Full Width Text

Question

Full width text is text that has a space after every character, including the last one. For instance, the first sentence of this question becomes:

F u l l   w i d t h   t e x t   i s   t e x t   t h a t   h a s   a   s p a c e   a f t e r   e v e r y   c h a r a c t e r ,   i n c l u d i n g   t h e   l a s t   o n e . 

Write a program that takes a line in text from standard input and outputs it as full-width text to standard out.

Leaderboard

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body{text-align:left!important}#answer-list,#language-list{padding:10px;width:290px;float:left}table thead{font-weight:700}table td{padding:5px}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <link rel="stylesheet" type="text/css" href="//cdn.sstatic.net/codegolf/all.css?v=83c949450c8b"> <div id="answer-list"> <h2>Leaderboard</h2> <table class="answer-list"> <thead> <tr><td></td><td>Author</td><td>Language</td><td>Size</td></tr></thead> <tbody id="answers"> </tbody> </table> </div><div id="language-list"> <h2>Winners by Language</h2> <table class="language-list"> <thead> <tr><td>Language</td><td>User</td><td>Score</td></tr></thead> <tbody id="languages"> </tbody> </table> </div><table style="display: none"> <tbody id="answer-template"> <tr><td>{{PLACE}}</td><td>{{NAME}}</td><td>{{LANGUAGE}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table> <table style="display: none"> <tbody id="language-template"> <tr><td>{{LANGUAGE}}</td><td>{{NAME}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table>

Answer 1

Jelly, 5 3 2 bytes

Thanks to Dennis for saving 2 bytes. Also thanks to FryAmTheEggman for saving 1 byte. Code:

p⁶

Explanation:

p⁶   # Cartesian product with the input and the space character.

Uses the Jelly encoding.

Try it online!

Answer 2

Python 3.5, 18 bytes

print(*input(),'')

This works because print's default separator is single space.

Answer 3

Hexagony, 21 13 12 10 bytes

Code:

Saved a lot of bytes thanks to FryAmTheEggman. Code:

P,<0/*;@.>

Or in a more readable form:

  P , <
 0 / * ;
@ . > . .
 . . . .
  . . .

Try it online!

Explanation:

The Hexagony program starts at the top-left corner, immediately setting the memory edge to the ASCII value of P, which is 80. After that, we can see that the following path is taken:

We can see that the path taken is: P,<;.P/0....;*/>. After the P, we take a byte of user input. If this is empty, the following branch (<) would direct us to the North East. If the input is non-empty, the branch directs us to the South East. After that, we output the user input using ;. We set the memory edge back to P, which is 80. The zero followed by the mirror is then concatenated to our number, resulting into 800. This is then outputted using the ; command, but first it is taken modulo 256, resulting into 32, which is the space character. After that, we reset the memory edge using the * command and return to loop over the rest of the user input. When we're done with the user input, the path is directed to the North East:

This basically goes to the @ command, which terminates the program.

Using Timwi's amazing HexagonyColorer for making the diagrams.

Answer 4

Haskell, 11 bytes

((:" ")=<<)

Usage example: ((:" ")=<<) "Code Golf" -> "C o d e G o l f ".

Map each character c to a two element list [c, space] and concatenate everything into a single list.

Answer 5

Retina, 5

.
$& 

Note the space at the end of the second line.

$& is equivalent to $0. Thanks to @mbomb007 for this link.

Try it online.

Answer 6

Awk, 7 bytes

(4 characters code + 3 characters command line option.)

NF++

Sample run:

bash-4.3$ awk -F '' 'NF++' <<< 'Full width text.'
F u l l   w i d t h   t e x t . 

(There is some disagreement on what should be included in the command line option count. I included what is actually passed to the awk interpreter: “-”, “F” and a separator between “F” and the empty string parameter. See below what I mean.)

bash-4.3$ od -tax1 /proc/`pidof awk`/cmdline 
0000000   a   w   k nul   -   F nul nul   N   F   +   + nul
         61  77  6b  00  2d  46  00  00  4e  46  2b  2b  00
                         ╰────────╯

Answer 7

JavaScript, 20 Bytes

Simple, I just wish that Array.join added the space to the end so I could save 3 bytes.

s=>[...s,``].join` `

Answer 8

><>, 13 10 bytes

3 bytes saved thanks to @Sp3000

i:0(?;o 'o

Try it here. Click the link, then Submit, then type some input and press Give, and finally run the program with Start or Run without animation.

