Timeline for Is it a leap year?
Current License: CC BY-SA 3.0
13 events
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Jun 17, 2020 at 9:04 | history | edited | CommunityBot |
Commonmark migration
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May 26, 2015 at 16:18 | comment | added | LegionMammal978 | @FUZxxl Thanks, it's been a long time since I've read them. | |
May 26, 2015 at 16:18 | history | edited | LegionMammal978 | CC BY-SA 3.0 |
deleted 12 characters in body
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May 26, 2015 at 16:11 | history | edited | LegionMammal978 | CC BY-SA 3.0 |
deleted 12 characters in body
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May 26, 2015 at 15:33 | comment | added | FUZxxl | This is a standard loophole; you're using a function that does exactly the required functionality. This is verboten. | |
May 26, 2015 at 15:15 | comment | added | LegionMammal978 |
@alephalpha Alternatively, you could use U+F523 (\[Implies] ) to make it #∣4&&(#∣100<U+F523>#∣400)& for 19 chars (but still 27 bytes).
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May 26, 2015 at 15:05 | history | edited | LegionMammal978 | CC BY-SA 3.0 |
added 26 characters in body
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May 26, 2015 at 14:59 | history | edited | LegionMammal978 | CC BY-SA 3.0 |
deleted 32 characters in body
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May 26, 2015 at 14:10 | comment | added | FUZxxl | @zeldredge Still, that's not shorter than the APL solution. | |
May 26, 2015 at 13:54 | comment | added | alephalpha |
You can use ∣ to represent Divisible : #∣4&&(!#∣100||#∣400)& , 21 characters, 27 UTF-8 bytes.
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May 26, 2015 at 13:23 | comment | added | zeldredge | This is one of those puzzles where Mathematica offers a solution that feels kind of cheaty: LeapYearQ[#]& | |
May 26, 2015 at 12:09 | history | edited | LegionMammal978 | CC BY-SA 3.0 |
[Edit removed during grace period]
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May 26, 2015 at 11:25 | history | answered | LegionMammal978 | CC BY-SA 3.0 |