ASCII Cayley Graph

Question

While doing some research for a different challenge I'm formulating, I came across a Cayley graph, specifically this one. Since I'm one of the top ascii-art challenge writers, of course I had to make an ASCII art challenge for this.

Your challenge is to produce this ASCII art depiction of a Cayley graph of the free group on two generators as follows:

                                               +                                               
                                              +++                                              
                                             + | +                                             
                                            ++-+-++                                            
                                             + | +                                             
                                          +    |    +                                          
                                         +++   |   +++                                         
                                        + |    |    | +                                        
                                       ++-+----+----+-++                                       
                                        + |    |    | +                                        
                                         +++   |   +++                                         
                                          +    |    +                                          
                                   +           |           +                                   
                                  +++          |          +++                                  
                                 + | +         |         + | +                                 
                                ++-+-++        |        ++-+-++                                
                                 + | +         |         + | +                                 
                              +    |           |           |    +                              
                             +++   |           |           |   +++                             
                            + |    |           |           |    | +                            
                           ++-+----+-----------+-----------+----+-++                           
                            + |    |           |           |    | +                            
                             +++   |           |           |   +++                             
                              +    |           |           |    +                              
                                 + | +         |         + | +                                 
                                ++-+-++        |        ++-+-++                                
                                 + | +         |         + | +                                 
                    +             +++          |          +++             +                    
                   +++             +           |           +             +++                   
                  + | +                        |                        + | +                  
                 ++-+-++                       |                       ++-+-++                 
                  + | +                        |                        + | +                  
               +    |    +                     |                     +    |    +               
              +++   |   +++                    |                    +++   |   +++              
             + |    |    | +                   |                   + |    |    | +             
            ++-+----+----+-++                  |                  ++-+----+----+-++            
             + |    |    | +                   |                   + |    |    | +             
              +++   |   +++                    |                    +++   |   +++              
               +    |    +                     |                     +    |    +               
        +           |                          |                          |           +        
       +++          |                          |                          |          +++       
      + | +         |                          |                          |         + | +      
     ++-+-++        |                          |                          |        ++-+-++     
      + | +         |                          |                          |         + | +      
   +    |           |                          |                          |           |    +   
  +++   |           |                          |                          |           |   +++  
 + |    |           |                          |                          |           |    | + 
++-+----+-----------+--------------------------+--------------------------+-----------+----+-++
 + |    |           |                          |                          |           |    | + 
  +++   |           |                          |                          |           |   +++  
   +    |           |                          |                          |           |    +   
      + | +         |                          |                          |         + | +      
     ++-+-++        |                          |                          |        ++-+-++     
      + | +         |                          |                          |         + | +      
       +++          |                          |                          |          +++       
        +           |                          |                          |           +        
               +    |    +                     |                     +    |    +               
              +++   |   +++                    |                    +++   |   +++              
             + |    |    | +                   |                   + |    |    | +             
            ++-+----+----+-++                  |                  ++-+----+----+-++            
             + |    |    | +                   |                   + |    |    | +             
              +++   |   +++                    |                    +++   |   +++              
               +    |    +                     |                     +    |    +               
                  + | +                        |                        + | +                  
                 ++-+-++                       |                       ++-+-++                 
                  + | +                        |                        + | +                  
                   +++             +           |           +             +++                   
                    +             +++          |          +++             +                    
                                 + | +         |         + | +                                 
                                ++-+-++        |        ++-+-++                                
                                 + | +         |         + | +                                 
                              +    |           |           |    +                              
                             +++   |           |           |   +++                             
                            + |    |           |           |    | +                            
                           ++-+----+-----------+-----------+----+-++                           
                            + |    |           |           |    | +                            
                             +++   |           |           |   +++                             
                              +    |           |           |    +                              
                                 + | +         |         + | +                                 
                                ++-+-++        |        ++-+-++                                
                                 + | +         |         + | +                                 
                                  +++          |          +++                                  
                                   +           |           +                                   
                                          +    |    +                                          
                                         +++   |   +++                                         
                                        + |    |    | +                                        
                                       ++-+----+----+-++                                       
                                        + |    |    | +                                        
                                         +++   |   +++                                         
                                          +    |    +                                          
                                             + | +                                             
                                            ++-+-++                                            
                                             + | +                                             
                                              +++                                              
                                               +

Input

No input, unless your language explicitly requires input to run.

