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C: 10 tokens##tokens

int max(int a, int b, int c)
{
    a += (b > a) * (b - a);
    a += (c > a) * (c - a);
    return a;
}

Inspired by @openorclose's answer, but converted to C and made branchless using multiplication rather than short circuit boolean operators.

C: 10 tokens##

int max(int a, int b, int c)
{
    a += (b > a) * (b - a);
    a += (c > a) * (c - a);
    return a;
}

int max(int a, int b, int c)
{
    a += (b > a) * (b - a);
    a += (c > a) * (c - a);
    return a;
}

Inspired by @openorclose's answer, but converted to C and made branchless using multiplication rather than short circuit boolean operators.

C: 810 tokens##

int max(int a, int b, int c)
{
    a += (b > a) * (b - a);
    a += (c > a) * (c - a);
    return a;
}

Inspired by @openorclose's answer, but converted to C and made branchless using multiplication rather than short circuit boolean operators.