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A repost of this challenge. Meta discussion. Sandbox post. Body of the question similar to the original

Robber's challenge

This cops and robbers is now (08/03/2018) closed to further competing cop entries, as robbers may no longer be competing to crack answers, but feel free to post new answers.

The Cops challenge was won by Dennis with his brilliant 6 byte Sesos answer

The Robbers challenge was won by totallyhuman, with an astounding 30 cracks!

The Cops' Challenge

To compete as a cop:

  1. Choose a programming language. A valid programming language is one which meets all three of these criteria:

  2. Write a full program that outputs the numbers from 1 to 100, inclusive, in ascending order. You can output as decimal integers, as bytecode values (! to represent 33, for instance), or as unary digits (1111 for 4, e.g)1. If using unary, you should use any consistent character for digits, and a different, consistent character as a delimiter. If using integers, you should output with a constant non-digit delimiter between each number. You may also output with leading and trailing characters (such as []) but please be sensible (don't output a thousand bytes of rubbish either side of the count for instance). You must specify your output format in your answer.

    You must not assume a REPL environment or existing boilerplate code. Flags may be used, but you must reveal what flags are used in your answer. The program must be in the form of one or more source files (to rule out quirky languages like Folders) and must fit into your answer in full (so it must not be longer than 65,536 characters) - this shouldn't be an issue for any serious submission.

    If your code contains bytes outside of printable ASCII + newline, please include a hex dump to make sure your code is actually testable.

    The program must terminate within 5 minutes on a typical desktop PC.

That's it. However, as with everything, there is a catch. You should aim to obfuscate your program as much as possible, as the Robbers' task is to guess the language you used. You should also aim to make sure that your program only works in the intended language (although this is likely to be less of a problem than the Foo cracks in the original challenge). The output format must be the same as your intended solution in order to constitute a valid crack.

Once 7 days have passed without anyone discovering any language where your program is a valid crack, you may reveal the language and mark it as safe. Please note, your submission can still be cracked until you reveal the language.

You must not under any circumstances edit the source code of your submission once posted (as this may invalidate a robber's active attempts at cracking your answer). So make sure that you golf it as well as you can (or dare) before posting. If you realise that your answer does not work after posting it, simply delete your answer and post a fixed version if you want to.

The shortest safe submission in bytes wins!

1: If you wish to output in a different way, please ask in the comments

The Stack Snippet

You can use this stack snippet to browse the answers more easily:

