Swapping "Good" and "Bad"

Question

Challenge Description:

Write a program that asks the user for input. The user will enter Good or Bad. You do not have to support any other input. If the user enters Good, print Bad and vice versa (to stdout etc).

Notes:

1) You cannot use any other pair of two words.

2) Your program only has to ask and print once.

3) You do not need to display prompt string.

4) The output must appear separated from the input by any means.

5) No function is allowed accepting the value and returning the result; User must interact with the program.

Good luck!

May we write a function that takes input as argument instead of prompting for it? — Adám, Commented Jul 7, 2019 at 14:01
Please edit your question about whether a function is allowed or not. I would highly recommend not restricting input to STDIN, unless you have a very good reason to (and I can't see one) — Jo King, Commented Jul 9, 2019 at 0:21
asks the user for input (stdin etc) shows that only STDIN or interactive input is allowed. Please change this to all default I/O methods — MilkyWay90, Commented Jul 9, 2019 at 17:05
"Asks the user for input", should that be some explicit question? Because an empty CLI prompt isn't really asking for anything … — user0721090601, Commented Jul 10, 2019 at 13:23
What is the purpose for this restriction? No function is allowed accepting the value and returning the result; User must interact with the program — mbomb007, Commented Jul 12, 2019 at 13:58

Jonathan Allan · Accepted Answer · 2019-07-08 22:20:37Z

53

Python 3, 32 31 bytes

exit('GBoaodd'['G'<input()::2])

Try it online!

How?

Tests if input is 'Good' by comparing 'G'<input().

Uses the fact that in Python False==0 and True==1 to use the result as the start index of a slice of 'GBoaodd' using an undefined stop and a step of 2 with 'GBoaodd'[start:stop:step].

Prints to STDERR (saving a byte with exit in place of print).

edited Jul 8, 2019 at 22:20

answered Jul 7, 2019 at 14:58

Jonathan Allan

110k7 gold badges65 silver badges282 bronze badges

\$\begingroup\$ What a trick! Can't understand how this works. \$\endgroup\$
– Ishaq Khan
Commented Jul 7, 2019 at 15:50
\$\begingroup\$ Can you use a lambda to shorten bytes? \$\endgroup\$
– MilkyWay90
Commented Jul 7, 2019 at 16:55
\$\begingroup\$ @MilkyWay90 As per the question it must be a program accepting input. \$\endgroup\$
– Jonathan Allan
Commented Jul 7, 2019 at 17:11
\$\begingroup\$ @A__ by default yes, although there is a comment by OP which suggests it could be overruled here. \$\endgroup\$
– Jonathan Allan
Commented Jul 8, 2019 at 7:01
7

\$\begingroup\$ Too bad that "Good" and "Bad" share a "d", or you could do 'GoodBad'.strip(input()) which is a byte shorter. \$\endgroup\$
– xnor
Commented Jul 10, 2019 at 4:16

| Show 1 more comment

Adám · Accepted Answer · 2019-07-08 04:32:56Z

20

APL (Dyalog Unicode), 13 bytes^SBCS

Full program that prompts for input from stdin and prints to stdout.

'GooBad'~¯1↓⍞

Try it online!

⍞ prompt for input from stdin; Good or Bad

¯1↓ drop the last character (d); Goo or Ba

'GooBad'~ multiset subtract those characters from these; Bad or Good

edited Jul 8, 2019 at 4:32

answered Jul 7, 2019 at 14:05

Adám

31.1k3 gold badges124 silver badges287 bronze badges

7

\$\begingroup\$ Why the downvote‽ \$\endgroup\$
– Adám
Commented Jul 7, 2019 at 14:39
1

\$\begingroup\$ Does the code have GooBad or GoodBad? \$\endgroup\$
– NoOneIsHere
Commented Jul 8, 2019 at 1:58
\$\begingroup\$ I think it should have GooBad, as adding a character ```d`` will make this post 14 bytes. \$\endgroup\$
– user85052
Commented Jul 8, 2019 at 2:20
\$\begingroup\$ @NoOneIsHere Thanks. Fixed. \$\endgroup\$
– Adám
Commented Jul 8, 2019 at 4:33

