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1-Sum[#~Binomial~k#0@k/(#-k+1),{k,0,#-1}]Sign@#&]&
Unnamed function that uses the literal definition, with some trickery to account for 0.
1-Sum[#~Binomial~k#0@k/(#-k+1),{k,0,#-1}]Sign@#&
1-Sum[#~Binomial~k#0@k/(#-k+1),{k,0,#-1}]&
Unnamed function that uses the literal definition.
