17
\$\begingroup\$

Fairly obviously, you have to print the Greek alphabet. But I thought I'd make it slightly more interesting, so there's a twist: when your program is ran with an argument (anything), it should output the Greek alphabet in lowercase.

Information

  1. Greek alphabet (Capitals): ΑΒΓΔΕΖΗΘΙΚΛΜΝΞΟΠΡΣΤΥΦΧΨΩ
  2. Greek alphabet (Lowercase): αβγδεζηθικλμνξοπρστυφχψω

Rules/Requirements

  • Each submission must be a full program.
  • Builtins to print the Greek alphabet are not permitted
  • Standard loopholes apply
  • You must print exactly what is shown.

Scoring

Programs are scored according to bytes. If you are using a character set different to UTF-8 please specify. Try to get the least bytes out of everyone, this is !

Test cases

./program
==> ΑΒΓΔΕΖΗΘΙΚΛΜΝΞΟΠΡΣΤΥΦΧΨΩ

./program 1
==> αβγδεζηθικλμνξοπρστυφχψω

./program 'lower'
==> αβγδεζηθικλμνξοπρστυφχψω

./program 123897883421
==> αβγδεζηθικλμνξοπρστυφχψω

./program ""
==> αβγδεζηθικλμνξοπρστυφχψω

greek();
==> ΑΒΓΔΕΖΗΘΙΚΛΜΝΞΟΠΡΣΤΥΦΧΨΩ

greek("blah");
==> αβγδεζηθικλμνξοπρστυφχψω

greek(123);
==> αβγδεζηθικλμνξοπρστυφχψω

Submissions

To make sure that your answer shows up, please start your answer with a headline, using the following Markdown template:

# Language Name, N bytes

where N is the size of your submission. If you improve your score, you can keep old scores in the headline, by striking them through. For instance:

# Ruby, <s>104</s> <s>101</s> 96 bytes

If there you want to include multiple numbers in your header (e.g. because your score is the sum of two files or you want to list interpreter flag penalties separately), make sure that the actual score is the last number in the header:

# Perl, 43 + 2 (-p flag) = 45 bytes

You can also make the language name a link which will then show up in the leaderboard snippet:

# [><>](http://esolangs.org/wiki/Fish), 121 bytes

Leaderboard

Here is a Stack Snippet to generate both a regular leaderboard and an overview of winners by language.

/* Configuration */

var QUESTION_ID = 97049; // Obtain this from the url
// It will be like https://XYZ.stackexchange.com/questions/QUESTION_ID/... on any question page
var ANSWER_FILTER = "!t)IWYnsLAZle2tQ3KqrVveCRJfxcRLe";
var COMMENT_FILTER = "!)Q2B_A2kjfAiU78X(md6BoYk";
var OVERRIDE_USER = 53406; // This should be the user ID of the challenge author.

/* App */

var answers = [], answers_hash, answer_ids, answer_page = 1, more_answers = true, comment_page;

function answersUrl(index) {
  return "https://api.stackexchange.com/2.2/questions/" +  QUESTION_ID + "/answers?page=" + index + "&pagesize=100&order=desc&sort=creation&site=codegolf&filter=" + ANSWER_FILTER;
}

function commentUrl(index, answers) {
  return "https://api.stackexchange.com/2.2/answers/" + answers.join(';') + "/comments?page=" + index + "&pagesize=100&order=desc&sort=creation&site=codegolf&filter=" + COMMENT_FILTER;
}

function getAnswers() {
  jQuery.ajax({
    url: answersUrl(answer_page++),
    method: "get",
    dataType: "jsonp",
    crossDomain: true,
    success: function (data) {
      answers.push.apply(answers, data.items);
      answers_hash = [];
      answer_ids = [];
      data.items.forEach(function(a) {
        a.comments = [];
        var id = +a.share_link.match(/\d+/);
        answer_ids.push(id);
        answers_hash[id] = a;
      });
      if (!data.has_more) more_answers = false;
      comment_page = 1;
      getComments();
    }
  });
}

