Timeline for Find Integral Roots of A Polynomial
Current License: CC BY-SA 3.0
17 events
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| Jun 17, 2020 at 9:04 | history | edited | CommunityBot |
Commonmark migration
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| Jan 24, 2018 at 20:00 | comment | added | Jonathan Allan |
ah, yes - 0.2 is a root so it fails.
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| Jan 24, 2018 at 19:52 | history | edited | Mr. Xcoder | CC BY-SA 3.0 |
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| Jan 24, 2018 at 19:51 | comment | added | Mr. Xcoder |
@Jonathan You must return the integral roots of a given polynomial. 0 does not satisfy 10x^2+(-42)x+8=0, since 10*0^2+(-42)*0+8=8 is not equal to zero. Therefore, 0 is not a root of this polynomial.
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| Jan 24, 2018 at 19:47 | comment | added | Jonathan Allan | I'm obviously not understanding something then. | |
| Jan 24, 2018 at 19:43 | comment | added | Mr. Xcoder |
@JonathanAllan But it does fail for [10,-42,8], right?
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| Jan 24, 2018 at 19:40 | comment | added | Jonathan Allan | "If there is no solution for the given equation, then the output is undefined" | |
| Jan 24, 2018 at 19:38 | history | edited | Mr. Xcoder | CC BY-SA 3.0 |
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| Jan 24, 2018 at 19:37 | comment | added | Mr. Xcoder |
@JonathanAllan As I expected, yours fails for [1,2,3].
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| Jan 24, 2018 at 19:34 | comment | added | Jonathan Allan | I'm slightly confused since the Python answer with numpy isn't doing so either, and am thinking I've missed some edge case. | |
| Jan 24, 2018 at 19:31 | comment | added | Jonathan Allan |
Is there something I'm missing about taking the (allowed) reverse order and doing Ær+.Ḟ?
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| Jan 24, 2018 at 17:57 | history | edited | Mr. Xcoder | CC BY-SA 3.0 |
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| Jan 24, 2018 at 17:51 | history | edited | Mr. Xcoder | CC BY-SA 3.0 |
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| Jan 24, 2018 at 17:45 | history | edited | Mr. Xcoder | CC BY-SA 3.0 |
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| Jan 24, 2018 at 17:44 | history | undeleted | Mr. Xcoder | ||
| Jan 24, 2018 at 17:40 | history | deleted | Mr. Xcoder | via Vote | |
| Jan 24, 2018 at 17:36 | history | answered | Mr. Xcoder | CC BY-SA 3.0 |