Output

The ASCII art representation shown above.

MD5 Hashes

Since this is a pretty large output, to check your work here are some MD5 hashes of example forms of output (all are UTF-8 without BOM):

Square space padding, CR/LF linefeeds, and trailing newline -- 954B93871DAAE7A9C05CCDF79B00BF3C -- this is the representation used above.
Square space padding, CR/LF linefeeds, no trailing newline -- 28405EF91DA305C406BD03F9275A175C
Square space padding, LF linefeeds, and trailing newline -- 8CA65FB455DA7EE5A4C10F25CBD49D7E
Square space padding, LF linefeeds, no trailing newline -- FDB1547D68023281BB60DBEC82C8D281
No trailing spaces, CR/LF linefeeds, and trailing newline -- 77FDE8CE5D7BD1BDD47610BA23264A19
No trailing spaces, CR/LF linefeeds, no trailing newline -- EAD390C3EFD37F0FCACE55A84B793AB5
No trailing spaces, LF linefeeds, and trailing newline -- 1F6CAB740F87881EB2E65BED65D08C36
No trailing spaces, LF linefeeds, no trailing newline -- 7D41CE1E637619FEA9515D090BFA2E9C
If there is an additional MD5 you would like for comparison, please let me know and I'll create it and update the challenge.

Rules

Leading or trailing newlines or whitespace are all optional, so long as the characters themselves line up correctly.
Either a full program or a function are acceptable. If a function, you can return the output rather than printing it.
If possible, please include a link to an online testing environment so other people can try out your code!
Standard loopholes are forbidden.
This is code-golf so all usual golfing rules apply, and the shortest code (in bytes) wins.

I'm slightly surprised this isn't parametrised in any way - it looks as if it should be the sixth in a sequence. — Neil, Commented Mar 14, 2017 at 18:30
@Neil I had considered doing so, but decided against it for fear that it would increase the difficulty too much for little gain. — AdmBorkBork, Commented Mar 14, 2017 at 18:33
Looks like the runs of -/|s follow the formula (2<<n)-n-2 rather than (1<<n)-1 which is what my original guess would have been. — Neil, Commented Mar 14, 2017 at 19:25
@Neil They're actually Eulerian numbers, since that provided the best aesthetic. — AdmBorkBork, Commented Mar 14, 2017 at 19:30

Neil · Accepted Answer · 2017-03-16 01:08:21Z

JavaScript (ES6), 204 195 188 180 bytes

f=
_=>[...Array(9119)].map((_,i)=>~i%96?g(48+~(i/96),47-i%96,5):`
`,g=(x,y,z,n=(1<<z)-z)=>x|y?(x=x<0?-x:x)+(y=y<0?-y:y)<n?` |-+`[2*!x+!y]:z--?x>y?g(x-n,y,z):g(x,y-n,z):` `:`+`).join``
;document.write(`<pre>`+f())

Square space padding, LF linefeeds, ~~and~~ no trailing newline, although I haven't checked the MD5.

f=
m=>[...Array((w=(4<<m)-m*-~m-2)*~-w)].map((_,i)=>~i%w?g(w/2+~(i/w),w/2-i%w-1,m):`
`,g=(x,y,z,n=(1<<z)-z)=>x|y?(x=x<0?-x:x)+(y=y<0?-y:y)<n?` |-+`[2*!x+!y]:z--?x>y?g(x-n,y,z):g(x,y-n,z):` `:`+`).join``

<input type=number min=0 oninput=o.textContent=f(this.value)><pre id=o>+

Parametrised version for ~~222~~ ~~216~~ ~~207~~ 199 bytes. Explanation: The output size is 9119 ASCII characters, including 46 newlines. (For the parametrised version, the output size is calculated including the trailing newline.) Each character is individually determined, firstly by checking whether a newline is due, otherwise by calling a function on the coordinates relative to the origin in the middle of the final diagram. The function recursively checks the point against the nearest crosses of each size to the point, and returns the appropriate character depending on whether the point is discovered to lie on the centre or axis of a cross.

fergusq · Accepted Answer · 2017-03-15 22:10:27Z

7

Röda, 284 280 238 234 bytes

{a=[1,-1]t=[]seq 1,95|t+=[" "]*95,_
f={|x,y,i,d|{s=[27,12,5,2,1][i]i++
a|{|j|{seq y,y+s*j|t[_][x]="|"f x,y+s*j,i,2-j}if[d!=2+j]}_
a|{|j|{seq x,x+s*j|t[y][_]="-"f x+s*j,y,i,3-j}if[d!=3+j]}_}if[i<5]
t[y][x]="+"}f 47,47,0,0
t|print _&""}

Try it online!

