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#C++ This behavior is actually specified in the standard (and that's why it was deprecated).

#include<iostream>
#include<memory>
int main()
{
    std::auto_ptr<int> a = new int(0);
    std::cout<<a.get()<<'\n';
    std::auto_ptr<int> b = a;
    std::auto_ptr<<a.get()<<'\n';
}

Output

some address
0

The process that causes this is the same as Abhijit's answer but without requiring a std::move and the same as marinus' answer but using a standard class instead of defining it myself.