answersSafe=[];answersCracked=[];answersUncracked=[];answerPage=1;robberTodo=[];userNames={};robberMap={};robberStats={};robberTimes={};function template($element,data){var $clone=$element.clone().removeClass('template');var html=$clone.html();for(var key in data){html=html.replace('{'+key+'}',data[key])}$clone.html(html);$element.after($clone)}function hideEmpty(){$('tbody').each(function(){if($(this).find('tr:not(.template):has(td)').length==0){$(this).find('tr:not(.empty):has(th)').addClass('inactive');$(this).find('tr.empty').removeClass('inactive')}})}function formatError(obj,reason){template($('.warn.template'),{id:obj.cop_id,cop:obj.cop_user,reason:reason})}function showAnswers(category,selector,sorter){sorter(category);$('#'+selector).find('tr:not(.template):has(td)').remove();$.each(category,function(i,answer){template($('#'+selector+' .template'),answer)});$('code:has(br)').addClass('clickable').click(function(){$(this).toggleClass('full')});updateCountdowns()}function getAnswers(){$.ajax({url:"https://api.stackexchange.com/2.2/questions/155018/answers?pagesize=100&order=desc&sort=creation&site=codegolf&filter=!*LUzJZNOIUpZsWsZBLe&page="+(answerPage++),method:"get",dataType:"jsonp"}).then(function(data){$.each(data.items,function(i,answer){var obj={cop_id:answer.answer_id,cop_user:answer.owner.display_name,cop_time:answer.creation_date,safe_on:answer.creation_date+604800};var $e=$('<div/>').html(answer.body);var $headers=$e.find(':header');if($headers.length==0){return formatError(obj,"no header")}var header=$headers.first().html();var $code=$e.find('pre code');if($code.length==0){return formatError(obj,"no code")}obj.code=$code.first().html().replace(/\n/g,'<br/>');if(obj.code.endsWith('<br/>')){obj.code=obj.code.slice(0,-5)}var bm=/(\d+)\s+bytes/.exec(header);if(bm==null){return formatError(obj,"no bytecount")}obj.size=parseInt(bm[1]);if(obj.size==NaN){return formatError(obj,"bytecount is NaN: 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i=0;i<graphData.length;i+=1){graphColors.push(['#b58900','#cb4b16','#dc322f','#d33682','#6c71c4','#268bd2','#2aa198','#859900'][i%8])}$('#robber-stats').attr('width',600);$('#robber-stats').attr('height',24*graphData.length+66);$('#answer-stats').attr('width',600);$('#answer-stats').attr('height',400);Chart.defaults.global.defaultFontColor='#839496';new Chart($('#robber-stats'),{type:'horizontalBar',data:{labels:graphLabels,datasets:[{data:graphValues,backgroundColor:graphColors}]},options:{responsive:false,legend:false,tooltips:false,layout:{padding:{right:40}},title:{display:true,text:'Number of answers cracked per robber',fontSize:18},scales:{yAxes:[{gridLines:{display:false}}],xAxes:[{gridLines:{display:false},ticks:{beginAtZero:true}}]},plugins:{datalabels:{anchor:'end',align:'end'}}}});new Chart($('#answer-stats'),{type:'pie',data:{labels:['Uncracked','Cracked','Safe'],datasets:[{data:[answersUncracked.length,answersCracked.length,answersSafe.length],backgroundColor:['#2aa198','#dc322f','#859900'],borderColor:'#002b36'}]},options:{responsive:false,tooltips:{backgroundColor:'#073642',displayColors:false},title:{display:true,text:'Number of answers in each category',fontSize:18},plugins:{datalabels:false}}});updateCountdowns();setInterval(updateCountdowns,1000);$('#loading').hide()}else{$.ajax({url:"https://api.stackexchange.com/2.2/answers/"+robberTodo.slice(0,100).join(';')+"?site=codegolf&filter=!*RB.h_b*K*dQTllFUdy",method:"get",dataType:"jsonp"}).then(function(data){$.each(data.items,function(i,robber){robberTodo=robberTodo.filter(function(e){return e!==robber.answer_id});robberMap[robber.answer_id]=robber.owner.user_id;robberTimes[robber.answer_id]=robber.creation_date;userNames[robber.owner.user_id]=robber.owner.display_name;if(robber.owner.user_id in 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M80.438,13.03c0,3.59-1.353,6.656-4.072,9.177c-2.712,2.53-5.98,3.796-9.803,3.796c-3.835,0-7.111-1.266-9.854-3.796c-2.738-2.522-4.11-5.587-4.11-9.177c0-3.583,1.372-6.654,4.11-9.207C59.447,1.274,62.729,0,66.563,0c3.822,0,7.091,1.277,9.803,3.823C79.087,6.376,80.438,9.448,80.438,13.03z"/></svg> Click the "Full page" link in the top right for vastly superior experience</div><div class="warn template">&#9888; <a href="https://codegolf.stackexchange.com/a/{id}">This answer</a> by {cop} is not formatted correctly ({reason}).