This is an anonymous function. I used newlines instead of semicolons so it is very nicely formatted!

The recursive function f creates the graph in a two-dimensional array t, which is then printed at the last line.

I didn't find a way to calculate 27,12,5,2,1 in few bytes, so they are hard-coded.

edited Mar 15, 2017 at 22:10

answered Mar 14, 2017 at 20:24

fergusq

5,1371 gold badge18 silver badges36 bronze badges

\$\begingroup\$ Is there no way to calculate powers of 2? \$\endgroup\$
– Neil
Commented Mar 14, 2017 at 22:33
\$\begingroup\$ @Neil A b_shiftl operator exists, but it's too long to be used in this program, I think. \$\endgroup\$
– fergusq
Commented Mar 15, 2017 at 18:17
\$\begingroup\$ Only thing I can think of is maybe base-3? Dunno how good Roda is at base conversion though... 10000110001200020001 -> 1168671727 doubt you can convert and split with less than 2 bytes though heh... \$\endgroup\$
– Magic Octopus Urn
Commented Mar 16, 2017 at 13:56

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Neil · Accepted Answer · 2017-06-18 11:04:18Z

3

Charcoal, 50 43 bytes

Ｆ³²⁴«Ｐ++↷ＡＥ…¹¦⁵∧¬﹪ιＸ³κ⁻Ｘ²⁺κ¹⁺κ²εＦ⁺ε⮌ε¿κ«+κ↶

Try it online! Link is to verbose version of code. I originally tried various reflections and rotations but they either didn't do what I want or in some cases were buggy. I then tried a nested loop approach but I've now switched to this iterative method which works by drawing a number of lines between each inner cross depending on how many powers of 3 the step number is divisible by. It can even be readily modified to accept a size parameter at a cost of only 4 bytes:

ＮβＦ×⁴Ｘ³β«Ｐ++↷ＡＥ…·¹β∧¬﹪ιＸ³κ⁻Ｘ²⁺κ¹⁺κ²εＦ⁺ε⮌ε¿κ«+κ↶

Edit: I've since worked out how to use RotateShutterOverlap to achieve this task, but annoyingly it takes me 44 bytes:

Ａ⁰ηＦ⁶«ＡηγＡ⁻⁺Ｘ²ιηιηＪη⁰Ｐ-γ+¿γ⟲ＳＯ²⁶⁻×²γ¹»‖⟲ＳＯ⁹⁵

If RotateShutterOverlap accepted a variable rotations integer, that would reduce it to 40 bytes:

Ａ⁰ηＦ⁶«Ａ∨η¹γＡ⁻⁺Ｘ²ιηιηＪη⁰Ｐ+γ+⟲ＳＯ⎇‹ι⁵Ｌβ²⁴⁶γ

As it is, using a rotations list parameter takes 45 bytes:

Ａ⁰ηＦ⁶«Ａ∨η¹γＡ⁻⁺Ｘ²ιηιηＪη⁰Ｐ+γ+⟲ＳＯ⟦⁶×²⁺¹⁼⁵ι⟧⁻×²γ¹

edited Jun 18, 2017 at 11:04

answered May 26, 2017 at 0:43

Neil

177k12 gold badges74 silver badges281 bronze badges

\$\begingroup\$ This feels like cheating to me. :P \$\endgroup\$
– hyperneutrino ♦
Commented May 26, 2017 at 1:08
\$\begingroup\$ @HyperNeutrino Slightly less hardcoded version: Try it online! Or is that not what you meant? \$\endgroup\$
– Neil
Commented May 26, 2017 at 20:04
\$\begingroup\$ :P I meant this is way too short and way too easy for Charcoal :P \$\endgroup\$
– hyperneutrino ♦
Commented May 26, 2017 at 20:05
\$\begingroup\$ @Neil :O This is amazing! I'm wondering if you could give an example of a buggy reflection/rotation so I can fix it \$\endgroup\$
– ASCII-only
Commented May 30, 2017 at 10:38
\$\begingroup\$ @ASCII-only In the case of a buggy reflection, I think only one of the diagonal reflections was working, but I can't remember which. I think the error was an undefined variable (probably too much copypasta). \$\endgroup\$
– Neil
Commented May 30, 2017 at 10:41

