytes

_|__”’ø*L{:jjp»»

explanation:

_|__”             push "_|__"
     ’ø           push 18
       *          repeat the "_|__" 18 times
        L{        repeat 10 times:
          :       duplicate the sting
           jj     pop the last 2 letters off
             p    output it
              »»  put the last 2 characters at the start

Answer 14

GolfSharp, 38 bytes

c(r(175).s(n=>"_|__").j().S(70).j(N));

Answer 15

Pyth, 24 23 22 bytes

VT:*175"_|__"J*70N+70J

OK, I'm still learning. Any hints gratefully received :)

Edit

Saved a byte by moving the assignment of J to first use

Answer 16

Racket 159 bytes

(let p((n 2)(x 0)(t 0)(d display))(when(> x 69)(d"\n")(set! x 0))(cond[(> t 699)
(d"\n")][(> n 2)(d"|")(p 0(+ 1 x)(+ 1 t)d)][(d"_")(p(+ 1 n)(+ 1 x)(+ 1 t)d)]))

Ungolfed:

(define (f)
  (let loop ((n 2)   (x 0)   (t 0)  (d display))

    (when (> x 69)  (d "\n")
                    (set! x 0))
    (cond
      [(> t 699)    (d "\n")]

      [(> n 2)      (d "|")
                    (loop    0    (+ 1 x) (+ 1 t) d)]

      [else         (d "_")
                    (loop (+ 1 n) (+ 1 x) (+ 1 t) d)]
      )))

Testing:

(f)

Output:

_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__

Answer 17

Ruby, 89 80 77 76 72 53 47 42 Bytes

puts (%w[___]*176*?|)[2..-1].scan(/.{70}/)

Demo:

>> puts (%w[___]*176*?|)[2..-1].scan(/.{70}/)
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__

Update: I didn’t see there’s already an answer with 30 bytes.

Answer 18

PHP, 46 bytes

<?=wordwrap(str_repeat('_|__',175),70,"\n",1);

Output:

C:\PHP>php build-me-a-brick-wall.php
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__

Answer 19

Java 8, 128

This code directly calculates each character and has no imports or dependencies.

Golfed:

()->{String s="";for(int x,y=0;y<10;++y){for(x=0;x<70;++x)s+=((y%2<1&(x+3)%4<1)|(y%2>0&(x+1)%4<1))?"|":"_";s+="\n";}return s;}

Ungolfed:

() -> {
  String s = "";
  for (int x, y = 0; y < 10; ++y) {
    for (x = 0; x < 70; ++x)
      s += ((y % 2 < 1 & (x + 3) % 4 < 1) | (y % 2 > 0 & (x + 1) % 4 < 1)) ? "|" : "_";
    s += "\n";
  }
  return s;
}

Answer 20

Swift 3, 69 bytes

(3...702).map{print($0%4<1 ?"|":"_",terminator:($0-2)%70<1 ?"\n":"")}

Output after compiling and running:

_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__

Try online here (In this tool it run as script so it will produce a warning due the map result is unused.

Answer 21

Clojure, 117 110 bytes

(fn[](println(apply str(map #(str(apply str %)"\n")(partition 70(subs(apply str(repeat 175 "_|__"))0 700))))))

Basically creates a long string of "_|__"s 700 characters long, cuts it every 70 characters, then joins them with newline.

Managed to get rid of the calls to join!

Ungolfed:

(defn build-wall []
  (println
    (apply str
      (map #(str (apply str %) "\n")
        (partition 70
          (subs (apply str
                  (repeat 175 "_|__"))
                0 700))))))

Answer 22

C#, 106 102 101 118 107 106 100 96 bytes

Thanks shebang for saving 2 bytes and pointing out a mistake, Yodle for saving 6 bytes and Link Ng for saving 4 bytes.

var a="";int i;for(;i++<175;)a+="_|__";for(i=0;i<10;)Console.Write(a.Substring(i++*10,70)+"\n");

You can test it directly on http://csharppad.com/.

Answer 23

Java 8 + Guava, 81 106 bytes

25 bytes for import: com.google.common.base.*;

Lambda that takes no input and returns the required wall.

()->String.join("\n",Splitter.fixedLength(70).split(Strings.repeat("_|__",175)));

Same as many other solutions. Takes a repeating string of "_|__" 175 times, splits it into lengths of 70, then joins them on newline.

Answer 24

SAS, 68

option linesize=70;data;length w$700;w=repeat('_|__',174);put w;run;

The 174 is not a typo - in SAS the repeat function rather pedantically returns the original string plus n repeats.

Answer 25

Python 3, 43

print(("_|__"*17+"_|\n"+"__|_"*17+"_\n")*5)

Fixed to be more Trump-like.

Answer 26

Kotlin, 99 bytes

fun main(a:Array<String>){"_|__".repeat(999).split(Regex("(?<=\\G.{70})")).take(10).map(::println)}

Regex taken from here. First ever golf, done in 10 minutes, probably improvable..

Answer 27

Lua, 54 bytes

w=("_|__"):rep(17)print((w.."_|\n__"..w.."\n"):rep(5))

No fancy splits for Lua, but it does have an easy repeat.

Answer 28

Python 2, 46 bytes

import textwrap as t;print t.fill('_|__'*175)

I was going to do an exec loop similar to @xnor's one alternate solution but he/she got to it before me. I guess I'll just have to let Python do the dirty work for me.

Answer 29

R, 62 bytes

Don't have the rep to comment, so posting as an answer: @user3297046's answer can be golfed-down to 62 bytes:

cat(gsub('(.{70})','\\1
',paste(rep('_|__',175),collapse='')))

which results in

_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__
_|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|
___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|___|__

Answer 30

PHP, 56 bytes

Although I know it can be done smaller using wordwrap or string splits, I prefer more hacky solutions.

for($i=0;$i<700;$i++){echo($i%70?'':'
').'_|___'[$i%4];}