deleted 10 characters in body

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edited Jan 3, 2012 at 3:41

Python

Used the fact that the length of a valid string will always be a Triangle Number.

t=raw_input()
x=int(((8*lenlen(t)+1t+t)**.5-1)/2)
print t==''.join(t[i:x]for i in range(x))

A Ruby solution might be shorter, will post soon.

Used the fact that the length of a valid string will always be a Triangle Number.

t=raw_input()
x=int(((8*len(t)+1)**.5-1)/2)
print t==''.join(t[i:x]for i in range(x))

A Ruby solution might be shorter, will post soon.

Used the fact that the length of a valid string will always be a Triangle Number.

t=raw_input()
x=int(len(t+t)**.5)
print t==''.join(t[i:x]for i in range(x))

A Ruby solution might be shorter, will post soon.

deleted 1 characters in body

Source Link

edited Jan 2, 2012 at 6:00

Used the fact that the length of a valid string will always be a Triangle Number.

t=raw_input()
x=int(((8*len(t)+1)**0**.5-1)/2)
print t==''.join(t[i:x]for i in range(x))

A Ruby solution might be shorter, will post soon.

Used the fact that the length of a valid string will always be a Triangle Number.

t=raw_input()
x=int(((8*len(t)+1)**0.5-1)/2)
print t==''.join(t[i:x]for i in range(x))

A Ruby solution might be shorter, will post soon.

Used the fact that the length of a valid string will always be a Triangle Number.

t=raw_input()
x=int(((8*len(t)+1)**.5-1)/2)
print t==''.join(t[i:x]for i in range(x))

A Ruby solution might be shorter, will post soon.

Source Link

created Dec 30, 2011 at 11:24

Used the fact that the length of a valid string will always be a Triangle Number.

t=raw_input()
x=int(((8*len(t)+1)**0.5-1)/2)
print t==''.join(t[i:x]for i in range(x))

A Ruby solution might be shorter, will post soon.

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