| Show 5 more comments

Magic Octopus Urn · Accepted Answer · 2017-03-14 19:07:47Z

05AB1E, 620 bytes

•1dOœ˜‘Av–Qs†ƒFã&äuÌÊ¹Ý2býádÙI’´Ëœ¼)Y»+™ß›[Vg“Ò¢Jù1no<V<*Ét*-¢&â-ßBÆ×090`11-øsµ–¶1VÛ==ü:¼÷ØûÍZ„æ¹=#ùÞV«¡fä&Îˆ'ëˆÝ=ä^‰¤?Êçù!ØèØr-3îÛ+êò‚û¢½°BéG¦U”Ü1žˆr6S‹“ŽKRK°A¹ª¿â9]}×u¬]ž„Îï›V¦Â¶4Ãï¢v£×é´Ü2Äžiqô>§17F*ÎañníÆ4]s8mÏ›HSÏ771í´‰d3´Þ|À]Uà{þñýqø’e„XÿF4–:Yl&uqžÍÒÿ¾u9¤jóHP‰çêoÒNŠX-°xpÒÿ*ejÏD0Ë+GnÊ-/§3ÜJÙˆƒÌ=ŒÒOX‰|O%wæ[n‹ã4)ôF+~´Ö{aÄ$(Þí¼”÷u–qÿBòfÂíÜìTó–xÝwû¾])<§O«\‚e°‡¾‹K…ZDPô;µ!ÃÂ²&Ô¼¨1gŠ—Ÿ¦©zW¢¾×4K±ÔÄ_ìûÄ‚3¶Ñ>‚bùn±œ×)ÙCâRöè£¶”ˆ1ßÑÍ®Ö±[ZéRïyÓxÓE¨cW˜{Ã’ùoE›¥ÚvA¨‹êÆýÑY½RÎ5´‘Ê™uåÄr"ãYð÷I!0¤)å‡ëž”>úèWò}é€@.ØñÈQ€ñ{Á„‘Ü’‰~Çñ=…|“ÚƒÄ¬cóÇkþÛÇ–š;{¡¦½ÕrÎé–àTz€Kì2à^|¢èˆÎxž“å$œ2ô»EidœþFrSS¥ÝÜ—X¡á~îþQ˜NÜGñ¥Q)aè•4B"1230"" +-|"‡48ôû€û»

Try it online!

All I did was cut the pattern into fourths, converted the symbols to base-4, compressed 1/4 of the pattern into base-214 and then flipped it over the lines of symmetry. I'm working on something smarter using the actual algorithm, but until I finish that this is what'll be here for me.

That's by far the largest 05AB1E answer I have seen. xD Usually it's close to 6.20 instead of 620 with answers in this language. ;) — Kevin Cruijssen, Commented Mar 15, 2017 at 8:25
@KevinCruijssen if it was asking for iteration 4 it would've been much-much smaller haha. Still working on the actual algorithm in 05AB1E... Bit harder than I thought. — Magic Octopus Urn, Commented Mar 16, 2017 at 13:51

RootTwo · Accepted Answer · 2017-03-15 16:49:28Z

2

Python 3, 264 bytes

def F(g,p,d,k):
 for c in'-|'[d.real!=0]*(2**k-k-1):g[p]=c;p+=d
 P(g,p,k-1)
def P(g,p,k):
 if'+'==g.setdefault(p,'+')and k:
  for d in[1,1j,-1,-1j]:F(g,p+d,d,k)
g={}
P(g,0j,5)
print('\n'.join(''.join(g.get(r+c*1j,' ')for c in range(-47,48))for r in range(-47,48)))

Uses a pair of mutually recursive functions. F draws the lines and P inserts the '+'s. Can be golfed more, but out of time for now.

