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Jun 17, 2020 at 9:04 history edited CommunityBot
Commonmark migration
Feb 22, 2018 at 14:14 comment added linemade Thanks for the explanation, mypetlion. Also thanks Turksarama and Ruts for saving me some bytes!
Feb 22, 2018 at 14:13 history edited linemade CC BY-SA 3.0
added 9 characters in body
Feb 22, 2018 at 7:41 comment added Ruts Also tried to remove R=range and used function range twice in your code. This also seems to save 1 byte.
Feb 22, 2018 at 7:30 comment added Ruts I'm not very experienced, but I believe you can win 9 bytes by not introducing variables wand h. Remove line w,h=30,5 and change m=[list(' '*w)for y in R(h)] to m=[list(' '*30)for y in R(5)]. I hope I'm right.
Feb 21, 2018 at 23:43 comment added Turksarama Assign your initial 0 inside your loop and set l after the assignment. This saves you one whole line (m[2][0]=0 is gone) and 2 bytes on the for loop (for i in R(1,30): becomes for i in R(30):). You will also need to recalculate l after you set the 0. This should take you to 144 bytes.
Feb 21, 2018 at 18:46 comment added mypetlion In python, boolean a subclass of int. So False can be used in place of 0 and True can replace 1. The ~ is a unary operator for bitwise not and the - operator flips the sign (multiply by -1). So ~-(False) evaluates to -1 and ~-(True) evaluates to 0.
Feb 21, 2018 at 18:34 comment added linemade @mypetlion can you explain how l+=random.randint(~-(l<1),l<4) works?
Feb 21, 2018 at 18:13 history edited linemade CC BY-SA 3.0
deleted 1 character in body
Feb 21, 2018 at 17:58 history edited linemade CC BY-SA 3.0
deleted 8 characters in body
Feb 21, 2018 at 17:52 comment added mypetlion Change m=[[' 'for x in R(w)]for y in R(h)] to m=[list(' '*w)for y in R(h)] to save 7 bytes.
Feb 21, 2018 at 17:51 comment added Mr. Xcoder You should be able to remove a lot of spaces and newlines.
Feb 21, 2018 at 17:48 comment added mypetlion Change l+=random.randint(-1,1) l=0 if l<0 else l l=4 if l>4 else l to l+=random.randint(~-(l<1),l<4) to save 31 bytes.
Feb 21, 2018 at 17:37 history answered linemade CC BY-SA 3.0