Explanation

i       read a character
:       duplicate
0(      is it less than 0?
?;      if so: end program. Else:
o       output read character
 '      push all chars until matching (same) quote. Top character is a space
o       output that character, which is a space. Go back to the beginning

Answer 9

Java, 132 (System.in) or 99 (Program argument) bytes

Can you feel the overhead tonight?

class F{public static void main(String[]a){System.out.print(new java.util.Scanner(System.in).nextLine().replaceAll("(.)", "$0 "));}}
class W{public static void main(String[]a){for(char c:a[0].toCharArray())System.out.print(c+" ");}}

shooqie figured out a 6 byte shorter way to do this but I won't steal their approach. I've used it with the STDIN and lambda versions, however.

28 characters for a lambda but that doesn't meet the program requirement.

s->s.replaceAll("(.)","$0 ")

Answer 10

Java, 92

class T{public static void main(String[]A){System.out.print(A[0].replaceAll("(.)","$0 "));}}

Answer 11

Cubix, 10 bytes

Cubix is a 2 dimensional language developed by @ETHproductions where the commands are wrapped onto a cube. Try it online

@.?wi^\oSo

This maps onto a cube with edge length 2

    @ .
    ? w
i ^ \ o S o . .
. . . . . . . .
    . .
    . .

Starts with a input i. The flow is redirected north ^ to the top face. ? If the value is negative turn left to finish @, zero carries on into shift right w or positive turn right then reflect left \. Output character with a trailing space oSo.

Answer 12

Cubix, 9 bytes

@./.i?>So

See it work online!

Cubix is a language in which the instructions are mapped out onto the face of a cube. This program forms the following cube net:

    @ .
    / . 
i ? > S o . . .
. . . . . . . .
    . .
    . .

The instruction pointer begins at i, which takes another character-code from input and pushes it to the stack. If there is no more input left to be taken, the ? turns the IP left, where it hits /, and is reflected upwards to @, which terminates the program.

However, if there is input left, the value will be a character code. As all¹ character codes are positive, the ? makes the IP turn right, where it wraps all the way around the cube, passing o on the way which outputs the char. It then hits / which makes it loop back around to >So, which pushes and prints a space. The IP carries on west until wrapping around back to the i, back to the start of the main loop.

¹ If the character is a null byte, it will ignore the ? and carry on straight ahead, simply outputting a single space.

---

Of course, there's only so much a written explanation can do, so I highly recommend you view this in the online interpreter. There's a "speed" option, which allows you to view the execution as slow or fast as you like.

Answer 13

Stax, 2 bytes

Ties Jelly!

0\

Try it at staxlang.xyz!

All this does is push 0 to the stack and zip the string from standard input with it, repeating the 0 as necessary. In Stax, code point 0 in a string is usually converted to 32 (space).

This is short enough that packing it into ûT does nothing but reduce readability.

Answer 14

Seriously, 7 bytes

' ;,@j+

Try it online!

Man, that required ending space added 3 additional bytes. Without it, ,' j would work for 4.

Explanation:

' ;,@j+
' ;      push two copies of a single space
   ,@    push input, swap
     j+  join on spaces, append a space

Answer 15

05AB1E, 4 bytes

Sð«J

Try it online.

Explanation

Sð«J

S     split string into a list
 ð«   append a space to each element
   J  join

Answer 16

CJam, 5 4 bytes

1 byte fewer thanks to @FryAmTheEggman

lSf+

Try it online!

Explanation

l     e# read line
Sf+   e# map "concatenation" (+) with a space (S) as extra parameter
      e# implicitly display characters in the stack

Answer 17

GolfScript, 6 bytes

' ':n*

Try it online!

