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lambda s:1in[lens in[''.join({s[i::n]forc*n ifor c in range(n)}s[::n])for n in range(2,len(s))]
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-4 bytes, thanks to Jitse
lambda s:1in[len({s[i::n]for i in range(n)})for n in range(2,len(s))]
Try it online!
lambda s:s in[''.join(c*n for c in s[::n])for n in range(2,len(s))]
lambda s:1 in[len1in[len({s[i::n]for i in range(n)})for n in range(2,len(s))]
-34 bytes, thanks to Jitse
lambda s:1 in[len({s[i::n]for i in range(n)})for n in range(2,len(s))]
-3 bytes, thanks to Jitse
lambda s:1 in[len(set({s[i::n]for i in range(n))})for n in range(2,len(s))]
lambda s:1 in[len(set(s[i::n]for i in range(n)))for n in range(2,len(s))]
