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Commonmark migration
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#Bash, 77 bytes

Bash, 77 bytes

IFS=$'\n '
f=(`factor $1`)
g=(`uniq<<<"${f[*]}"`)
echo $((${#f[*]}-${#g[*]}))

Complete program, with input in $1 and output to stdout.

We set IFS to begin with a newline, so that the expansion "${f[*]}" is newline-separated. We use arithmetic substitution to print the difference between the number of words in the factorisation with the result of filtering through uniq. The number itself is printed as a prefix by factor, but it is also present after filtering, so falls out in the subtraction.

#Bash, 77 bytes

IFS=$'\n '
f=(`factor $1`)
g=(`uniq<<<"${f[*]}"`)
echo $((${#f[*]}-${#g[*]}))

Complete program, with input in $1 and output to stdout.

We set IFS to begin with a newline, so that the expansion "${f[*]}" is newline-separated. We use arithmetic substitution to print the difference between the number of words in the factorisation with the result of filtering through uniq. The number itself is printed as a prefix by factor, but it is also present after filtering, so falls out in the subtraction.

Bash, 77 bytes

IFS=$'\n '
f=(`factor $1`)
g=(`uniq<<<"${f[*]}"`)
echo $((${#f[*]}-${#g[*]}))

Complete program, with input in $1 and output to stdout.

We set IFS to begin with a newline, so that the expansion "${f[*]}" is newline-separated. We use arithmetic substitution to print the difference between the number of words in the factorisation with the result of filtering through uniq. The number itself is printed as a prefix by factor, but it is also present after filtering, so falls out in the subtraction.

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Toby Speight
Toby Speight
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#Bash, 77 bytes

IFS=$'\n '
f=(`factor $1`)
g=(`uniq<<<"${f[*]}"`)
echo $((${#f[*]}-${#g[*]}))

Complete program, with input in $1 and output to stdout.

We set IFS to begin with a newline, so that the expansion "${f[*]}" is newline-separated. We use arithmetic substitution to print the difference between the number of words in the factorisation with the result of filtering through uniq. The number itself is printed as a prefix by factor, but it is also present after filtering, so falls out in the subtraction.