answered Mar 15, 2017 at 16:49

RootTwo

2,1069 silver badges8 bronze badges

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Community · Accepted Answer · 2020-06-17 09:04:33Z

2

C, 236 bytes

char t[95][95],i=95;f(x,y,s,n,m){if(t[y][x]<33){m=~s+(1<<s);for(n=~m;n++<m;)t[y][x+n]='-',t[y+n][x]=n==0?'+':'|';if(s--)f(x+n,y,s),f(x-n,y,s),f(x,y+n,s),f(x,y-n,s);}}main(){memset(t,32,9025);f(47,47,5);while(i--)printf("%.95s\n",t[i]);}

Just building the character table recursively before displaying it.

Try it online!

Thanks @Neil for making me realize that the length of the branches follow an actual rule.

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Mar 22, 2017 at 19:52

dim

8,6181 gold badge14 silver badges21 bronze badges

\$\begingroup\$ 227 bytes \$\endgroup\$
– ceilingcat
Commented Jul 6, 2020 at 6:03

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emanresu A · Accepted Answer · 2021-04-29 10:58:17Z

Deadfish~, 11547 bytes

{iii}ii{cccc}ccccccc{i}ic{d}d{cccc}ccccccc{dd}ddc{ii}ii{cccc}cccccc{i}iccc{d}d{cccc}cccccc{dd}ddc{ii}ii{cccc}ccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{cccc}ccccc{dd}ddc{ii}ii{cccc}cccc{i}icciicddciicddcc{d}d{cccc}cccc{dd}ddc{ii}ii{cccc}ccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{cccc}ccccc{dd}ddc{ii}ii{cccc}cc{i}ic{d}dcccc{{i}d}iic{{d}i}ddcccc{i}ic{d}d{cccc}cc{dd}ddc{ii}ii{cccc}c{i}iccc{d}dccc{{i}d}iic{{d}i}ddccc{i}iccc{d}d{cccc}c{dd}ddc{ii}ii{cccc}{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{cccc}{dd}ddc{ii}ii{ccc}ccccccccc{i}icciicddciiccccddciiccccddciicddcc{d}d{ccc}ccccccccc{dd}ddc{ii}ii{cccc}{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{cccc}{dd}ddc{ii}ii{cccc}c{i}iccc{d}dccc{{i}d}iic{{d}i}ddccc{i}iccc{d}d{cccc}c{dd}ddc{ii}ii{cccc}cc{i}ic{d}dcccc{{i}d}iic{{d}i}ddcccc{i}ic{d}d{cccc}cc{dd}ddc{ii}ii{ccc}ccccc{i}ic{d}d{c}c{{i}d}iic{{d}i}dd{c}c{i}ic{d}d{ccc}ccccc{dd}ddc{ii}ii{ccc}cccc{i}iccc{d}d{c}{{i}d}iic{{d}i}dd{c}{i}iccc{d}d{ccc}cccc{dd}ddc{ii}ii{ccc}ccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dccccccccc{{i}d}iic{{d}i}ddccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{ccc}ccc{dd}ddc{ii}ii{ccc}cc{i}icciicddciicddcc{d}dcccccccc{{i}d}iic{{d}i}ddcccccccc{i}icciicddciicddcc{d}d{ccc}cc{dd}ddc{ii}ii{ccc}ccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dccccccccc{{i}d}iic{{d}i}ddccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{ccc}ccc{dd}ddc{ii}ii{ccc}{i}ic{d}dcccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddcccc{i}ic{d}d{ccc}{dd}ddc{ii}ii{cc}ccccccccc{i}iccc{d}dccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddccc{i}iccc{d}d{cc}ccccccccc{dd}ddc{ii}ii{cc}cccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{cc}cccccccc{dd}ddc{ii}ii{cc}ccccccc{i}icciicddciiccccddcii{c}cddcii{c}cddciiccccddciicddcc{d}d{cc}ccccccc{dd}ddc{ii}ii{cc}cccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{cc}cccccccc{dd}ddc{ii}ii{cc}ccccccccc{i}iccc{d}dccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddccc{i}iccc{d}d{cc}ccccccccc{dd}ddc{ii}ii{ccc}{i}ic{d}dcccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddcccc{i}