Timeline for Find Integral Roots of A Polynomial
Current License: CC BY-SA 3.0
15 events
| when toggle format | what | by | license | comment | |
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| Jan 25, 2018 at 0:08 | history | edited | Rod | CC BY-SA 3.0 |
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| Jan 24, 2018 at 19:01 | history | edited | Rod | CC BY-SA 3.0 |
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| Jan 24, 2018 at 18:44 | history | edited | Mr. Xcoder | CC BY-SA 3.0 |
You must specify external packages / modules / equivalents
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| Jan 24, 2018 at 18:36 | history | edited | Rod | CC BY-SA 3.0 |
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| Jan 24, 2018 at 18:31 | comment | added | Mr. Xcoder |
Using numpy.polyval saves quite a few bytes
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| Jan 24, 2018 at 17:25 | comment | added | Rod | @Zgarb there, fixed! | |
| Jan 24, 2018 at 17:24 | history | edited | Rod | CC BY-SA 3.0 |
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| Jan 24, 2018 at 17:11 | comment | added | Zgarb | Our current consensus seems to be that programs must always terminate, unless the challenge states otherwise. | |
| Jan 24, 2018 at 16:59 | history | edited | Rod | CC BY-SA 3.0 |
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| Jan 24, 2018 at 16:01 | comment | added | Rod | @LuisMendo yes. | |
| Jan 24, 2018 at 15:29 | history | edited | Rod | CC BY-SA 3.0 |
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| Jan 24, 2018 at 15:27 | comment | added | ovs | 91 bytes | |
| Jan 24, 2018 at 15:22 | history | edited | Rod | CC BY-SA 3.0 |
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| Jan 24, 2018 at 15:17 | history | edited | Rod | CC BY-SA 3.0 |
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| Jan 24, 2018 at 15:10 | history | answered | Rod | CC BY-SA 3.0 |