Answer 18

PHP, 39 bytes

echo join(' ',str_split($argv[1])).' ';

Run it from the command line

php fullwidth.php "Full width text is text that has a space after every character, including the last one."

https://eval.in/541179

Answer 19

Pyth, 5 4 bytes

Thanks to @FryAmTheEggman for saving a byte.

s*zd

Try it online here.

Answer 20

WhoScript 38 bytes

1v;pr;e;#0 1;-;i;t=;ti;o;tl;" ";d;>;pf

Works best when the string is given at the command line, but it can be done one character at a time in real time as well.

Ungolfed:

time_vortex
  psychic_paper read
  duplicate
  # 0 1
  -
  integer
  TARDIS =
  TARDIS if
      opening
  TARDIS landing
  # 20
paradox
pop
psychic_paper flush

Answer 21

Labyrinth, 10 bytes

<.23.%):,>

This terminates with an error, but the error messages goes to STDERR.

Try it online!

Explanation

This is one of the rare cases where a completely linear program is feasible. The loop is achieved via the source code modification commands < and >, which works because after each iteration we know that the stack is empty again.

< cyclically shifts the entire line one cell to the left, so we end up with:

.23.%):,><

This takes the instruction pointer (IP) with it so the IP is now at the right end of the code and has to move left. Next, the > does the opposite modification so it shifts the source code back to

<.23.%):,>

Now we execute a single iteration (from right to left), before everything starts over:

,    Read a character code from STDIN, or -1 at EOF.
:)   Duplicate and increment.
%    Modulo. At EOF this will attempt a division by zero and terminate. Otherwise, we
     have n % (n+1) = n, so we're left with the input character again.
.    Print it back to STDOUT.
32   Turn the top of the stack into a 32.
.    Print it as well (a space).

Answer 22

Gema, 5 bytes

?=?\ 

Sample run:

bash-4.3$ gema '?=?\ ' <<< 'Full width text.'
F u l l   w i d t h   t e x t . 

Answer 23

MATL, 7 bytes

tnZ"v1e

Try it online!

Explanation

t    % implicitly take input string and duplicate it
n    % number of elements
Z"   % string with that many spaces
v    % concatenate vertically (2xN array, where N is input length)
1e   % reshape into 1 row. Implicitly display

Answer 24

APL, 5 bytes

∊2∘↑¨

This takes 2 items for each character in the string, with the effect of adding a space

To make it a program that takes stdin, it's the same number of bytes:

∊2↑¨⎕

Try it here.

Answer 25

brainfuck, 24 22 bytes

Simple example using the shortest known 32 for the space character(s).

,[.>>-[-[-<]>>+<]>-.,]

Try it online

Answer 26

PHP, 31 bytes

<?=chunk_split($argv[1],1," ");

takes input from command line argument.

Answer 27

Threead, 45 16 Bytes non-competing.

  B[coB]
32c   o

Takes input via STDIN.

The first Line/Tape simply reads bytes from STDIN, and writes them. The second line, initially stores a space via 32c, then at the same time that the next character is being read, outputs that space.

Try it online!

Answer 28

Python 2, 27 25 24 bytes

lambda x:' '.join(x)+' '

Shorter than Raffi's answer...

-1 thanks to 60919 (FlipTack).

Answer 29

C, 50 bytes

Little bit of main() recursion :)

main(c){~(c=getchar())?printf("%c ",c),main():0;}

Try it online! - If using this on your own machine, use Ctrl+D to signify EOF.

Answer 30

C, 56 Bytes (as program argument), 46 Bytes (from stdin)

main(int a,char**b){while(*b[1])printf("%c ",*b[1]++);}

Plain old C answer. Once compiled, the program needs to be called with a string as it's first parameter, a string with spaces needs to be enclosed in quotes. For the example in the start post:

./prog "Full width text is text that has a space after every character, including the last one."

Which will output

F u l l   w i d t h   t e x t   i s   t e x t   t h a t   h a s   a   s p a c e   a f t e r   e v e r y   c h a r a c t e r ,   i n c l u d i n g   t h e   l a s t   o n e .

Solution that reads directly from stdin.

main(c){while(c=~getchar())printf("%c ",~c);}

One byte less thanks to @FryAmTheEggman