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Feb 11, 2016 at 7:49 comment added Cyoce Quick reference thing: fun`foo${1}bar${2}baz is equivalent to calling fun(["foo","bar","baz"],1,2)
Feb 10, 2016 at 19:17 comment added Cyoce Be warned, this actually passes an array. fun`string` is the same as fun(["string"]), not fun("string"). This is fine for functions that cast to string, like alert, but for others this could cause issues. For more information see the MDN article
Jun 25, 2015 at 11:53 history edited Optimizer CC BY-SA 3.0
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Jun 25, 2015 at 11:50 history answered Downgoat CC BY-SA 3.0