Almost equivalent to Project Euler's first question:
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
Given##Challenge:
Given a positive integer N
and a set of at least one positive integer A
, output the sum of all positive integers less than N
that are multiples of at least one member of A
.
For example, for the Project Euler case, the input would be:
1000
3
5
##Test cases:
Input : 50, 2[2]
Output: 600
Input : 10, 3[3, 55]
Output: 23
Input : 28, 4[4, 22]
Output: 182
Input : 19, 7[7, 55]
Output: 51
Input : 50, 2[2, 3, 55]
Output: 857