ic{d}d{ccc}{dd}ddc{ii}ii{ccc}ccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dccccccccc{{i}d}iic{{d}i}ddccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{ccc}ccc{dd}ddc{ii}ii{ccc}cc{i}icciicddciicddcc{d}dcccccccc{{i}d}iic{{d}i}ddcccccccc{i}icciicddciicddcc{d}d{ccc}cc{dd}ddc{ii}ii{ccc}ccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dccccccccc{{i}d}iic{{d}i}ddccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{ccc}ccc{dd}ddc{ii}ii{cc}{i}ic{d}d{c}ccc{i}iccc{d}d{c}{{i}d}iic{{d}i}dd{c}{i}iccc{d}d{c}ccc{i}ic{d}d{cc}{dd}ddc{ii}ii{c}ccccccccc{i}iccc{d}d{c}ccc{i}ic{d}d{c}c{{i}d}iic{{d}i}dd{c}c{i}ic{d}d{c}ccc{i}iccc{d}d{c}ccccccccc{dd}ddc{ii}ii{c}cccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{cc}cccc{{i}d}iic{{d}i}dd{cc}cccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{c}cccccccc{dd}ddc{ii}ii{c}ccccccc{i}icciicddciicddcc{d}d{cc}ccc{{i}d}iic{{d}i}dd{cc}ccc{i}icciicddciicddcc{d}d{c}ccccccc{dd}ddc{ii}ii{c}cccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{cc}cccc{{i}d}iic{{d}i}dd{cc}cccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{c}cccccccc{dd}ddc{ii}ii{c}ccccc{i}ic{d}dcccc{{i}d}iic{{d}i}ddcccc{i}ic{d}d{cc}c{{i}d}iic{{d}i}dd{cc}c{i}ic{d}dcccc{{i}d}iic{{d}i}ddcccc{i}ic{d}d{c}ccccc{dd}ddc{ii}ii{c}cccc{i}iccc{d}dccc{{i}d}iic{{d}i}ddccc{i}iccc{d}d{cc}{{i}d}iic{{d}i}dd{cc}{i}iccc{d}dccc{{i}d}iic{{d}i}ddccc{i}iccc{d}d{c}cccc{dd}ddc{ii}ii{c}ccc{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{c}ccccccccc{{i}d}iic{{d}i}dd{c}ccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{c}ccc{dd}ddc{ii}ii{c}cc{i}icciicddciiccccddciiccccddciicddcc{d}d{c}cccccccc{{i}d}iic{{d}i}dd{c}cccccccc{i}icciicddciiccccddciiccccddciicddcc{d}d{c}cc{dd}ddc{ii}ii{c}ccc{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{c}ccccccccc{{i}d}iic{{d}i}dd{c}ccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{c}ccc{dd}ddc{ii}ii{c}cccc{i}iccc{d}dccc{{i}d}iic{{d}i}ddccc{i}iccc{d}d{cc}{{i}d}iic{{d}i}dd{cc}{i}iccc{d}dccc{{i}d}iic{{d}i}ddccc{i}iccc{d}d{c}cccc{dd}ddc{ii}ii{c}ccccc{i}ic{d}dcccc{{i}d}iic{{d}i}ddcccc{i}ic{d}d{cc}c{{i}d}iic{{d}i}dd{cc}c{i}ic{d}dcccc{{i}d}iic{{d}i}ddcccc{i}ic{d}d{c}ccccc{dd}ddc{ii}iicccccccc{i}ic{d}d{c}c{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{c}c{i}ic{d}dcccccccc{dd}ddc{ii}iiccccccc{i}iccc{d}d{c}{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{c}{i}iccc{d}dccccccc{dd}ddc{ii}iicccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dccccccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}ddccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dcccccc{dd}ddc{ii}iiccccc{i}icciicddciicddcc{d}dcccccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}ddcccccccc{i}icciicddciicddcc{d}dccccc{dd}ddc{ii}iicccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dccccccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}ddccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dcccccc{dd}ddc{ii}iiccc{i}ic{d}dcccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddcccc{i}ic{d}dccc{dd}ddc{ii}iicc{i}iccc{d}dccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddccc{i}iccc{d}dcc{dd}