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Doorknob · Accepted Answer · 2019-07-07 16:03:56Z

13

bash, 20 bytes

sed s/$1//<<<GoodBad

Try it online!

answered Jul 7, 2019 at 16:03

Doorknob

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MilkyWay90 · Accepted Answer · 2019-07-09 16:07:38Z

Turing Machine But Way Worse, 405 bytes

0 0 0 1 1 0 0
1 1 1 1 2 0 0
0 2 0 1 3 0 0
0 3 0 1 4 0 0
0 4 0 1 5 0 0
1 5 0 1 6 0 0
0 5 1 1 h 0 0
1 6 1 1 7 0 0
1 7 0 1 8 1 0
0 8 0 1 9 0 0
1 9 1 1 9 0 0
0 9 0 1 a 0 0
1 a 0 1 a 0 0
0 a 0 0 b 0 0
0 b 1 1 c 1 0
0 c 0 0 d 0 0
1 d 0 0 e 0 0
0 e 0 0 f 0 0
0 f 1 1 g 1 1
1 h 1 1 i 0 0
0 i 1 1 j 1 0
0 j 0 1 k 0 0
1 k 1 1 k 0 0
0 k 0 1 l 0 0
0 l 1 1 l 0 0
1 l 1 0 m 1 0
1 m 1 1 n 1 0
1 n 1 1 o 0 0
0 o 0 1 p 1 1

Try it online!

Well, this took a while.

UNFINISHED EXPLANATION:

0 0 0 1 1 0 0 Start going to the sixth bit
1 1 1 1 2 0 0
0 2 0 1 3 0 0
0 3 0 1 4 0 0
0 4 0 1 5 0 0 End going to the sixth bit
1 5 0 1 6 0 0 If the sixth bit is 1, then it is Good. Start transforming "G" to "B" and go to state 6
0 5 1 1 h 0 0 Else, it is Bad. Start transforming "B" to "G" and go to state h
1 6 1 1 7 0 0 Keep on transforming "G" to "B"
1 7 0 1 8 1 0 End transforming and print "B"
0 8 0 1 9 0 0 We are in the first "o" in "Good". Start moving into the 5th bit.
1 9 1 1 9 0 0
0 9 0 1 a 0 0
1 a 0 1 a 0 0 Do some looping magic and start transforming "o" to "a"
0 a 0 0 b 0 0 End looping magic
0 b 1 1 c 1 0 End transforming and print "a"
0 c 0 0 d 0 0 
1 d 0 0 e 0 0 Start transforming "a" to "d"
0 e 0 0 f 0 0 
0 f 1 1 g 1 1 Stop transforming, print "d", and terminate
1 h 1 1 i 0 0 Continue transforming "B" to "G"
0 i 1 1 j 1 0 Stop transforming and print out "G"
0 j 0 1 k 0 0 Start going into position to print out "oo"
1 k 1 1 k 0 0
0 k 0 1 l 0 0 Move more efficiently using LOOPING MAGIC1!1111111 
0 l 1 1 l 0 0 looping magic end, start transforming
1 l 1 0 m 1 0 end transforming and print out out "o"
1 m 1 1 n 1 0 print out "o" again
1 n 1 1 o 0 0 get into the "d" byte
0 o 0 1 p 1 1 print "d" and execute YOU HAVE BEEN TERMINATED

"Turing-Machine-But-Way-Worse" is, without a doubt, my new favorite esolang. — User1000547, Commented Jul 8, 2019 at 17:53
@A__ It isn't actually ArnoldC; I just put the exit command as a comment as a joke — MilkyWay90, Commented Jul 10, 2019 at 15:41

Community · Accepted Answer · 2020-06-17 09:04:33Z

8088 Assembly, IBM PC DOS, 25 bytes

Unassembled:

BA 0110     MOV  DX, OFFSET GB  ; point DX to 'Good','Bad' string 
D1 EE       SHR  SI, 1          ; point SI to DOS PSP (80H) 
02 04       ADD  AL, [SI]       ; add input string length to AL, set parity flag 
7B 02       JNP  DISP           ; if odd parity, input was 'Bad' so jump to display 'Good'
02 D0       ADD  DL, AL         ; otherwise add string length as offset for 'Bad' string 
        DISP: 
B4 09       MOV  AH, 9          ; DOS display string function 
CD 21       INT  21H            ; call DOS API, write string to console 
C3          RET                 ; return to DOS 
        GB  DB  'Good$','Bad$'

Explanation:

Looks at the length of input string (plus leading space) that DOS stores at memory address 80H, and adds it to AL (initially 0 by DOS). If there is an odd number of 1 bits in the binary representation of the string length, the CPU parity flag is set to odd, and vice-versa. So input string ' Bad' length 4 (0000 0100), is odd parity and input string ' Good' is 5 (0000 0101) is even parity.

DX is initially set to point to the string 'Good$Bad$', and if parity is even (meaning input was ' Good') advance the string pointer by that length (5) so it now points to 'Bad$'. If parity is odd, do nothing since it already points to 'Good$'. Then use DOS API to display a $ terminated string to console.

Example:

Download and test GOODBAD.COM or build from xxd dump:

0000000: ba10 01d1 ee02 047b 0202 d0b4 09cd 21c3  .......{......!.
0000010: 476f 6f64 2442 6164 24                   Good$Bad$

score 7 · Accepted Answer · 2019-07-08 02:33:29Z

7

Python 3, 38 37 34 33 bytes

exit("C">input()and"Good"or"Bad")

Try it online!

exit() : returns an exit code as output

"C">input() : Checks whether the input is larger than the string C in the alphabetical order

and"Good" : If the result is True, then returns with Good

or"Bad" : Otherwise, returns with Bad

edited Jul 8, 2019 at 2:33

answered Jul 7, 2019 at 14:37

user85052

2

\$\begingroup\$ 34: print("C">input()and"Good"or"Bad") \$\endgroup\$
– Adám
Commented Jul 7, 2019 at 14:51
2

\$\begingroup\$ exit(input()[3:]and"Bad"or"Good") also works for the same byte count. \$\endgroup\$
– Neil
Commented Jul 8, 2019 at 9:14

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Jonathan Allan · Accepted Answer · 2019-07-09 07:03:16Z

7

Jelly, 8 bytes

“Ċ³ṫ³»œṣ

Try it online!

A full program expecting a Python formatted string as an argument

How?

“Ċ³ṫ³»œṣ - Main Link: list of characters, S
“Ċ³ṫ³»   - compression of dictionary words "Good"+"Bad" = ['G','o','o','d','B','a','d']
      œṣ - split on sublists equal to S
         - implicit, smashing print

edited Jul 9, 2019 at 7:03

answered Jul 7, 2019 at 15:07

Jonathan Allan

110k7 gold badges65 silver badges282 bronze badges

1

\$\begingroup\$ Looks like OP responded, input isn't restricted to STDIN. \$\endgroup\$
– Erik the Outgolfer
Commented Jul 9, 2019 at 5:44

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pommicket · Accepted Answer · 2019-07-08 03:16:37Z

6

C, 39 38 bytes

main(){puts("Good\0Bad"+getchar()%6);}

Try it online!

