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added 2 characters in body; deleted 1 characters in body

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edited Feb 6, 2014 at 9:00

user8777

Python 2.7 - 6365

Nice and short one, this uses complex numbers to step through the plane:

x=lambda s:abs2*abs(sum([[1,-1,1j,-1j]['RLUD'.index(i)]for i in s]))

Props to DSM and Abhijit in other questions that showed me the use of 1j to calculate this.

Nice and short one, this uses complex numbers to step through the plane:

x=lambda s:abs(sum([[1,-1,1j,-1j]['RLUD'.index(i)]for i in s]))

Props to DSM and Abhijit in other questions that showed me the use of 1j to calculate this.

Nice and short one, this uses complex numbers to step through the plane:

x=lambda s:2*abs(sum([[1,-1,1j,-1j]['RLUD'.index(i)]for i in s]))

Props to DSM and Abhijit in other questions that showed me the use of 1j to calculate this.

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created Feb 6, 2014 at 3:10

user8777

Nice and short one, this uses complex numbers to step through the plane:

x=lambda s:abs(sum([[1,-1,1j,-1j]['RLUD'.index(i)]for i in s]))

Props to DSM and Abhijit in other questions that showed me the use of 1j to calculate this.