ddc{ii}iic{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}dc{dd}ddc{iii}iiicciicddciiccccddcii{c}cddcii{cc}ccccccddcii{cc}ccccccddcii{c}cddciiccccddciicddcc{ddd}dddc{ii}iic{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}dc{dd}ddc{ii}iicc{i}iccc{d}dccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddccc{i}iccc{d}dcc{dd}ddc{ii}iiccc{i}ic{d}dcccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddcccc{i}ic{d}dccc{dd}ddc{ii}iicccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dccccccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}ddccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dcccccc{dd}ddc{ii}iiccccc{i}icciicddciicddcc{d}dcccccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}ddcccccccc{i}icciicddciicddcc{d}dccccc{dd}ddc{ii}iicccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dccccccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}ddccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dcccccc{dd}ddc{ii}iiccccccc{i}iccc{d}d{c}{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{c}{i}iccc{d}dccccccc{dd}ddc{ii}iicccccccc{i}ic{d}d{c}c{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{cc}cccccc{{i}d}iic{{d}i}dd{c}c{i}ic{d}dcccccccc{dd}ddc{ii}ii{c}ccccc{i}ic{d}dcccc{{i}d}iic{{d}i}ddcccc{i}ic{d}d{cc}c{{i}d}iic{{d}i}dd{cc}c{i}ic{d}dcccc{{i}d}iic{{d}i}ddcccc{i}ic{d}d{c}ccccc{dd}ddc{ii}ii{c}cccc{i}iccc{d}dccc{{i}d}iic{{d}i}ddccc{i}iccc{d}d{cc}{{i}d}iic{{d}i}dd{cc}{i}iccc{d}dccc{{i}d}iic{{d}i}ddccc{i}iccc{d}d{c}cccc{dd}ddc{ii}ii{c}ccc{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{c}ccccccccc{{i}d}iic{{d}i}dd{c}ccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{c}ccc{dd}ddc{ii}ii{c}cc{i}icciicddciiccccddciiccccddciicddcc{d}d{c}cccccccc{{i}d}iic{{d}i}dd{c}cccccccc{i}icciicddciiccccddciiccccddciicddcc{d}d{c}cc{dd}ddc{ii}ii{c}ccc{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{c}ccccccccc{{i}d}iic{{d}i}dd{c}ccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{c}ccc{dd}ddc{ii}ii{c}cccc{i}iccc{d}dccc{{i}d}iic{{d}i}ddccc{i}iccc{d}d{cc}{{i}d}iic{{d}i}dd{cc}{i}iccc{d}dccc{{i}d}iic{{d}i}ddccc{i}iccc{d}d{c}cccc{dd}ddc{ii}ii{c}ccccc{i}ic{d}dcccc{{i}d}iic{{d}i}ddcccc{i}ic{d}d{cc}c{{i}d}iic{{d}i}dd{cc}c{i}ic{d}dcccc{{i}d}iic{{d}i}ddcccc{i}ic{d}d{c}ccccc{dd}ddc{ii}ii{c}cccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{cc}cccc{{i}d}iic{{d}i}dd{cc}cccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{c}cccccccc{dd}ddc{ii}ii{c}ccccccc{i}icciicddciicddcc{d}d{cc}ccc{{i}d}iic{{d}i}dd{cc}ccc{i}icciicddciicddcc{d}d{c}ccccccc{dd}ddc{ii}ii{c}cccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{cc}cccc{{i}d}iic{{d}i}dd{cc}cccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{c}cccccccc{dd}ddc{ii}ii{c}ccccccccc{i}iccc{d}d{c}ccc{i}ic{d}d{c}c{{i}d}iic{{d}i}dd{c}c{i}ic{d}d{c}ccc{i}iccc{d}d{c}ccccccccc{dd}ddc{ii}ii{cc}{i}ic{d}d{c}ccc{i}iccc{d}d{c}{{i}d}iic{{d}i}dd{c}{i}iccc{d}d{c}ccc{i}ic{d}d{cc}{dd}ddc{ii}ii{ccc}ccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dccccccccc{{i}d}iic{{d}i}ddccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{ccc}ccc{dd}ddc{ii}ii{ccc}cc{