</div><table><thead><tr><th colspan="5"><svg xmlns="http://www.w3.org/2000/svg" width="14" height="14" viewBox="0 0 9 9"><path class="right-arrow" d="M 0 0 L 0 9 L 9 4.5 Z"/><path class="down-arrow" d="M 0 0 L 9 0 L 4.5 9 Z"/></svg> Uncracked answers</th></tr></thead><tbody id="uncracked"><tr><th colspan="3" onclick="showAnswers(answersUncracked, 'uncracked', sortByCop)" class="clickable">Posted by</th><th onclick="showAnswers(answersUncracked, 'uncracked', sortBySize)" class="clickable">Size</th><th onclick="showAnswers(answersUncracked, 'uncracked', sortByTime)" class="clickable">Safe in</th><th>Code</th></tr><tr class="empty inactive"><th colspan="5">There are no uncracked answers</th></tr><tr class="template"><td colspan="3"><a href="https://codegolf.stackexchange.com/a/{cop_id}">{cop_user}</a></td><td>{size} bytes</td><td><span class="countdown" data-target="{safe_on}"></span></td><td><code>{code}</code></td></tr></tbody><thead><tr><th colspan="5"><svg xmlns="http://www.w3.org/2000/svg" width="14" height="14" viewBox="0 0 9 9"><path class="right-arrow" d="M 0 0 L 0 9 L 9 4.5 Z"/><path class="down-arrow" d="M 0 0 L 9 0 L 4.5 9 Z"/></svg> Cracked answers</th></tr></thead><tbody id="cracked"><tr><th onclick="showAnswers(answersCracked, 'cracked', sortByCop)" class="clickable">Posted by</th><th onclick="showAnswers(answersCracked, 'cracked', sortByRobber)" class="clickable">Cracked by</th><th onclick="showAnswers(answersCracked, 'cracked', sortByLanguage)" class="clickable">Language</th><th onclick="showAnswers(answersCracked, 'cracked', sortBySize)" class="clickable">Size</th><th onclick="showAnswers(answersCracked, 'cracked', sortByLiveTime)" class="clickable">Cracked after</th><th>Code</th></tr><tr class="empty inactive"><th colspan="5">There are no cracked answers</th></tr><tr class="template"><td><a href="https://codegolf.stackexchange.com/a/{cop_id}">{cop_user}</a></td><td><a href="https://codegolf.stackexchange.com/a/{robber_id}">{robber_user}</a></td><td>{language}</td><td>{size} bytes</td><td>{cracked_after_str}</td><td><code>{code}</code></td></tr></tbody><thead><tr><th colspan="5"><svg xmlns="http://www.w3.org/2000/svg" width="14" height="14" viewBox="0 0 9 9"><path class="right-arrow" d="M 0 0 L 0 9 L 9 4.5 Z"/><path class="down-arrow" d="M 0 0 L 9 0 L 4.5 9 Z"/></svg> Safe answers</th></tr></thead><tbody id="safe"><tr><th colspan="2" onclick="showAnswers(answersSafe, 'safe', sortByCop)" class="clickable">Posted by</th><th onclick="showAnswers(answersSafe, 'safe', sortByLanguage)" class="clickable">Language</th><th colspan="2" onclick="showAnswers(answersSafe, 'safe', sortBySize)" class="clickable">Size</th><th>Code</th></tr><tr class="empty inactive"><th colspan="5">There are no safe answers</th></tr><tr class="template"><td colspan="2"><a href="https://codegolf.stackexchange.com/a/{cop_id}">{cop_user}</a></td><td>{language}</td><td colspan="2">{size} bytes</td><td><code>{code}</code></td></tr></tbody></table><div id="stats-header"><svg xmlns="http://www.w3.org/2000/svg" width="14" height="14" viewBox="0 0 9 9"><path class="right-arrow" d="M 0 0 L 0 9 L 9 4.5 Z"/><path class="down-arrow" d="M 0 0 L 9 0 L 4.5 9 Z"/></svg> Statistics</div><div id="stats"><div><canvas id="robber-stats"/></div><div><canvas id="answer-stats"/></div></div><small>Snippet made by <a href="https://codegolf.stackexchange.com/u/55934/" target="_blank">NieDzejkob</a>, licensed as <a href="https://creativecommons.org/licenses/by-sa/3.0/" target="_blank">CC 3.0 BY-SA</a>. "Info" icon made by <a href="https://www.flaticon.com/authors/chanut" target="_blank">Chanut</a> from <a href="https://www.flaticon.com/" target="_blank">Flaticon</a>, licensed as <a href="http://creativecommons.org/licenses/by/3.0/" target="_blank">CC 3.0 BY</a>. "Arrow" icons made by <a href="https://codegolf.stackexchange.com/u/12012/" target="_blank">Dennis</a> for <a href="https://tio.run/" target="_blank">Try It Online</a>, licensed as <a href="https://github.com/TryItOnline/tryitonline/blob/master/LICENSE" target="_blank">MIT</a>. Some code shamelessly copy-pasted from <a href="https://stackoverflow.com/a/9609450">this answer</a> on Stack Overflow by <a href="https://stackoverflow.com/u/24950">Robert K</a>, licensed as <a href="https://creativecommons.org/licenses/by-sa/3.0/">CC 3.0 BY-SA</a>. This snippet utilises <a href="http://jquery.com/">jQuery</a> (<a href="https://github.com/jquery/jquery/blob/master/LICENSE.txt">MIT</a>), <a href="http://www.chartjs.org/">chart.js</a> (<a href="https://github.com/chartjs/Chart.js/blob/master/LICENSE.md">MIT</a>) and <a href="https://github.com/chartjs/chartjs-plugin-datalabels/">chartjs-plugin-datalabels</a> (<a href="https://github.com/chartjs/chartjs-plugin-datalabels/blob/master/LICENSE.md">MIT</a>). Color scheme: <a href="http://ethanschoonover.com/solarized">Solarized by Ethan Schoonover</a> (<a href="https://github.com/altercation/solarized/blob/master/LICENSE">MIT</a>).</small>

