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Oct 24, 2015 at 15:30 vote accept GamrCorps
Oct 2, 2015 at 1:16 comment added MickyT I think you may be able to get away with M[c(i,r),]=M[c(r,i),] rather than t=M[i,];M[i,]=M[r,];M[r,]=t
Oct 2, 2015 at 1:07 history answered Alex A. CC BY-SA 3.0