Saved one byte thanks to @tsh.

edited Jul 8, 2019 at 3:16

answered Jul 8, 2019 at 1:23

pommicket

3,1872 gold badges14 silver badges20 bronze badges

5

\$\begingroup\$ main(){puts("Good\0Bad"+getchar()%6);} 38 bytes \$\endgroup\$
– tsh
Commented Jul 8, 2019 at 1:47
\$\begingroup\$ Shouldn't you add #include<stdio.h>? \$\endgroup\$
– polfosol ఠ_ఠ
Commented Jul 9, 2019 at 11:04
4

\$\begingroup\$ @polfosolఠ_ఠ If this were anything but code golf, you should, but in C89, you can implicitly declare functions. \$\endgroup\$
– pommicket
Commented Jul 9, 2019 at 11:11
\$\begingroup\$ Can you use a null byte instead of \0? \$\endgroup\$
– Hello Goodbye
Commented Dec 19, 2019 at 14:18

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Helena · Accepted Answer · 2019-07-08 19:53:02Z

6

brainfuck, 72 bytes

,>+++++>,>,>,>,[<<<<[-<->>---<]<.>>+.>>.>>>]<[<<<[-<+>>+++<]<.>>-..>.>>]

Try it online!

Explanation: ,>+++++>,>,>,>,

Read either: "G", 5, "o", "o", "d" or "B", 5, "a", "d", 0

[<<<<[-<->>---<]<.>>+.>>.>>>] If the last character is not zero:

Substract 5 from the first cell once and from the third cell thrice. Increment cell 3

Output cells 1, 3, 5.

<[<<<[-<+>>+++<]<.>>-..>.>>]

Otherwise add 5 to the first cell once and to the third cell thrice.

Decrement cell 3

Output cells 1, 3, 3, 4

answered Jul 8, 2019 at 19:53

Helena

4313 silver badges7 bronze badges

\$\begingroup\$ That's a nice solution. You can shorten it a little bit by not using a newline in the input. ,>+++++>,>,>,[<<<[-<->>---<]<.>>+.>>.>>]<[<<[-<+>>+++<]<.>>-..>.>] \$\endgroup\$
– Dorian
Commented Jul 9, 2019 at 8:29
\$\begingroup\$ yeah, I realized that there is something to optimise there, but I found it hard to interpret what is necessary to comply with rule 4 \$\endgroup\$
– Helena
Commented Jul 9, 2019 at 17:11

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Robert S. · Accepted Answer · 2019-07-09 19:47:53Z

5

R, 42 37 35 32 bytes

-10 thanks to Giuseppe and AkselA!

`if`(scan(,'')>'C','Bad','Good')

Try it online!

edited Jul 9, 2019 at 19:47

answered Jul 8, 2019 at 20:24

Robert S.

1,32311 silver badges17 bronze badges

1

\$\begingroup\$ No problem. I recognize a lot of the other R golfers' names, so I often click on posts if I see their name as the most recent. :-) \$\endgroup\$
– Giuseppe
Commented Jul 8, 2019 at 20:35
1

\$\begingroup\$ using "C" instead of the first "Bad" as in this answer will save another couple bytes. \$\endgroup\$
– Giuseppe
Commented Jul 8, 2019 at 20:50
1

\$\begingroup\$ Just out of curiosity, would something like `if`(readline()>"C","Bad","Good") be a valid answer? I'm new to this game and its rules. \$\endgroup\$
– AkselA
Commented Jul 9, 2019 at 15:33
2

\$\begingroup\$ @AkselA yes, but I'd also suggest using scan(,"") instead of readline(). Feel free to come to golfR, the R golf chatroom if you have any R-specific questions :-) \$\endgroup\$
– Giuseppe
Commented Jul 9, 2019 at 19:44
2

\$\begingroup\$ @AkselA also see Tips for Golfing in R for some specific tips; there are hidden gems in there if you read them :-) \$\endgroup\$
– Giuseppe
Commented Jul 9, 2019 at 19:46

| Show 1 more comment

GammaFunction · Accepted Answer · 2019-08-28 05:23:20Z

5

sed, 21 16 13 bytes

Thanks @Cowsquack for the hints.

/B/cGood
cBad

~~Try it online! Try it online!~~ Try it online!

