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\(d)sum((d*c(1:7,-1)))%%11
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Takes input as a vector of digits. Outputs swapped truthy (non-zero) / falsy (zero).
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\(d)sum(d*c(1:7,-1))%%11
\(d)sum(d[-8]*1(d*c(1:7,-1)%%11==d[8]))%%11
\(d)sum(d[-8]*1:7)%%11==d[8]
Takes input as a vector of digits.
