Given a polynomial function f (e.g. as a list p of real coefficients in ascending or descending order), a non-negative integer n, and a real value x, return:
# f n(x)
i.e. the value of f (f (f (…f (x)…))) for n applications of f on x.
Use reasonable precision and rounding.
###Example cases
p =[1,0,0] or f =x^2, n =0, x =3: f 0(3) =3
p =[1,0,0] or f =x^2, n =1, x =3: f 1(3) =9
p =[0.1,-2.3,-4] or f =0.1x^2-2.3x-4, n =0, x =2.3: f 0(2.3) =2.3
p =[0.1,-2.3,-4] or f =0.1x^2-2.3x-4, n =1, x =2.3: f 1(2.3) =-8.761
p =[0.1,-2.3,-4] or f =0.1x^2-2.3x-4, n =2, x =2.3: f 2(2.3) =23.8258
p =[0.1,-2.3,-4] or f =0.1x^2-2.3x-4, n =3, x =2.3: f 3(2.3) =-2.03244
p =[0.1,-2.3,-4] or f =0.1x^2-2.3x-4, n =4, x =2.3: f 4(2.3) =1.08768
p =[0.1,-2.3,-4] or f =0.1x^2-2.3x-4, n =5, x =2.3: f 5(2.3) =-6.38336
p =[0.1,-2.3,-4] or f =0.1x^2-2.3x-4, n =6, x =2.3: f 6(2.3) =14.7565
p =[0.1,-2.3,-4] or f =0.1x^2-2.3x-4, n =7, x =2.3: f 7(2.3) =-16.1645
p =[0.1,-2.3,-4] or f =0.1x^2-2.3x-4, n =8, x =2.3: f 8(2.3) =59.3077
p =[0.1,-2.3,-4] or f =0.1x^2-2.3x-4, n =9, x =2.3: f 9(2.3) =211.333
p =[0.1,-2.3,-4] or f =0.1x^2-2.3x-4, n =10, x =2.3: f 10(2.3) =3976.08
p =[0.1,-2.3,-4] or f =0.1x^2-2.3x-4, n =11, x =2.3: f 11(2.3) =1.57177E6
p =[-0.1,2.3,4] or f =−0.1x^2+2.3x+4, n =0, x =-1.1: f 0(-1.1) =-1.1
p =[-0.1,2.3,4] or f =−0.1x^2+2.3x+4, n =1, x =-1.1: f 1(-1.1) =1.349
p =[-0.1,2.3,4] or f =−0.1x^2+2.3x+4, n =2, x =-1.1: f 2(-1.1) =6.92072
p =[-0.1,2.3,4] or f =−0.1x^2+2.3x+4, n =14, x =-1.1: f 14(-1.1) =15.6131
p =[0.02,0,0,0,-0.05] or f =0.02x^4-0.05, n =25, x =0.1: f 25(0.1) =-0.0499999
p =[0.02,0,-0.01,0,-0.05] or f =0.02x^4-0.01x^2-0.05, n =100, x =0.1: f 100(0.1) =-0.0500249