Timeline for Same length sub arrays
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Jun 9, 2016 at 22:28 | comment | added | Maltysen | I guess mathematica's short-circuiting is just weird and I'm not understanding it...sorry | |
| Jun 9, 2016 at 22:28 | comment | added | LLlAMnYP | @Maltysen I'm not seeing how that would be helpful. | |
| Jun 9, 2016 at 22:24 | comment | added | Maltysen |
oic, can you do instead then {}&&stuff?
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| Jun 9, 2016 at 22:21 | comment | added | LLlAMnYP |
@Maltysen Your statement is the inverse of mine and is also true. I'm referring to a@{} -> {} && ArrayQ@{} -> {} && True -> {}. This is desirable. But let b = {{1},{2},{3}}, then a@b -> b && ArrayQ@b -> b && True -> b -> {{1},{2},{3}} whereas we need True here.
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| Jun 9, 2016 at 22:18 | comment | added | Maltysen | why does it do that? shouldn't it return c if b is true? | |
| Jun 9, 2016 at 22:17 | comment | added | LLlAMnYP |
@Maltysen That doesn't seem to work, it'll always return the array if it is an array then (b&&c will always return b if c evaluates to True).
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| Jun 9, 2016 at 22:12 | comment | added | Maltysen |
I don't have my mathematica rpi running atm, but IIRC, you can save by special casing {} by doing a@b_:=b&&ArrayQ@b
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| Jun 9, 2016 at 21:55 | history | answered | LLlAMnYP | CC BY-SA 3.0 |