Formatting

(Feel free to skip this section if you're not planning to participate as a cop)

This is required for new cop answers to make it possible for the snippet above to parse them.

  • New answers should include a header like this:

    # ???, [N] bytes
    

    where [N] is the size of your code in bytes and ??? should appear literally.

  • If the answer is not cracked for 7 days and you want to make your answer safe by revealing the language, simply replace the ??? and add safe to the end, e.g.

    # Ruby, [N] bytes, safe
    

    Feel free to have the language name link to a relevant website like an esolangs page or a GitHub repository. The link will then be displayed in the leaderboard.

  • If another user successfully cracked your submission, please also add the language, along with a notice like

    # Ruby, [N] bytes, [cracked](crack-link) by [user]
    

    where [user] is the name of the user who submitted the first valid crack, and crack-link is a link to the corresponding answer in the Robbers' thread. Please use the short link format you get from the "share" button. Feel free to make the user name a link to their profile page.

    If the language used in the crack is different from the one you intended, your answer is still cracked, and you shall follow this format. However, you can mention in the answer that you intended it to be something else. It's your choice on whether you want to reveal the intended answer, or if you want to let Robbers have more fun.

Good luck Cops!

\$\endgroup\$
14
  • 15
    \$\begingroup\$ How not to compete in this challenge. \$\endgroup\$ Feb 8, 2018 at 17:55
  • 2
    \$\begingroup\$ Note that if you're using a language with an interpreter on TIO, all someone has to do to crack your submission is try every language on TIO. \$\endgroup\$
    – mbomb007
    Feb 8, 2018 at 23:08
  • 2
    \$\begingroup\$ @mbomb007 Take a look at this comment. Aside from requesting that Robbers don't brute-force, there is nothing more that we can do to prevent this behaviour unfortunately. However, I invite anyone to downvote Robbers using scripts to brute-force submissions as it contradicts the spirit of the challenge. \$\endgroup\$ Feb 8, 2018 at 23:16
  • 2
    \$\begingroup\$ @NieDzejkob I'd say that the compiler has to be on Wikipedia/Rosetta Code/Esolangs or be on TIO. \$\endgroup\$ Feb 13, 2018 at 15:45
  • 2
    \$\begingroup\$ @cairdcoinheringaahing Both answers that inspired me to ask that question are a gray area: This Beatnik answer only works in some interpreters, and none of them have their own page. However, a working interpreter is linked on the esolangs page. In the case of this, the language is installed on TIO, but it's not listed on the language list. These answers have already been cracked, but I think that the rules should be modified to be unambigous in the future. \$\endgroup\$
    – Maya
    Feb 13, 2018 at 16:24

211 Answers 211

1
4 5 6
7
8
1
\$\begingroup\$

MarioLANG, 2022 bytes, Cracked

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# 2022 bytes for 2022!
\$\endgroup\$
1
1
\$\begingroup\$

Bubblegum, 143 bytes, cracked by emanresu A

Hexdump:

00000000: e001 2200 875d 0018 8802 a848 1ea2 618e  .."..].....H..a.
00000010: ba58 e8d8 b9db 6604 e1a3 f1a8 dbcc 8053  .X....f........S
00000020: 0835 e444 539b a0f4 0369 0d1d a219 f0b5  .5.DS....i......
00000030: 2178 ae46 89df b43b 9f4a 6e6d dcde 8ec4  !x.F...;.Jnm....
00000040: e2fe 95dc e75e dbfb f737 1dc2 aa77 8c3c  .....^...7...w.<
00000050: 04d4 fae0 1991 c8ba 7a0a ed70 4a78 76ab  ........z..pJxv.
00000060: 7cd9 839d 35f6 2730 8893 ecd3 89b1 350b  |...5.'0......5.
00000070: 7425 b77c 630d 0b2e 73f3 4fb3 93d8 ba29  t%.|c...s.O....)
00000080: 8e07 d6f4 7549 fadc 41a5 3d36 8a00 00    ....uI..A.=6...

Decompress the hexdump online!

Language is on TIO.