TIL c will short-circuit the current line's parsing.

edited Aug 28, 2019 at 5:23

answered Aug 27, 2019 at 15:05

GammaFunction

6,91413 silver badges23 bronze badges

2

\$\begingroup\$ c offers a shorter solution \$\endgroup\$
– user41805
Commented Aug 27, 2019 at 16:10
1

\$\begingroup\$ You can still save 3 more bytes using c \$\endgroup\$
– user41805
Commented Aug 28, 2019 at 5:03
1

\$\begingroup\$ Had to play around with it a bit, but I figured it out! \$\endgroup\$
– GammaFunction
Commented Aug 28, 2019 at 5:24

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ovs · Accepted Answer · 2020-08-13 09:05:33Z

5

Retina, 10 bytes

:`GoodBad

Try it online!

: swaps the input and the regex, so this computes 'GoodBad'.replace(input, '').

answered Aug 13, 2020 at 9:05

ovs

60.6k3 gold badges47 silver badges161 bronze badges

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nimi · Accepted Answer · 2019-07-07 17:05:31Z

4

Haskell, 36 34 bytes

interact g
g"Bad"="Good"
g _="Bad"

Try it online!

Edit: -2 bytes thanks to @cole

edited Jul 7, 2019 at 17:05

answered Jul 7, 2019 at 16:12

nimi

35.9k4 gold badges34 silver badges99 bronze badges

1

\$\begingroup\$ 34 bytes \$\endgroup\$
– cole
Commented Jul 7, 2019 at 17:01

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ADJenks · Accepted Answer · 2019-07-08 06:06:55Z

4

JavaScript 31 bytes

I like Arnauld's answer, but I would like it to accept user input and be runnable on StackExchange like so:

alert(prompt()[3]?'Bad':'Good')

edited Jul 8, 2019 at 6:06

answered Jul 8, 2019 at 5:57

ADJenks

1814 bronze badges

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Hello Goodbye · Accepted Answer · 2019-12-19 14:42:56Z

Shakespeare Programming Language, 582 bytes

(Whitespace added for readability)

G.Ajax,.Puck,.Act I:.Scene I:.[Enter Ajax and Puck]Ajax:
Open mind.Be you nicer the sum ofa big cat the cube ofa big big cat?If solet usScene V.
You is the sum ofthe sum ofyou a big big cat a cat.Speak thy.You is the sum ofyou twice twice twice the sum ofa big big cat a cat.Speak thy.Speak thy.You is the square oftwice the sum ofa big big cat a cat.Let usScene X.
Scene V:.Ajax:
You is the sum ofthe sum ofyou a big big pig a pig.Speak thy.You is the sum ofyou the sum ofa big big big big big cat a pig.Speak thy.You is the sum ofyou the sum ofa big cat a cat.
Scene X:.Ajax:Speak thy.

Try it online!

I get the first letter of the input with Open mind. Then I need to determine what it is. Of all the numbers between B=66 and G=71, my brute forcer says 66 is the shortest to write (the sum ofa big cat the cube ofa big big cat), so I compare the first letter of the input to 66. Scene I continues to print Good, or Scene V prints Bad.

Pseudo Nym · Accepted Answer · 2019-12-19 23:02:46Z

4

Charcoal, 13 bytes

¿⁻ＬＳ³Ba¦Goo¦d

Try it online!

Explanation:

¿⁻ＬＳ³          If length of input minus 3 is truthy:
      Ba¦         print Ba
         Goo¦       else print Goo
             d        print d

answered Dec 19, 2019 at 23:02

Pseudo Nym

5112 silver badges5 bronze badges

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negative seven · Accepted Answer · 2019-07-08 07:09:56Z

3

Befunge-93, 20 18 bytes

"BadooGB"~-_#@,,<,

Try it online!