i}icciicddciicddcc{d}dcccccccc{{i}d}iic{{d}i}ddcccccccc{i}icciicddciicddcc{d}d{ccc}cc{dd}ddc{ii}ii{ccc}ccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dccccccccc{{i}d}iic{{d}i}ddccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{ccc}ccc{dd}ddc{ii}ii{ccc}{i}ic{d}dcccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddcccc{i}ic{d}d{ccc}{dd}ddc{ii}ii{cc}ccccccccc{i}iccc{d}dccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddccc{i}iccc{d}d{cc}ccccccccc{dd}ddc{ii}ii{cc}cccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{cc}cccccccc{dd}ddc{ii}ii{cc}ccccccc{i}icciicddciiccccddcii{c}cddcii{c}cddciiccccddciicddcc{d}d{cc}ccccccc{dd}ddc{ii}ii{cc}cccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{cc}cccccccc{dd}ddc{ii}ii{cc}ccccccccc{i}iccc{d}dccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddccc{i}iccc{d}d{cc}ccccccccc{dd}ddc{ii}ii{ccc}{i}ic{d}dcccc{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}dd{c}c{{i}d}iic{{d}i}ddcccc{i}ic{d}d{ccc}{dd}ddc{ii}ii{ccc}ccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dccccccccc{{i}d}iic{{d}i}ddccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{ccc}ccc{dd}ddc{ii}ii{ccc}cc{i}icciicddciicddcc{d}dcccccccc{{i}d}iic{{d}i}ddcccccccc{i}icciicddciicddcc{d}d{ccc}cc{dd}ddc{ii}ii{ccc}ccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}dccccccccc{{i}d}iic{{d}i}ddccccccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{ccc}ccc{dd}ddc{ii}ii{ccc}cccc{i}iccc{d}d{c}{{i}d}iic{{d}i}dd{c}{i}iccc{d}d{ccc}cccc{dd}ddc{ii}ii{ccc}ccccc{i}ic{d}d{c}c{{i}d}iic{{d}i}dd{c}c{i}ic{d}d{ccc}ccccc{dd}ddc{ii}ii{cccc}cc{i}ic{d}dcccc{{i}d}iic{{d}i}ddcccc{i}ic{d}d{cccc}cc{dd}ddc{ii}ii{cccc}c{i}iccc{d}dccc{{i}d}iic{{d}i}ddccc{i}iccc{d}d{cccc}c{dd}ddc{ii}ii{cccc}{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{cccc}{dd}ddc{ii}ii{ccc}ccccccccc{i}icciicddciiccccddciiccccddciicddcc{d}d{ccc}ccccccccc{dd}ddc{ii}ii{cccc}{i}ic{d}dc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddcccc{{i}d}iic{{d}i}ddc{i}ic{d}d{cccc}{dd}ddc{ii}ii{cccc}c{i}iccc{d}dccc{{i}d}iic{{d}i}ddccc{i}iccc{d}d{cccc}c{dd}ddc{ii}ii{cccc}cc{i}ic{d}dcccc{{i}d}iic{{d}i}ddcccc{i}ic{d}d{cccc}cc{dd}ddc{ii}ii{cccc}ccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{cccc}ccccc{dd}ddc{ii}ii{cccc}cccc{i}icciicddciicddcc{d}d{cccc}cccc{dd}ddc{ii}ii{cccc}ccccc{i}ic{d}dc{{i}d}iic{{d}i}ddc{i}ic{d}d{cccc}ccccc{dd}ddc{ii}ii{cccc}cccccc{i}iccc{d}d{cccc}cccccc{dd}ddc{ii}ii{cccc}ccccccc{i}ic{d}d{cccc}ccccccc

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ASCII Cayley Graph

Input

Output

MD5 Hashes

Rules

7 Answers 7

JavaScript (ES6), 204 195 188 180 bytes

Röda, 284 280 238 234 bytes

Charcoal, 50 43 bytes

05AB1E, 620 bytes

Python 3, 264 bytes

C, 236 bytes

Deadfish~, 11547 bytes

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ASCII Cayley Graph

Input

Output

MD5 Hashes

Rules

7 Answers 7

JavaScript (ES6), 204 195 188 180 bytes

Röda, 284 280 238 234 bytes

Charcoal, 50 43 bytes

05AB1E, 620 bytes

Python 3, 264 bytes

C, 236 bytes

Deadfish~, 11547 bytes

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