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3
  • \$\begingroup\$ Took one look at this and... cracked \$\endgroup\$
    – emanresu A
    May 17, 2022 at 21:12
  • \$\begingroup\$ @emanresuA lmao I honestly didn't think it would be that easy \$\endgroup\$
    – naffetS
    May 17, 2022 at 21:13
  • \$\begingroup\$ The hexdump was a dead giveaway \$\endgroup\$
    – emanresu A
    May 17, 2022 at 21:14
1
\$\begingroup\$

Banana Golf, 34 Bytes, safe

X [print(_) for _ in range(1,101)]
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4
  • \$\begingroup\$ Is this Python? \$\endgroup\$
    – noodle man
    Jul 2, 2023 at 14:32
  • \$\begingroup\$ @noodleman no, this is using the “execute python” instruction of the language. \$\endgroup\$ Jul 3, 2023 at 6:54
  • \$\begingroup\$ Is this programming language listed on Try It Online, esolangs.org, Rosetta Code, or have an English Wikipedia article? (these are the requirements for a programming language to be used in this challenge) \$\endgroup\$
    – noodle man
    Jul 3, 2023 at 14:06
  • \$\begingroup\$ @noodleman yes, it is. \$\endgroup\$ Jul 5, 2023 at 16:45
1
\$\begingroup\$

!@#$%^&*()_+, 70 bytes, safe

>1+v< /  >    \
(!_++)t(!_++^!#
@!d_+)        /
v""<> /
> ^>^
~~<^\=~~

Try it online!

How is this safe?

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0
\$\begingroup\$

Huginn, 54 + 9 (--no-argv) = 63 bytes, cracked by Dennis

main(){i=1;while(i<101){print("{} ".format(i));i+=1;}}

Outputs each number in decimal. These are separated by a space.

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4
  • \$\begingroup\$ If anyone cracks it, feel free to edit in, I'll most likely be sleeping :P \$\endgroup\$
    – Mr. Xcoder
    Feb 6, 2018 at 22:29
  • \$\begingroup\$ Cracked. The --no-argv is a dead giveaway. \$\endgroup\$
    – Dennis
    Feb 7, 2018 at 0:14
  • \$\begingroup\$ @Dennis Actually it didn't even need to be mentioned at all in the post, per the new consensus. ;-) \$\endgroup\$ Feb 7, 2018 at 14:16
  • 3
    \$\begingroup\$ @EriktheOutgolfer Flags may be used, but you must reveal what flags are used in your answer. \$\endgroup\$
    – Dennis
    Feb 7, 2018 at 14:20
0
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Symbolic Python, 242 bytes, cracked by user202729

_=+([]==[]),
__('_+=-~_[~([]>[])],;'*-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~-~([]==[]))
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3
  • \$\begingroup\$ Is the count of -~ correct? \$\endgroup\$
    – tsh
    Feb 8, 2018 at 3:15
  • \$\begingroup\$ @tsh yep ------ \$\endgroup\$
    – MD XF
    Feb 8, 2018 at 4:03
  • \$\begingroup\$ Cracked \$\endgroup\$
    – DELETE_ME
    Feb 8, 2018 at 4:11
0
\$\begingroup\$

Milky Way, 11 bytes, cracked by ovs

print-ZL¡;

Try it online!

Have fun!

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1
  • 1
    \$\begingroup\$ cracked \$\endgroup\$
    – ovs
    Feb 6, 2018 at 21:20
0
\$\begingroup\$

Pain-Flak, 241 bytes, cracked by H.PWiz

Pastebin

‮>‭<)‮‭‮))‮‭)‮)‮‭)‮)‭‮(‮)‭(‮‮)‭(‮‮(‭}{‭(‮}‮‭{(‭}‮{‭‮)(‭(‮}‮‭{(‮‭}‮{‭(‮}‭‮))‭}‮‮{‮‭(]‭)‮‮(‭‮[‮(‮‮‮‭{)‭(}‭{‮}‭‮><‭{‮‮

Everyone knows what I program in??

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4
  • \$\begingroup\$ Cracked. It looks like your Pastebin has a lot of unprintables, was this intened? \$\endgroup\$
    – H.PWiz
    Feb 9, 2018 at 1:01
  • \$\begingroup\$ @H.PWiz AFAICT Christopher didn't want people to know he used the RLM in his answer, nor did he want to fix it using an LRM, so he outsourced it to pastebin. (Just a guess tho) \$\endgroup\$ Feb 9, 2018 at 1:03
  • \$\begingroup\$ @ConorO'Brien no if it has unprintables you have to pastebin \$\endgroup\$
    – user63187
    Feb 9, 2018 at 1:08
  • \$\begingroup\$ @Christopher right but that doesn't stop you from posting code :P \$\endgroup\$ Feb 9, 2018 at 1:08
0
\$\begingroup\$

Prelude, 38 bytes, cracked by jimmy23013

91+ v+   vv++ (1-v!)
   ^  ^^+    0 1+

Output is in raw chars 0x01-0x64.

