#GNU dc, 6 (3x2)
I think this is the shortest answer not to require the "mod 90°" rule-relaxation:
3z1
0p2
Outputs 0, 1, 2 or 3 for each rotation.
For the 0, 2 and 3 rotations, the p simply pops and prints the last number literal to have been pushed to the stack. For the 1 rotation, the z pushes the current stack depth (1) to the stack, then the p pops and prints it.