-2 bytes thanks to Jo King

edited Jul 8, 2019 at 7:09

answered Jul 7, 2019 at 15:38

negative seven

2,2011 gold badge10 silver badges19 bronze badges

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G B · Accepted Answer · 2019-07-08 08:02:44Z

3

Ruby, 22 bytes

->n{n>?F?"Bad":"Good"}

Try it online!

edited Jul 8, 2019 at 8:02

answered Jul 8, 2019 at 7:55

G B

22.8k1 gold badge20 silver badges53 bronze badges

\$\begingroup\$ The question does say "asks the user for input", but the shortest way to do that is replacing the lambda with p gets and so it's the same length. (my original comment said you could save 2 bytes, but I didn't account for printing the result) \$\endgroup\$
– DaveMongoose
Commented Jul 8, 2019 at 10:09
3

\$\begingroup\$ If we're actually going to be talking about a full program asking user for input, using the -p flag would give the most efficient answer: $_=$_>?F?:Bad:"Good" is 20 bytes. Try it online! \$\endgroup\$
– Value Ink
Commented Jul 8, 2019 at 23:17

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Community · Accepted Answer · 2020-06-17 09:04:33Z

3

05AB1E, 10 9 bytes

”‚¿‰±”áIK

-1 byte thanks to @Emigna.

Try it online or verify both test cases.

Explanation:

”‚¿‰±”     # Push dictionary string "Good Bad"
      á    # Only keep letters (to remove the space)
       IK  # Remove the input
           # (output the result implicitly)

See this 05AB1E tip of mine (section How to use the dictionary?), to understand why ”‚¿‰±” is "Good Bad".

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Jul 8, 2019 at 8:06

Kevin Cruijssen

131k13 gold badges144 silver badges384 bronze badges

\$\begingroup\$ I can see many alternate variations on this, but they all end up at the same byte count :( \$\endgroup\$
– Emigna
Commented Jul 8, 2019 at 9:49
1

\$\begingroup\$ Actually, you can save a byte with á. \$\endgroup\$
– Emigna
Commented Jul 8, 2019 at 9:52
\$\begingroup\$ @Emigna Ah of course, brilliant. Now that I see á I can't believe I hadn't thought about it, but at the same time I know I would have never thought about it. ;) Thanks! (And yeah, I had a few 10-byte alternatives as well.) \$\endgroup\$
– Kevin Cruijssen
Commented Jul 8, 2019 at 9:54
1

\$\begingroup\$ Don't even need á, ”‚¿Bad”IK is also a 9. \$\endgroup\$
– Grimmy
Commented Jul 8, 2019 at 10:29

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Felix Bohnacker · Accepted Answer · 2019-07-08 22:29:14Z

3

Java (JDK), 124 bytes

interface G{static void main(String[]a){System.out.print(new java.util.Scanner(System.in).next().length()>3?"Bad":"Good");}}

Try it online!

Most likely, there‘s still some room for improvement, but I‘m entirely new to code golfing.

edited Jul 8, 2019 at 22:29

answered Jul 8, 2019 at 17:42

Felix Bohnacker

313 bronze badges

2

\$\begingroup\$ Welcome! Consider adding an explanation and/or a link to an online interpreter where you can run your code. (See other answers for examples.) Code-only answers tend to be automatically flagged as low-quality. \$\endgroup\$
– mbomb007
Commented Jul 8, 2019 at 21:38
4

\$\begingroup\$ The length part could just be !="Bad" \$\endgroup\$
– Jo King ♦
Commented Jul 9, 2019 at 2:14
\$\begingroup\$ 109 bytes \$\endgroup\$
– Olivier Grégoire
Commented Aug 27, 2019 at 14:32

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DaveMongoose · Accepted Answer · 2019-07-09 11:15:58Z

3

Ruby, 30 28 bytes

puts %w|Good Bad|-gets.split

Not the golf-iest, but I like the abuse of split to remove the trailing newline and convert to an array in one call.