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2
  • \$\begingroup\$ Cracked. It's Prelude. \$\endgroup\$
    – jimmy23013
    Feb 9, 2018 at 12:18
  • \$\begingroup\$ @jimmy23013 yeah this wasn't hard at all \$\endgroup\$ Feb 9, 2018 at 12:23
0
\$\begingroup\$

JavaScript, 37 bytes, cracked by Steadybox

n=1;while(n<101){console.log(n);n++;}

Pretty easy... but... ehhh...

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1
0
\$\begingroup\$

JavaScript/JSFuck, 38541 bytes, cracked by Steadybox

If this remains uncracked for seven days, I am seriously going to cry.

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Here's a pastebin link, for easier copy-and-pasting. (And no, I did not write all of the code manually.)

The program outputs normally by printing to the language's equivalent of STDOUT

This program, when un-JSFuck-ified, turns into (function(){for(var i = 0; i < 101; i++){console.log(i)}})(). Not too crazy looking now, is it?

I could have made it worse/longer by making it un-runnable from the console (yes, that is possible, but it could make it extremely clear what the language is), and adding some extra awesomeness to it.

\$\endgroup\$
2
  • \$\begingroup\$ Not exactly aiming to win, just want to see if anyone can crack it :) \$\endgroup\$
    – iPhoenix
    Feb 9, 2018 at 22:40
  • 1
    \$\begingroup\$ Cracked \$\endgroup\$
    – Steadybox
    Feb 9, 2018 at 22:46
0
\$\begingroup\$

Mathematica, 301 bytes, cracked by Silvio Mayolo

Print["1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 "]
\$\endgroup\$
7
  • \$\begingroup\$ Cracked. \$\endgroup\$ Feb 9, 2018 at 20:46
  • 2
    \$\begingroup\$ This also works in Foo. I was just about to post a crack. \$\endgroup\$
    – MD XF
    Feb 9, 2018 at 20:46
  • \$\begingroup\$ @totallyhuman actually intended to be Mathics, didn't realize mathematia had a print[] function \$\endgroup\$
    – qqq
    Feb 9, 2018 at 20:48
  • \$\begingroup\$ I had to verify it myself; never personally had cause to do a straight print in Mathematica, but alas it does. \$\endgroup\$ Feb 9, 2018 at 20:49
  • 8
    \$\begingroup\$ @MDXF And we thought there wouldn't be any Foo polyglots this time around! \$\endgroup\$
    – DLosc
    Feb 9, 2018 at 21:09
0
\$\begingroup\$

Super Stack, 47 bytes, cracked by totallyhuman

1 1 if pop dup output 1 add dup 101 swap sub fi

Let's see if anyone knows this one!

\$\endgroup\$
1
0
\$\begingroup\$

Pari/GP, 33 bytes, cracked by Mr. Xcoder

print(Vecrev(((x^101-1)/(x-1))'))

A very easy one. I don't expect it to last long.

\$\endgroup\$
3
  • 1
    \$\begingroup\$ This is Pari/GP. \$\endgroup\$
    – Mr. Xcoder
    Feb 11, 2018 at 8:08
  • \$\begingroup\$ OK. 27 minutes. \$\endgroup\$
    – alephalpha
    Feb 11, 2018 at 8:11
  • 1
    \$\begingroup\$ It lasted 27 minutes because I only saw this 25 minutes ago :P \$\endgroup\$
    – Mr. Xcoder
    Feb 11, 2018 at 8:12
0
\$\begingroup\$

zsh, 288 bytes, cracked by Conor O'Brien

`#echo#`:`#a:G.Array.Integer#`
;: PVar$i: G.Integer :;
;: `#FOR#:i=0:!i>a.Length:i+=1` :;
;: :: IO.Out.PrintInt: a.$i :: :;
;: `#ENDFOR#` :;
`#endecho#`
`#main#`:`#a:G.Array.Array.Char#`
;: PVar$i: G.Integer :;
;: PVar$j: G.Integer :;
:; i=1 ;:
:; j=100 ;:
:; echo {$i..$j} ;:
`#endmain#`

Probably won't last long, but eh.

