Timeline for Exponential-ish number sequence
Current License: CC BY-SA 3.0
13 events
when toggle format | what | by | license | comment | |
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Dec 28, 2017 at 12:17 | comment | added | FlipTack | 54 using the OP's method, but probably can't be golfed to be shorter than yours | |
Dec 27, 2017 at 22:19 | history | edited | Mr. Xcoder | CC BY-SA 3.0 |
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Dec 27, 2017 at 21:47 | history | edited | Wheat Wizard♦ | CC BY-SA 3.0 |
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Dec 27, 2017 at 21:47 | comment | added | Mr. Xcoder | @WheatWizard Since this is kolmo-complexity, recursion should (theoretically) not be shorter | |
Dec 27, 2017 at 21:46 | comment | added | Wheat Wizard♦ | Don't know if it helps but, f(n)=2*(f(n-1)+n) for all n except 0 | |
Dec 27, 2017 at 21:42 | history | edited | Mr. Xcoder | CC BY-SA 3.0 |
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Dec 27, 2017 at 21:41 | comment | added | Mr. Xcoder | @WheatWizard Thanks! That was the cleverish trick I was looking for! | |
Dec 27, 2017 at 21:40 | comment | added | Wheat Wizard♦ | 51 | |
Dec 27, 2017 at 20:58 | history | edited | Mr. Xcoder | CC BY-SA 3.0 |
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Dec 27, 2017 at 20:51 | history | edited | Mr. Xcoder | CC BY-SA 3.0 |
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Dec 27, 2017 at 20:38 | comment | added | Steadybox |
I wrote exactly the same for i in range(18):print(2**i-i)*2-(i<1) print"NOPE!" solution, but was too late, it seems :)
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Dec 27, 2017 at 20:33 | history | edited | Mr. Xcoder | CC BY-SA 3.0 |
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Dec 27, 2017 at 20:26 | history | answered | Mr. Xcoder | CC BY-SA 3.0 |