Timeline for Alphabet Histogram
Current License: CC BY-SA 3.0
3 events
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| Apr 11, 2018 at 22:55 | comment | added | Jonathan Frech |
Since a!=1 will be boolean, a%5&&a!=1? should be equivalent to a%5&a!=1? or a%5&&~-a.
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| Apr 11, 2018 at 22:52 | comment | added | Jonathan Frech |
for(p=b[1];*p;p++) can most likely be for(p=b[1]-1;*++p;), main(int a,char **b) could probably be golfed to m(a,b)char**b;.
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| Apr 11, 2018 at 22:21 | history | answered | Simon | CC BY-SA 3.0 |