bash + GNU coreutils, 115109 Bytes

l=${#1}
for i in `seq 0 $l`;{  
for j in `seq $((l-i))`;{
t=$(printffor 'k %.0s'in `seq 0$i`;{ $i`)printf ' ';}
echo "${t:1}${1:i:j}"
}; }

Maybe there is a shorter solution, but this is the best that came into my mind. Uniqueness of chracters does not matter here.

bash + GNU coreutils, 115 Bytes

l=${#1}
for i in `seq 0 $l`;{  
for j in `seq $((l-i))`;{
t=$(printf ' %.0s' `seq 0 $i`)
echo "${t:1}${1:i:j}"
}; }

Maybe there is a shorter solution, but this is the best that came into my mind. Uniqueness of chracters does not matter here.

l=${#1}
for i in `seq 0 $l`;{
for j in `seq $((l-i))`;{
for k in `seq $i`;{ printf ' ';}
echo ${1:i:j}
}; }

Maybe there is a shorter solution, but this is the best that came into my mind. Uniqueness of chracters does not matter here.

added 46 characters in body

Source Link

edited Apr 28, 2016 at 15:52

l=${#1}
for i in `seq 0 $l`;{  
for j in `seq $((l-i))`;{
t=$(printf ' %.0s' `seq 0 $i`)
echo "${t:1}${1:i:j}"
}; }

Maybe there is a shorter solution, but this is the best that came into my mind. Uniqueness of chracters does not matter here.

l=${#1}
for i in `seq 0 $l`;{  
for j in `seq $((l-i))`;{
t=$(printf ' %.0s' `seq 0 $i`)
echo "${t:1}${1:i:j}"
}; }

Maybe there is a shorter solution, but this is the best that came into my mind.

l=${#1}
for i in `seq 0 $l`;{  
for j in `seq $((l-i))`;{
t=$(printf ' %.0s' `seq 0 $i`)
echo "${t:1}${1:i:j}"
}; }

Maybe there is a shorter solution, but this is the best that came into my mind. Uniqueness of chracters does not matter here.

Source Link

created Apr 28, 2016 at 15:19

l=${#1}
for i in `seq 0 $l`;{  
for j in `seq $((l-i))`;{
t=$(printf ' %.0s' `seq 0 $i`)
echo "${t:1}${1:i:j}"
}; }

Maybe there is a shorter solution, but this is the best that came into my mind.