Timeline for Random Golf of the Day #7: A distinctly random character
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 13, 2016 at 11:48 | comment | added | trichoplax is on Codidact now | Unless A is also chosen with a probability of 1/2 when it is reached, with the possibility of wrapping back round to Z? If it always terminates when it reaches A then p(A) = p(B) = 1/2^(25). | |
| Aug 13, 2016 at 11:43 | comment | added | trichoplax is on Codidact now | This appears to give the same probability for A and B. Imagine it for an alphabet of only 3 letters ABC: p(C) = 1/2, p(B) = 1/4, p(A) = 1 - 1/2 - 1/4 = 1/4. | |
| Aug 12, 2016 at 13:33 | history | answered | cliffroot | CC BY-SA 3.0 |