EDIT -2 bytes thanks to Value Ink's suggestion!

edited Jul 9, 2019 at 11:15

answered Jul 8, 2019 at 11:20

DaveMongoose

2411 silver badge4 bronze badges

\$\begingroup\$ This prints "Good" or "Bad" (with quotes); I'm not sure that's allowed. \$\endgroup\$
– Jordan
Commented Jul 8, 2019 at 16:29
1

\$\begingroup\$ Abuse the fact that puts prints each element of an array on a separate line. It's 3 bytes more expensive than p, but it evens out since you take out the [0] and then save 2 more bytes by no longer needing parens. Try it online! \$\endgroup\$
– Value Ink
Commented Jul 8, 2019 at 23:22
\$\begingroup\$ @ValueInk thanks! Jordan's issue also gets resolved by this change so it's a win-win. \$\endgroup\$
– DaveMongoose
Commented Jul 9, 2019 at 11:20

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user85052user85052 · Accepted Answer · 2020-01-18 09:47:33Z

3

GolfScript, 11 bytes

"GoodBad"\/

Try it online!

Explanation

"GoodBad"   # Define the lookup table "GoodBad"
         \  # Swap the input so that it can be used by /
          / # Split the lookup table by occurences of the input
            # Implicit print, smashing

answered Jan 18, 2020 at 9:47

user85052

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Peter · Accepted Answer · 2023-01-19 12:05:29Z

3

C (gcc), 48 bytes

main(){puts(getchar()-66?"Bad":"Good");}

Try It Online!

The program only actually takes one character as input, although getchar reads until a newline is found unlike getch which only lets you input a single character. It checks if there's a difference between that character and the ascii code for 'B' (66), printing "Bad" if there is and "Good" if there isn't.

edited Jan 19, 2023 at 12:05

answered Jan 18, 2023 at 16:55

Peter

1,0175 silver badges15 bronze badges

\$\begingroup\$ Taking just one character as input is perfectly valid, and is in fact what most other answers are doing \$\endgroup\$
– mousetail 'he-him'
Commented Jan 19, 2023 at 10:13
\$\begingroup\$ @mousetail Thanks, I edited my answer to remove the question :) \$\endgroup\$
– Peter
Commented Jan 19, 2023 at 12:06

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cobrexus · Accepted Answer · 2023-11-18 20:31:39Z

3

JavaScript, 35 32 31 bytes

-3 bytes thanks to @xigoi

-1 byte thanks to @l4m2

alert(prompt()[3]?'Bad':'Good')

edited Nov 18, 2023 at 20:31

answered Jul 27, 2021 at 21:41

cobrexus

8336 silver badges19 bronze badges

2

\$\begingroup\$ -3 bytes: prompt()<'G' \$\endgroup\$
– xigoi
Commented Jul 27, 2021 at 22:48
1

\$\begingroup\$ prompt()[3] enough \$\endgroup\$
– l4m2
Commented Jan 18, 2023 at 14:47

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Neil · Accepted Answer · 2019-07-07 15:39:56Z

2

Retina 0.8.2, 20 bytes

oo
o
T`G\oaB`Ro
o
oo

Try it online! Link includes test suite. Explanation:

oo
o

Turn Good into God.

T`G\oaB`Ro

Transpose the letters GoaB with the reverse of that list, thus exchanging G with B and o with a, i.e. exchanging God with Bad.

o
oo

Turn God into Good.

answered Jul 7, 2019 at 15:39

Neil

177k12 gold badges74 silver badges281 bronze badges

1

\$\begingroup\$ 17 bytes, but less creative \$\endgroup\$
– pbeentje
Commented Jul 8, 2019 at 14:38

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recursive · Accepted Answer · 2019-07-07 18:08:52Z

2

Stax, 9 8 bytes

çEF♫a║▬h

Run and debug it

~~Essentially replace("BadGood", input, "").~~

Multiset xor with "GooBa". Algorithm copied verbatim from Luis Mendo

edited Jul 7, 2019 at 18:08

answered Jul 7, 2019 at 15:14

recursive

10.4k20 silver badges36 bronze badges

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Benjamin Urquhart · Accepted Answer · 2019-07-07 21:35:29Z

2

Java, 30 bytes

s->s.charAt(0)>66?"Bad":"Good"