function getComments() {
  jQuery.ajax({
    url: commentUrl(comment_page++, answer_ids),
    method: "get",
    dataType: "jsonp",
    crossDomain: true,
    success: function (data) {
      data.items.forEach(function(c) {
        if (c.owner.user_id === OVERRIDE_USER)
          answers_hash[c.post_id].comments.push(c);
      });
      if (data.has_more) getComments();
      else if (more_answers) getAnswers();
      else process();
    }
  });  
}

getAnswers();

var SCORE_REG = /<h\d>\s*([^\n,]*[^\s,]),.*?(\d+)(?=[^\n\d<>]*(?:<(?:s>[^\n<>]*<\/s>|[^\n<>]+>)[^\n\d<>]*)*<\/h\d>)/;

var OVERRIDE_REG = /^Override\s*header:\s*/i;

function getAuthorName(a) {
  return a.owner.display_name;
}

function process() {
  var valid = [];
  
  answers.forEach(function(a) {
    var body = a.body;
    a.comments.forEach(function(c) {
      if(OVERRIDE_REG.test(c.body))
        body = '<h1>' + c.body.replace(OVERRIDE_REG, '') + '</h1>';
    });
    
    var match = body.match(SCORE_REG);
    if (match)
      valid.push({
        user: getAuthorName(a),
        size: +match[2],
        language: match[1],
        link: a.share_link,
      });
    
  });
  
  valid.sort(function (a, b) {
    var aB = a.size,
        bB = b.size;
    return aB - bB
  });

  var languages = {};
  var place = 1;
  var lastSize = null;
  var lastPlace = 1;
  valid.forEach(function (a) {
    if (a.size != lastSize)
      lastPlace = place;
    lastSize = a.size;
    ++place;
    
    var answer = jQuery("#answer-template").html();
    answer = answer.replace("{{PLACE}}", lastPlace + ".")
                   .replace("{{NAME}}", a.user)
                   .replace("{{LANGUAGE}}", a.language)
                   .replace("{{SIZE}}", a.size)
                   .replace("{{LINK}}", a.link);
    answer = jQuery(answer);
    jQuery("#answers").append(answer);

    var lang = a.language;
    if (/<a/.test(lang)) lang = jQuery(lang).text();
    
    languages[lang] = languages[lang] || {lang: a.language, user: a.user, size: a.size, link: a.link};
  });

  var langs = [];
  for (var lang in languages)
    if (languages.hasOwnProperty(lang))
      langs.push(languages[lang]);

  langs.sort(function (a, b) {
    if (a.lang > b.lang) return 1;
    if (a.lang < b.lang) return -1;
    return 0;
  });

  for (var i = 0; i < langs.length; ++i)
  {
    var language = jQuery("#language-template").html();
    var lang = langs[i];
    language = language.replace("{{LANGUAGE}}", lang.lang)
                       .replace("{{NAME}}", lang.user)
                       .replace("{{SIZE}}", lang.size)
                       .replace("{{LINK}}", lang.link);
    language = jQuery(language);
    jQuery("#languages").append(language);
  }

}
body { text-align: left !important}

#answer-list {
  padding: 10px;
  width: 290px;
  float: left;
}

#language-list {
  padding: 10px;
  width: 290px;
  float: left;
}

table thead {
  font-weight: bold;
}

table td {
  padding: 5px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<link rel="stylesheet" type="text/css" href="//cdn.sstatic.net/codegolf/all.css?v=83c949450c8b">
<div id="answer-list">
  <h2>Leaderboard</h2>
  <table class="answer-list">
    <thead>
      <tr><td></td><td>Author</td><td>Language</td><td>Size</td></tr>
    </thead>
    <tbody id="answers">

    </tbody>
  </table>
</div>
<div id="language-list">
  <h2>Winners by Language</h2>
  <table class="language-list">
    <thead>
      <tr><td>Language</td><td>User</td><td>Score</td></tr>
    </thead>
    <tbody id="languages">

    </tbody>
  </table>
</div>
<table style="display: none">
  <tbody id="answer-template">
    <tr><td>{{PLACE}}</td><td>{{NAME}}</td><td>{{LANGUAGE}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr>
  </tbody>
</table>
<table style="display: none">
  <tbody id="language-template">
    <tr><td>{{LANGUAGE}}</td><td>{{NAME}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr>
  </tbody>
</table>

