Shortest method to implement the Pythagorean Theorem

Question

Who doesn't love the Pythagorean theorem \$a^2+b^2=c^2\$? Write the shortest method you can in any language that takes in value a and b and prints out The hypotenuse of this right triangle is c. Keep c to only three decimal places.

Answer 1

JavaScript, 70 bytes

(a,b)=>'The hypotenuse of the triangle is '+((a*a+b*b)**.5).toFixed(3)

The latter function rounds the number to 3 decimal places.

Answer 2

Rust, 72 bytes

|a,b|print!("The hypotenuse of this right triangle is {:.3}",a.hypot(b))

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Woohoo, rust has built-ins for this. The hypot method calculates the hypotenuse between the numbers. Instead of the usual "{}" format substitution I used "{:.3}" which forces the number to display with three decimal places.

Answer 3

Vyxal, 32 30 bytes

∆/`λƛ h⁼Ǐ¢Ṗλ₇ of λ× ¬ẋ Ȧ⇩ is Π

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Answer 4

Fig, \$36\log_{256}(96)\approx\$ 29.632 bytes

+qDFQ$XS)s2lSXreS8x%twBEZ:x@KUX"mqS*

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Answer 5

ARBLE, 73 60 bytes

"The hypotenuse of this right triangle is %.3f"%(a^2+b^2)^.5

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Answer 6

Javascript, 109

A=1,B=1,s=1e3,console.log("The hypotenuse of this right triangle is " + (Math.round(Math.sqrt(A*A+B*B)*s)/s))

Fiddledee

Answer 7

Scala (95c)

import Math._;val x=sqrt(pow(a,2)+pow(b,2));f"The hypotenuse of this right triangle is $x%1.3g"

Answer 8

Java : 223

   class l {
        public static void main(String[] args) {      
          new l().H(2,4);
        }   
        void H(float a, float b)
    {
        System.out.printf("The hypotenuse of this right triangle is %.3f",Math.hypot(a,b));
    }
    }

Answer 9

Groovy : 78 Characters

a={x,y->printf"The hypotenuse of this right triangle is %.3f",Math.hypot(x,y)}

Assuming the task is just writing a method. If you need to take input parameters:

99 Characters

printf"The hypotenuse of this right triangle is %.3f",Math.hypot(args[0].toLong(),args[1].toLong())

I found two ways to it with the same length:

printf"The hypotenuse of this right triangle is %.3f",Math.sqrt(args.collect{it.toLong()**2}.sum())

Answer 10

newLISP, 103 characters

(let(a 3.1 b 4)(println"The hypotenuse of this right triangle is "(round(pow(add(pow a)(pow b)).5)-3)))

The unspecified input method helps a lot... :)

Answer 11

F#, 78

let f a b=sqrt(a*a+b*b)|>printf"The hypotenuse of this right triangle is %.3f"

Answer 12

Java : 155

class A{A(int x,int y){System.out.printf("The hypotenuse of this right triangle is %.3f",Math.hypot(x,y));}public static void main(String[]s){new A(1,4);}}

Answer 13

Fortran (90)

read(*,*)a,b;print'(a,f9.3)',"The hypotenuse of this right triangle is ",sqrt(a*a+b*b);end

Uses implicit typing so that a,b are single precision reals.

Answer 14

Javascript 98 characters/bytes

This is implemented as a browser alert in a function.

function p(a,b){alert('The hypotenuse of this right triangle is: '+Math.sqrt(a*a+b*b).toFixed(3))};

Answer 15

Ruby 2.1+ (73 characters)

f=->a,b{puts"The hypotenuse of this right triangle is %.3f"%(a+b*1i).abs}

Answer 16

Prolog

h(A,B):-X is A*A+B*B, C is sqrt(X),format('The hypotenuse of this right triangle is ~3f',C).

Answer 17

Bash with bc, 91

No bash script yet?!

read a b
echo -n 'The hypotenuse of this right triangle is '
bc<<<"scale=3;sqrt($a^2+$b^2)"

There is no way this can win.

