Timeline for Find i^n, given n
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Nov 24, 2014 at 14:55 | history | edited | Rodolfo Dias | CC BY-SA 3.0 |
Corrected mistake
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| Nov 24, 2014 at 14:41 | history | edited | Rodolfo Dias | CC BY-SA 3.0 |
Added ungolfed code.
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| Nov 24, 2014 at 14:17 | history | edited | Rodolfo Dias | CC BY-SA 3.0 |
Updated reply and added a function.
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| Nov 24, 2014 at 14:13 | comment | added | Rodolfo Dias | @user902383 Daaaaamn, didn't even remember that. thumbs up | |
| Nov 24, 2014 at 14:09 | comment | added | user902383 |
actually i was thinking about parsing it, so you will have int n = Integer.parseInt(a[0])
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| Nov 24, 2014 at 14:04 | comment | added | Rodolfo Dias | @user902383 I could always make a function, indeed. Probably will post both versions, too. | |
| Nov 24, 2014 at 13:04 | comment | added | user902383 | you could reduced your code, if you pass it to main as argument. | |
| Nov 24, 2014 at 10:02 | history | answered | Rodolfo Dias | CC BY-SA 3.0 |