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Try it online!
read*,n;print*,sum([n*(j,j=1,n)]n+1);end/2;end
Try it online!Old (but kinda fun) solution: Construct inline anonymous array, sum, and print.
sum
print
read*,n;print*,sum([(j,j=1,n)]);end
Try it online! Construct inline anonymous array, sum, and print.
read*,n;print*,n*(n+1)/2;end
Old (but kinda fun) solution: Construct inline anonymous array, sum, and print.