Stax, 23 bytes
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Input is two integers separated by a space.
The first is d. -1 specifies north-east. 0 for north. 1 for north-west.
The second parameter is n.
These two values will get implicitly parsed from input and placed on the input stack with n on top.
Additionally d will be accessible from the stax's x register since it's the first implicitly parsed value.
For example, input "1 7"
Main stack Explanation
---------- -----------
; [7] peek from input stack
m map over integers [1..n] using the rest of the program
output each produced value implicitly
; [1 7] peek from input stack
+ [8] add
.*" [8 [42 34]] 2 character string literal with codepoints 42 and 34
@ [42] get the element at the specified modular index (8)
0 [42 0] literal zero
"|\/"x@ [42 0 92] get codepoint from string literal at input d (from x register)
\ [42 [0 92]] make pair
:B ['\ \ \ '] encode in custom base; it's binary with custom codepoints
_x* ['\ \ \ ' 1] (loop variable) * (input d)
;^ ['\ \ \ ' 1 8] peek from input stack and increment
% ['\ \ \ ' 1] modulus
6+ ['\ \ \ ' 7] add 6
) [' \ \ \ '] left-pad to length