R, 77 76 72 bytes

Edit: -4 bytes thanks to Robin Ryder

sum((d=scan()/10-9)>=c(11,9:2,.5,-1,d)&d<=c(d,14.5,12,11,9.5,8:4,2.5,0))

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Fairly naive solution, but benefits from R's automatic vectorization and its : sequence operator.