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May 29, 2019 at 8:06 answer added Kevin Cruijssen timeline score: 1
May 28, 2019 at 23:51 history edited jimmy23013
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Mar 31, 2011 at 13:29 answer added Dr. Pain timeline score: 3
Mar 31, 2011 at 4:36 answer added fR0DDY timeline score: 2
Mar 30, 2011 at 15:24 comment added Quixotic @Peter Taylor:I didn't knew about exponential Riordan group,thanks for the update :-)
Mar 30, 2011 at 14:42 comment added Peter Taylor @Debanjan, I see your reference and raise you Mathworld (eqn. 5 says that S(n,0) is 1 if n=0 and 0 otherwise). If you want I can find a reference for the stronger statement that Stirling2 is in the associative subgroup of the exponential Riordan group.
Mar 30, 2011 at 14:27 comment added Quixotic @Peter Taylor:I am changing the test case to make it more general,however I would like to add that the The basis cases of Stirling numbers of the second kind are a bit messy: $S(n,1)=1$, $S(n,n)=1$, and $S(n,m)=0$ if $n<m$ or $n=m=0$. (REFERENCE)
Mar 30, 2011 at 14:21 history edited Quixotic CC BY-SA 2.5
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Mar 30, 2011 at 12:44 comment added Peter Taylor @Debanjan: by doing nothing. Compare with binomial(0, 0) = 1, the number of ways of selecting 0 balls from 0 balls; or stirling2(0, 0) = 1 (the number of ways of distributing 0 distinguishable balls into 0 indistinguishable cells).
Mar 30, 2011 at 12:35 comment added Quixotic @Peter Taylor:How can we distribute 0 balls into 0 cells in 1 way?
Mar 30, 2011 at 12:33 comment added Quixotic @Eelvex:Added and No.
Mar 30, 2011 at 12:32 history edited Quixotic CC BY-SA 2.5
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Mar 30, 2011 at 9:19 answer added J B timeline score: 3
Mar 30, 2011 at 9:03 comment added Eelvex @Debanjan: Please add test cases for 0 0, 0 1 and 1 0. Also, is A > B always?
Mar 30, 2011 at 8:57 answer added Eelvex timeline score: 3
Mar 30, 2011 at 1:25 answer added aaaaaaaaaaaa timeline score: 3
Mar 29, 2011 at 23:52 answer added Peter Taylor timeline score: 4
Mar 29, 2011 at 22:07 answer added Peter Taylor timeline score: 2
Mar 29, 2011 at 21:47 comment added Quixotic @fR0DDY:Now it's a completely different problem with different test cases.
Mar 29, 2011 at 21:42 history edited Quixotic CC BY-SA 2.5
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Mar 29, 2011 at 20:16 comment added Peter Taylor You might want to add the test cases 0 0 gives 1, 1 0 gives 0, 0 1 gives 0.
Mar 29, 2011 at 17:09 answer added mellamokb timeline score: 1
Mar 29, 2011 at 14:53 history tweeted twitter.com/#!/StackCodeGolf/status/52745302771372032
Mar 29, 2011 at 8:36 comment added Quixotic SIZECON is in challenge.I was a bit bored yesterday,so I wrote this problem in here ... and then thought of adding in SPOJ and other sites so that it might reach to larger audience.Anyways,I will move it to tutorial if SPOJ users wants that.
Mar 29, 2011 at 7:57 comment added fR0DDY @Debanjan Even though it is your question, it is a challenge problem there. It is not a tutorial problem or from anagolf where answers are revealed.
Mar 29, 2011 at 7:40 history edited Quixotic CC BY-SA 2.5
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Mar 29, 2011 at 7:34 comment added Quixotic @fR0DDY:It's my problem and you can see similar instances here and here.Anyways,just remove the redundant newline in your submission in SPOJ,to set a new record :-)
Mar 29, 2011 at 6:30 history edited Nemo157
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Mar 29, 2011 at 5:58 comment added fR0DDY @Debanjan I don't like the idea of pasting questions from SPOJ here. People submit their code for competing there and it would be unfair to them.
Mar 28, 2011 at 23:58 answer added gnibbler timeline score: 3
Mar 28, 2011 at 22:10 answer added Jesse Millikan timeline score: 2
Mar 28, 2011 at 20:42 comment added mellamokb @Yonatan: I believe that is what is meant by "Every A and B can be distinguishable." That is the interpretation I used when developing my answer, which seems to at least agree with the examples given.
Mar 28, 2011 at 19:46 comment added Yonatan N I take it that the balls are unique? That is, placing ball x1 in bin y1 and ball x2 in bin y2 is different than x1 in y2 and x2 in y1?
Mar 28, 2011 at 15:13 comment added Quixotic @mellamokb:How about now?
Mar 28, 2011 at 14:54 comment added mellamokb That link is invalid for me.
Mar 28, 2011 at 14:50 answer added mellamokb timeline score: 4
Mar 28, 2011 at 14:46 history edited Quixotic CC BY-SA 2.5
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Mar 28, 2011 at 14:20 history edited Quixotic CC BY-SA 2.5
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Mar 28, 2011 at 14:10 history edited Quixotic CC BY-SA 2.5
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Mar 28, 2011 at 13:59 comment added Quixotic @Tim Nordenfur:Updated :-)
Mar 28, 2011 at 13:56 comment added user475 Are there time limits?
Mar 28, 2011 at 13:54 history asked Quixotic CC BY-SA 2.5