\$\endgroup\$
15
  • 5
    \$\begingroup\$ Does an empty string count as having an argument or having no argument? Please use the Sandbox to get feedback before posting a challenge on the main site. \$\endgroup\$
    – user45941
    Commented Oct 22, 2016 at 6:37
  • 1
    \$\begingroup\$ @Mego That counts as an argument. \$\endgroup\$
    – user53406
    Commented Oct 22, 2016 at 6:38
  • 2
    \$\begingroup\$ Related. \$\endgroup\$ Commented Oct 22, 2016 at 8:36
  • 2
    \$\begingroup\$ Will the argument be always one argument, or can there be two or more arguments? \$\endgroup\$ Commented Oct 22, 2016 at 8:40
  • 4
    \$\begingroup\$ I'm a bit confused by your last three test cases; they look like function calls, yet the rules specifically ask for a full program. \$\endgroup\$
    – Dennis
    Commented Oct 31, 2016 at 14:11

48 Answers 48

1
2
1
\$\begingroup\$

Python, 81 Bytes

lambda*x,b="αβγδεζηθικλμνξοπρστυφχψω":(b.upper(),b)[x>()]

-6 from TheThonnu for using *.
-2 from TheThonnu for telling me that the brackets are unneeded.
-28 from mousetail for using an uppercasing function.
-7 from TheThonnu for assigning the greek letters to a variable.

\$\endgroup\$
11
  • \$\begingroup\$ Fails for falsy arguments, like "" and 0 \$\endgroup\$
    – The Thonnu
    Commented Apr 11, 2023 at 10:33
  • \$\begingroup\$ You can fix it and save a few bytes: 118 bytes \$\endgroup\$
    – The Thonnu
    Commented Apr 11, 2023 at 10:34
  • \$\begingroup\$ @TheThonnu what does the asterik do? \$\endgroup\$ Commented Apr 11, 2023 at 11:04
  • \$\begingroup\$ It allows the function to take any number of arguments (including no arguments), and then wraps it all into a tuple, x. \$\endgroup\$
    – The Thonnu
    Commented Apr 11, 2023 at 11:41
  • \$\begingroup\$ Also, the parentheses are unnecessary, since and has a higher precedence than or: 116 bytes \$\endgroup\$
    – The Thonnu
    Commented Apr 11, 2023 at 11:41
1
\$\begingroup\$

Raku, 53 bytes

{say @*ARGS??.lc!!$_}([~] flat 'Α'..'Ρ','Σ'..'Ω')

Try it online!

  • [~] flat 'Α'..'Ρ','Σ'..'Ω' constructs the uppercase Greek alphabet.
  • { say @*ARGS ?? .lc !! $_ } is an anonymous function which receives the uppercase alphabet as an argument. If there are any command-line arguments, the alphabet is lowercased and printed, otherwise it is printed as-is.
\$\endgroup\$
1
\$\begingroup\$

Thunno 2 J, 17 16 15 14 bytes

24Ė17Ɗ913+C¤?L

-1 thanks to @TheThonnu :), saved 1 extra by using different method.

Explanation:

24Ė              # range [0, 24]
   17Ɗ           # remove index 17
      913+       # add 913 to each
          C      # convert to character array
           ¤?    # if there is input:
             L   #   convert to lowercase (vectorizes)
                 # J flag joins character array

Thunno 2 isn't on ATO yet, but I have confirmed that this works on my machine for both the input and no input versions.

\$\endgroup\$
2
  • \$\begingroup\$ Not at my computer right now, but would ¤?kj+ work in place of kj¤l×+? Also, doesn't the B flag give a string not a character array, so the J flag isn't necessary? \$\endgroup\$
    – The Thonnu
    Commented Apr 23, 2023 at 17:08
  • 1
    \$\begingroup\$ @TheThonnu Thanks, it does work! Not sure why it wasn't working for me earlier \$\endgroup\$ Commented Apr 23, 2023 at 17:12
1
\$\begingroup\$

Japt -P, 17 bytes

25od913+H*NÊ fÏÉ7

Test it

Explanation

25o                 map each n in range [0, 25):
   d                  convert the following codepoint to a character:
    913                 n + 913
       +H*NÊ            + (number of inputs * 32)
             fÏ     keep elements where the following is truthy:
               É7     subtract 17 from the index 
                      (if index is 17, this will be 0 = falsy)
-P                  P flag joins the array to a string

The cool part of this is fÏÉ7: É7 transforms to -17 by using the shortcut for -1 (i.e. decrement). The regular way of doing this would be something like f϶17 which is one byte longer.