Answer 18

Haskell, 77 characters

(\x y->print$"The hypotenuse of this right triangle is "++(show$sqrt$x^2+y^2))

Useage:

(\x y->print$"The hypotenuse of this right triangle is "++(show$sqrt$x^2+y^2)) 3.0 4.0
The hypotenuse of this right triangle is 5.0

Answer 19

Fortran 2008 (87 characters)

Based on the Fortran 90 solution, but now in Fortran 2008, HYPOT is an intrinsic function.

read(*,*)a,b;print'(a,f9.3)','The hypotenuse of this right triangle is ',hypot(a,b);end

Answer 20

J, 56 bytes

'The hypotenuse of this right triangle is '&,@":@(+&.*:)

explanation

J's "Under" verb &. is a nice fit here. It applies a transformation, executes a verb, and then applies the reverse transformation to the result. In this case, squaring is the transformation *:, its reverse is taking the square root, and the verb in question is addition. So we do addition "under" the square transformation. The rest is just formatting the number and cat'ing it onto the sentence.

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Answer 21

Perl 5, 69 bytes

printf"The hypotenuse of this right triangle is %.3f",sqrt<>**2+<>**2

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Answer 22

Tcl, 80 bytes

puts "The hypotenuse of this right triangle is [expr int(hypot($a,$b)*1e3)/1e3]"

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Answer 23

Jq 1.5, 80 bytes

"The hypotenuse of this right triangle is \(1e3*pow(map(.*.)|add;.5)|floor/1e3)"

Assumes input is [a,b]

Try it online at tio.run or jqplay.org

Answer 24

Axiom, 92 bytes

g(a,b)=="The hypotenuse of this right triangle is "((round((a^2+b^2)^.5*1.e3)/1.e3)::String)

test

(4) -> g(12, 19)
   (4)  "The hypotenuse of this right triangle is 22.472"
                                                             Type: String

Answer 25

05AB1E, 53 characters

"The hypotenuse of this right triangle is "|nOt₄*ï₄/«

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I could not figure out how to compress 05AB1E strings. :(

Explanation:

"..."|nOt₄*ï₄/«

     |             Push array of inputs.
      n            Square them.
       O           Get the sum.
        t          Get the square root.
         ₄*        Multiply by 1000
           ï       Convert to integer. This rounds it.
            ₄/     Divide by 1000
"..."         «    Append it to the string.
                   Implicit print.

Answer 26

Petit Computer BASIC, 66 bytes

INPUT A,B?"The hypotenuse of this right triangle is ";SQR(A*A+B*B)

PTC only displays the first 3 decimal places when printing.

Answer 27

Stax, 24 bytes

╬Z.-êû$P¿[▐Ä√#╙δdr▼▀Ö☺┐ç

Run and debug it

Unpacked, ungolfed, and commented, it looks like this.

`1/yyH\fBXNR&X+{.SC`p   print "The hypotenuse of this right triangle is "
:J+                     square and add the inputs
|Q                      square root
3j                      round to 3 places
p                       print

Run this one

Answer 28

APL (Dyalog), 51 bytes

'The hypotenuse of this right triangle is',3⍕|0j1⊥⎕

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0j1⊥⎕: Convert the input into base i. e.g a b -> b+ai

|: Magnitude

3⍕: Round to 3 decimal places

Answer 29

Japt, 37 bytes

`T hypÇQ«e  È ght â0Ø8  `+Nx²¬x3

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Answer 30

JavaScript (Node.js), 76 bytes

a=>b=>'The hypotenuse of this right triangle is '+Math.hypot(a,b).toFixed(3)

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Explanation

a => b => // the two arguments (curry method)
    `The hypotenuse of this right triangle is // write the text required
    ${Math.hypot(a,b)}` // and use JS Math.hypot function to calculate the hypotenuse. 

Alternately, if the you spare me the pain of writing this text.

f=Math.hypot // is also a valid answer