Python 2 - 56 bytes
The first actual answer, if I'm correct. Uses Newton's method.
n=x=input();exec"x-=(x**n-n)/(1.*n*x**-~n);"*999;print x
The first actual answer, if I'm correct. Uses Newton's method.
n=x=input();exec"x-=(x**n-n)/(1.*n*x**-~n);"*999;print x