\$\endgroup\$
0
\$\begingroup\$

Python 2, 108 bytes

#coding=iso-8859-7
import sys;print'αβγδεζηθικλμνξοπρστυφχψω'if~-len(sys.argv)else'ΑΒΓΔΕΖΗΘΙΚΛΜΝΞΟΠΡΣΤΥΦΧΨΩ'

Terribly golfed, maybe :(

And no, I can't use A.lower().

Thanks to 13285 (alexwlchan) for -11 bytes.

\$\endgroup\$
3
  • \$\begingroup\$ This is the most golfed version I can do. \$\endgroup\$ Commented Oct 22, 2016 at 10:34
  • \$\begingroup\$ You can save 8 bytes by skipping the assignment to A,a, and just using those strings directly in the print. \$\endgroup\$
    – alexwlchan
    Commented Oct 22, 2016 at 10:53
  • \$\begingroup\$ @alexwlchan Right, I just didn't think of it... still terribly golfed, though. \$\endgroup\$ Commented Oct 22, 2016 at 10:57
0
\$\begingroup\$

Mathematica, 91 bytes

Print@{#&,ToLowerCase}[[Length@$ScriptCommandLine]][""<>"Α"~CharacterRange~"Ω"~Drop~{18}]

Script. Just takes the character range from Α to Ω, removes U+03A2/ς, either converts to lowercase or doesn't, and prints.

\$\endgroup\$
0
\$\begingroup\$

Perl, 39 + 3 (-C2 flag) = 44 42 bytes

 perl -C2 -E 'say map{chr$_+954-!@ARGV*32}-9..7,9..15'
\$\endgroup\$
0
\$\begingroup\$

JavaScript, 95 bytes

95 bytes, but only 71 characters. Byte counter. Using @Neil s way to determine if arguments are passed.

(...a)=>'ΑΒΓΔΕΖΗΘΙΚΛΜΝΞΟΠΡΣΤΥΦΧΨΩ'[`to${a.length?'Low':'Upp'}erCase`]()
\$\endgroup\$
0
\$\begingroup\$

Java 7, 176 bytes

class M{public static void main(String[]a){System.out.print(a.length>0?"αβγδεζηθικλμνξοπρστυφχψω":"ΑΒΓΔΕΖΗΘΙΚΛΜΝΞΟΠΡΣΤΥΦΧΨΩ");}}

Java 8, 173 bytes

interface M{static void main(String[]a){System.out.print(a.length>0?"αβγδεζηθικλμνξοπρστυφχψω":"ΑΒΓΔΕΖΗΘΙΚΛΜΝΞΟΠΡΣΤΥΦΧΨΩ");}}
\$\endgroup\$
0
\$\begingroup\$

Groovy Script, 54 51 bytes

((913..937)-930).each{print((char)(args?it+32:it))}

Edit

Switched from 913..937 and it==930?: to (913..937)-930

\$\endgroup\$
1
  • \$\begingroup\$ Can someone explain me, why my answer was downvoted? Did it broke any rules? \$\endgroup\$
    – Victor A.
    Commented Oct 26, 2016 at 7:51
0
\$\begingroup\$

PHP, 79 bytes

for($i=944-32*!--$argc;$i++-9&31;$i+=$i%32==1)echo html_entity_decode("&#$i;");

generates unicode html entities and decodes them. Run with -r.

\$\endgroup\$
0
\$\begingroup\$

Pip, 21 20 bytes

C:913+32*#g+Y,24RM17

This is a memorable day. Pip has tied beaten Jelly!1

1 And lost to two other golflangs, but whatever.

Try it online!