\$\endgroup\$
1
0
\$\begingroup\$

QML, 215 bytes, cracked by totallyhuman

import QtQuick 2.9
import QtQuick.Window 2.2

Window {
    visible: true
    width: 640
    height: 480
    title: qsTr("Hello World")

    ListView {
        anchors.fill: parent
        model: 100
        delegate: Text { text: index + 1 }
    }
}

Outputs 1-100 in text with every number on it's own line. The whole UI is a vertical flickable application.

Well done to @totallyhuman who cracked this.

This is, indeed, QML. The model property usually is connected to a data source providing data for a list (as per doc.qt.io/archives/qt-5.5/qml-qtquick-listview.html#model-prop). However, it can also point to a Javascript array, or, hold a single number. When it's the later, it functions like a "Repeater" and the delegate element is repeated n times.

\$\endgroup\$
1
0
\$\begingroup\$

Windows Batch file, 320 bytes, cracked by MD XF

set S=1;2;3;4;5;6;7;8;9;10;11;12;13;14;15;16;17;18;19;20;21;22;23;24;25;26;27;28;29;30;31;32;33;34;35;36;37;38;39;40;41;42;43;44;45;46;47;48;49;50;51;52;53;54;55;56;57;58;59;60;61;62;63;64;65;66;67;68;69;70;71;72;73;74;75;76;77;78;79;80;81;82;83;84;85;86;87;88;89;90;91;92;93;94;95;96;97;98;99;100
echo %S:;= & echo %

Output: the numbers 1-100 with each number (in plain text) on it's own line

Well done @md-xf who cracked this. It is a Windows Batch file. The trick was an echo expansion causing the following to be generated:

echo 1
echo 2
echo 3
...
\$\endgroup\$
1
0
\$\begingroup\$

ExtraC, 68 bytes, cracked by NieDzejkob

for(int i be 1 AND not(i greater 100)AND increment i)do
print(i)
end
\$\endgroup\$
1
  • \$\begingroup\$ Cracked \$\endgroup\$
    – Maya
    Feb 14, 2018 at 17:16
0
\$\begingroup\$

PHP, 133 bytes, cracked by Dennis

Easy one : (numbers are separated by pipe symbol)

for 
(
 putenv("num=".(int)(bool)NO); 
 getenv ("num") <= 100; 
 putenv("num=". (getenv("num") + 1))
)
 printf("%d|", getenv("num"));

Catch :

  1. No PHP variables in FOR loop

  2. Code is made to be C-like syntax

  3. Objective-C has macro named NO which is 0.

  4. PHP has strange syntax construct "define without define" :
    if interpreter finds unqualified token in code - it assumes that this token is an undefined constant and because it's value is unknown - value is taken from token name converted to a string constant. That's why NO get's interpreted as 'NO' and because all non-empty strings in PHP means true when converted to boolean - integer 1 is saved into environment variable in FOR loop initialization part. Fortunately this PHP behavior is now a deprecated feature

  5. The only thing which truly reaveals that it is PHP code snippet - string concatenation operator . If PHP would have function strcat() like C does - hiding dot from the reader would make code more inseparable from a C syntax.

\$\endgroup\$
1
0
\$\begingroup\$

rk-lang, 44 bytes, cracked by Dennis

int $1
while $1 < 100 do
  print: ++ $1
done

Requires the -e flag. Outputs decimals separated by spaces with a trailing space.

\$\endgroup\$
1
0
\$\begingroup\$

Cubically 6×6×6, 14 bytes, cracked by H.PWiz

[+1[+7]35@]100

Per this meta post, Cubically with the -6 flag counts as a completely different language (Cubically 6x6x6) than with the -5 flag (Cubically 5x5x5), which is again different from the default language (Cubically 3x3x3).

Cubically 6x6x6 does not have its own wrapper on TIO (i.e. there is no tio.run/#cubically-6x6x6), but the language itself is on TIO; it simply requires the -6 flag. I believe this is valid due to the linked meta post and the fact that the language is on TIO, but simply needs more to run than just one of the /srv/wrappers scripts.

Dennis' 8cc answer acts similarly; the language is on TIO, but it requires multiple commands and command-line flags, none of which were specified in the answer.