TIO

answered Jul 7, 2019 at 21:35

Benjamin Urquhart

1,5248 silver badges25 bronze badges

\$\begingroup\$ How does it take input from the user (e.g. by reading from stdin) and print the result (instead of just returning it)? \$\endgroup\$
– nimi
Commented Jul 7, 2019 at 22:14
\$\begingroup\$ @nimi OP hasn't specified whether IO includes arguments and returns. By default, it is allowed \$\endgroup\$
– Benjamin Urquhart
Commented Jul 7, 2019 at 22:52
\$\begingroup\$ "ask the user for input" sounds like reading the input from stdin (or equivalent) to me. "print" usually means print to stdout (or equivalent). To my understanding the IO defaults are overwritten. \$\endgroup\$
– nimi
Commented Jul 7, 2019 at 22:59
\$\begingroup\$ @nimi I can argue a missing argument error is a prompt. As for output, you do have a point. \$\endgroup\$
– Benjamin Urquhart
Commented Jul 7, 2019 at 23:04
\$\begingroup\$ You can take the inputs as character-arrays, which is allowed by default for strings, to change s.charAt(0) to s[0]: 23 bytes. \$\endgroup\$
– Kevin Cruijssen
Commented Mar 4, 2022 at 15:31

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Xcali · Accepted Answer · 2019-07-08 03:53:46Z

2

Perl 5 `-p`, 15 bytes

$_=/B/?Good:Bad

Try it online!

answered Jul 8, 2019 at 3:53

Xcali

16.2k2 gold badges15 silver badges39 bronze badges

\$\begingroup\$ Just revisited this. Abusing flags as usual -0144l, you can save the ds! Try it online! \$\endgroup\$
– Dom Hastings
Commented Jun 21, 2022 at 21:17

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Wernisch · Accepted Answer · 2019-07-08 09:35:09Z

2

Excel, 24 bytes

=IF(A1>"C","Bad","Good")

Using @MilkyWay90's <C suggestion.

answered Jul 8, 2019 at 9:35

Wernisch

3,03410 silver badges22 bronze badges

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640KB · Accepted Answer · 2019-07-08 17:05:00Z

2

PHP, 26 23 bytes

A ternary is just cheaper:

<?=$argn==Bad?Goo:Ba?>d

Try it online!

Original answer, 26 bytes

<?=[Ba,Goo][$argn==Bad]?>d

Try it online!

Or 21 bytes (but this is basically Arnauld's answer)

<?=$argn[3]?Ba:Goo?>d

Try it online!

edited Jul 8, 2019 at 17:05

answered Jul 8, 2019 at 16:51

640KB

11.9k2 gold badges35 silver badges57 bronze badges

\$\begingroup\$ Judging by the phrasing of the question, readline() is likely more appropriate than $argn. \$\endgroup\$
– Progrock
Commented Oct 14, 2019 at 15:55

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Swapping "Good" and "Bad"

90 Answers 90

Python 3, 32 31 bytes

How?

APL (Dyalog Unicode), 13 bytesSBCS

bash, 20 bytes

Turing Machine But Way Worse, 405 bytes

8088 Assembly, IBM PC DOS, 25 bytes

Python 3, 38 37 34 33 bytes

Jelly, 8 bytes

How?

C, 39 38 bytes

brainfuck, 72 bytes

R, 42 37 35 32 bytes

sed, 21 16 13 bytes

Retina, 10 bytes

Haskell, 36 34 bytes

JavaScript 31 bytes

Shakespeare Programming Language, 582 bytes

Charcoal, 13 bytes

Explanation:

Befunge-93, 20 18 bytes

Ruby, 22 bytes

05AB1E, 10 9 bytes

Java (JDK), 124 bytes

Ruby, 30 28 bytes

GolfScript, 11 bytes

Explanation

C (gcc), 48 bytes

JavaScript, 35 32 31 bytes

Retina 0.8.2, 20 bytes

Stax, 9 8 bytes

Java, 30 bytes

Perl 5 -p, 15 bytes

Excel, 24 bytes

PHP, 26 23 bytes

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