Explanation

             ,25      Numbers 0 through 24
                RM17  Remove 17 (ς)
            Y         Yank (to get correct order of operations)
  913                 Char code of capital alpha
      32*#g           32 times number of cmdline args (must be 0 or 1)
     +     +          Add everything up
C:                    Convert to characters (using the compute-and-assign metaoperator to
                        lower the precedence of C)
\$\endgroup\$
0
\$\begingroup\$

MATLAB, 35 bytes

@(x)disp(char((913:937)+32*nargin))

Pretty self-explainatory, I think.

\$\endgroup\$
0
\$\begingroup\$

PowerShell, 94 bytes

param($n)$k=((0..16)+(18..24)|%{[char]($_+913)})-join'';if($n){$k.tolower()}else{$k.toupper()}

Try it online!

\$\endgroup\$
3
0
\$\begingroup\$

Excel, 48 bytes

=CONCAT(UNICHAR(ROW(1:24)*19/18+944-(A1="")*32))

Alternatively, you could put the upper case alphabet in B2 and use the formula below for a combined 47 bytes (or more depending on how you account for multiple cells)

=IF(A1="",B2,LOWER(B2))
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0
\$\begingroup\$

APL, 27 bytes

{⎕UCS(912+32×0∊⍴⍵)+18~⍨⍳25}

The program switched to uppercase, when empty array or empty string is received. Unfortunately, it is technically impossible to distinguish them.

\$\endgroup\$
0
\$\begingroup\$

Scala, 171 bytes

Modified from @Value Ink's Ruby solution.


Golfed version. Try it online!

object Main{def main(args:Array[String])=println((if(args.nonEmpty)('α'to'ω').toSet.diff(Set('ς')).toList else('Α'to'Ρ').toList++('Σ'to 'Ω').toList).mkString(" "))}

Ungolfed version. Try it online!

object Main {
  def main(args: Array[String]): Unit = {
    val result = if (args.nonEmpty) ('α' to 'ω').toSet.diff(Set('ς')).toList
                 else ('Α' to 'Ρ').toList ++ ('Σ' to 'Ω').toList
    println(result.mkString(" "))
  }
}
\$\endgroup\$
-1
\$\begingroup\$

Perl under Windows -- console has no Unicode support -- (42 bytes, including spaces)

This is not my solution, I am just merely adapting the Perl solution of Denis Ibaev above, to Windows console Perl.

perl -E"say map{chr$_+151-!@ARGV*24}1..24"
ΑΒΓΔΕΖΗΘΙΚΛΜΝΞΟΠΡΣΤΥΦΧΨΩ
$ perl -E"say map{chr$_+151-!@ARGV*24}1..24" with one or many arguments
αβγδεζηθικλμνξοπρσςτυφχψ

The console page code must be Greek of course:

chcp 737

NOTE: Just a small idea. On this page I can see that some of the answers use CHARACTERS that seem to been Unicode above 255. Therefore those characters take at least 2 bytes to code (perhaps 4 if one is using a console using 32bits Unicode chars?). Would not it be better if the contest measure was the CHARACTER unit (being Unicode or ASCII or EBCDIC ou whatever) rather than just BYTES? Would not it be simpler and more unifying (wonder if this adjectif exists in English, "unificateur" in French)?


Previous code in error: Does not print lowercase omega.

Corrected code (70 chars) :

perl -E"$i=!@ARGV+0;@a=73;pop@a if$i;say map{chr$_+151-$i*24}1..24,@a"
ΑΒΓΔΕΖΗΘΙΚΛΜΝΞΟΠΡΣΤΥΦΧΨΩ
perl -E"$i=!@ARGV+0;@a=73;pop@a if$i;say map{chr$_+151-$i*24}1..24,@a" foo
αβγδεζηθικλμνξοπρσςτυφχψω

I know we are not supposed to print the 'end-of-word' sigma form ('ς') but as it is a mispelling error in ancient Greek to use regular sigma ('σ') at the end of a lowercase word, I choose to print it, as the tittle of this puzzle is "Print the Greek alphabet" and that this character is part of it...

\$\endgroup\$
1
2

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