\$\endgroup\$
8
  • 1
    \$\begingroup\$ I'm watching :) \$\endgroup\$
    – MickyT
    Feb 12, 2018 at 0:20
  • 1
    \$\begingroup\$ It takes less than 6 seconds to crack once you find the right language. \$\endgroup\$
    – Steadybox
    Feb 12, 2018 at 4:10
  • \$\begingroup\$ What's the output format? \$\endgroup\$
    – Jo King
    Feb 16, 2018 at 0:17
  • 3
    \$\begingroup\$ Cracked. This is Cubically -6 \$\endgroup\$
    – H.PWiz
    Feb 18, 2018 at 1:58
  • 2
    \$\begingroup\$ This is invalid because you didn't specify the command line flags. (not that it matters now) \$\endgroup\$ Feb 18, 2018 at 2:01
0
\$\begingroup\$

Unfuck, 78 bytes, safe

++++(^~)~(~?!)((>+++++<-))(^)>(^~)~(~?!)((>+++++<-))(^)>(^~)~(~?!)((>+.<-))(^)
\$\endgroup\$
0
\$\begingroup\$

Attache, 15 bytes, cracked by totallyhuman

Print!V[1..100]

I like this language.

\$\endgroup\$
1
0
\$\begingroup\$
l=[1,...,100]
+.+.+.+.+.+.+./*
r=1
t(x)=(x,x)
n=1
*/for(i=0;i<100;i++){console.log(i+1)}
print(l)
i=1
p=1
asdfasdfasdfasdfasdfasdfasdf

What a mess. Just like me.

Specifying the output format would give it away. That's a hint.

\$\endgroup\$
2
  • \$\begingroup\$ You realise if you don't specify the format, anything's valid... \$\endgroup\$
    – emanresu A
    Aug 14, 2021 at 9:28
  • \$\begingroup\$ This is Desmos. Please specify your output formats next time if this was unintended. \$\endgroup\$
    – emanresu A
    Sep 5, 2021 at 11:26
0
\$\begingroup\$

51AC8, 7 bytes, Cracked by emanresu A

100r[t]

This was fun.

Outputs numbers as decimals separated by newlines.

\$\endgroup\$
1
  • \$\begingroup\$ This is 51ac8 \$\endgroup\$
    – emanresu A
    Aug 16, 2021 at 7:18
0
\$\begingroup\$

Jelly, 3 bytes, cracked by exedraj

³RY

Outputs numbers separated by newlines.

\$\endgroup\$
1
0
\$\begingroup\$

><>, 25 bytes, Cracked by emanresu A

0>1+:aa*1+=v
 ^ oan:;?  <

Outputs numbers separated by newlines. I learnt a new language :).

Should be fairly easy to crack.

\$\endgroup\$
0
\$\begingroup\$

Desmos, 9 bytes, cracked obviously

[1...100]
\$\endgroup\$
0
\$\begingroup\$

International Phonetic Esoteric Language, 147 bytes, safe

(print "")"e"(print ")ʁ(")(print ")1(")(print ")ɑ(")(print ")e(")(print ")o(")(print ")e(")(print ")1(")(print ")s(")(print ")ø(")(print ")ɒ(")

Outputs newline-separated decimal numbers to STDOUT.

Explanation

This abuses how matching parentheses () are comments in IPEL to make mostly incomprehensible Lisp code.

"e"ʁ1ɑeoe1søɒ (prints 1-100 inclusive in decimal separated by newlines)
"e"           (literal string "e")
   ʁ          (ord)
    1         (literal int 1)
     ɑ        (begin loop: from 1 to ord["e"])
      e       (loop counter)
       o      (pop and println)
        e1sø  (increment loop counter)
            ɒ (if loop counter <= ord["e"], jump back to ɑ. else exit)
\$\endgroup\$
2
  • \$\begingroup\$ What's the output format? \$\endgroup\$
    – emanresu A
    Jan 17, 2023 at 20:31
  • \$\begingroup\$ @emanresuA newline-separated decimal numbers \$\endgroup\$
    – bigyihsuan
    Jan 17, 2023 at 20:47
0
\$\begingroup\$

Vyxal, 6 bytes, Cracked by noodle man

100�

Uses SBCS encoding. Two unprintables at the start with hex codes 1C 1E.

\$\endgroup\$
3
  • \$\begingroup\$ Please give a hexdump of the program (just list the encoded hex codes) \$\endgroup\$
    – noodle man
    Jun 30, 2023 at 11:29
  • \$\begingroup\$ I'm pretty sure this is Vyxal Þ∞100Ẏ but I can't be sure until you post the dump \$\endgroup\$
    – noodle man
    Jun 30, 2023 at 11:37
  • \$\begingroup\$ @noodleman well done, you cracked it \$\endgroup\$ Jun 30, 2023 at 11:43
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