Python 2, 95 71 70 55 bytes
lambda i,m:min(i.count(c)/m.count(c)for c in m if" "<c)
Input: Ingredients i as a comma-separated string, and a meal m as a string.
Output: Max number of meals that can be made.
How: Divides the frequency of each character in the ingredient by its corresponding character in the meal, then takes the minimum.