deleted 3 characters in body

Source Link

edited Dec 3, 2017 at 1:25

16.5k
5
41
84

C, 210 192190 bytes

Thanks to @l4m2 for saving 17 bytes!

i,k,t,s;f(char*g){char*p=g,l[strlen(g)];for(s=t=0;*p;*p>35&&(t?l[i++]=*p:1)?*p=32:0,*p++-35&t&&++s~*p++&t&&++s)t^=*p==35;for(k=i;i;t&*p==32?*p=l[--i]:0)t^=*--p==35;printf("%s\n%d",g,k?k-s?k*2<s?1:2:3:0);}

Outputs 0 for empty glass, 1 for mostly empty, 2 for mostly full, and 3 for full.

First loops through the input string counting the space inside the glass, marking down letters that are inside the glass, and changing all letters to spaces. Then loops through the string backwards placing all the letters that were in the glass at the bottom of the glass.

Try it online!Try it online!

Unrolled:

i,k,t,s;
f(char*g)
{
    char l[strlen(g)], *p=g;
    for (s=t=0; *p; *p>35&&(t?l[i++]=*p:1)?*p=32:0, *p++-35&t&&++s~*p++&t&&++s)
        t ^= *p==35;
    for (k=i; i; t&*p==32?*p=l[--i]:0)
        t ^= *--p==35;
    printf("%s\n%d", g, k?k-s?k*2<s?1:2:3:0);
}

C, 210 192 bytes

Thanks to @l4m2 for saving 17 bytes!

i,k,t,s;f(char*g){char*p=g,l[strlen(g)];for(s=t=0;*p;*p>35&&(t?l[i++]=*p:1)?*p=32:0,*p++-35&t&&++s)t^=*p==35;for(k=i;i;t&*p==32?*p=l[--i]:0)t^=*--p==35;printf("%s\n%d",g,k?k-s?k*2<s?1:2:3:0);}

Outputs 0 for empty glass, 1 for mostly empty, 2 for mostly full, and 3 for full.

First loops through the input string counting the space inside the glass, marking down letters that are inside the glass, and changing all letters to spaces. Then loops through the string backwards placing all the letters that were in the glass at the bottom of the glass.

Try it online!

Unrolled:

i,k,t,s;
f(char*g)
{
    char l[strlen(g)], *p=g;
    for (s=t=0; *p; *p>35&&(t?l[i++]=*p:1)?*p=32:0, *p++-35&t&&++s)
        t ^= *p==35;
    for (k=i; i; t&*p==32?*p=l[--i]:0)
        t ^= *--p==35;
    printf("%s\n%d", g, k?k-s?k*2<s?1:2:3:0);
}

C, 190 bytes

Thanks to @l4m2 for saving 17 bytes!

i,k,t,s;f(char*g){char*p=g,l[strlen(g)];for(s=t=0;*p;*p>35&&(t?l[i++]=*p:1)?*p=32:0,~*p++&t&&++s)t^=*p==35;for(k=i;i;t&*p==32?*p=l[--i]:0)t^=*--p==35;printf("%s\n%d",g,k?k-s?k*2<s?1:2:3:0);}

Outputs 0 for empty glass, 1 for mostly empty, 2 for mostly full, and 3 for full.

First loops through the input string counting the space inside the glass, marking down letters that are inside the glass, and changing all letters to spaces. Then loops through the string backwards placing all the letters that were in the glass at the bottom of the glass.

Try it online!

Unrolled:

i,k,t,s;
f(char*g)
{
    char l[strlen(g)], *p=g;
    for (s=t=0; *p; *p>35&&(t?l[i++]=*p:1)?*p=32:0, ~*p++&t&&++s)
        t ^= *p==35;
    for (k=i; i; t&*p==32?*p=l[--i]:0)
        t ^= *--p==35;
    printf("%s\n%d", g, k?k-s?k*2<s?1:2:3:0);
}

deleted 3 characters in body

Source Link

edited Dec 3, 2017 at 0:56

Steadybox

16.5k
5
41
84

C, 210 192 bytes

Thanks to @l4m2 for saving 17 bytes!

i,k,t,s;f(char*g){char*p=g,l[strlen(g)];for(s=t=0;*p;*p>35&&(t?l[i++]=*p:1)?*p=32:0,*p++-35&t&&++s)t^=*p==35;for(k=i;i;t&*p==32?*p=l[--i]:0)t^=*--p==35;printf("%s\n%d",g,k?k-s?k*2<s?1:2:3:0);}

Outputs 0 for empty glass, 1 for mostly empty, 2 for mostly full, and 3 for full.

First loops through the input string counting the space inside the glass, marking down letters that are inside the glass, and changing all letters to spaces. Then loops through the string backwards placing all the letters that were in the glass at the bottom of the glass.

Try it online!

Unrolled:

i,k,t,s;
f(char*g)
{
    char l[strlen(g)], *p=g;
    for (s=t=0; *p; *p>35&&(t?l[i++]=*p:1)?*p=32:0, *p++-35&t&&++s)
        t ^= *p==35;
    for (k=i; i; t&*p==32 && (?*p=l[--i]):0)
        t ^= *--p==35;
    printf("%s\n%d", g, k?k-s?k*2<s?1:2:3:0);
}

C, 210 192 bytes

Thanks to @l4m2 for saving 17 bytes!

i,k,t,s;f(char*g){char*p=g,l[strlen(g)];for(s=t=0;*p;*p>35&&(t?l[i++]=*p:1)?*p=32:0,*p++-35&t&&++s)t^=*p==35;for(k=i;i;t&*p==32?*p=l[--i]:0)t^=*--p==35;printf("%s\n%d",g,k?k-s?k*2<s?1:2:3:0);}

Outputs 0 for empty glass, 1 for mostly empty, 2 for mostly full, and 3 for full.

First loops through the input string counting the space inside the glass, marking down letters that are inside the glass, and changing all letters to spaces. Then loops through the string backwards placing all the letters that were in the glass at the bottom of the glass.

Try it online!

Unrolled:

i,k,t,s;
f(char*g)
{
    char l[strlen(g)], *p=g;
    for (s=t=0; *p; *p>35&&(t?l[i++]=*p:1)?*p=32:0, *p++-35&t&&++s)
        t ^= *p==35;
    for (k=i; i; t&*p==32 && (*p=l[--i]))
        t ^= *--p==35;
    printf("%s\n%d", g, k?k-s?k*2<s?1:2:3:0);
}

C, 210 192 bytes

Thanks to @l4m2 for saving 17 bytes!

i,k,t,s;f(char*g){char*p=g,l[strlen(g)];for(s=t=0;*p;*p>35&&(t?l[i++]=*p:1)?*p=32:0,*p++-35&t&&++s)t^=*p==35;for(k=i;i;t&*p==32?*p=l[--i]:0)t^=*--p==35;printf("%s\n%d",g,k?k-s?k*2<s?1:2:3:0);}

Outputs 0 for empty glass, 1 for mostly empty, 2 for mostly full, and 3 for full.

First loops through the input string counting the space inside the glass, marking down letters that are inside the glass, and changing all letters to spaces. Then loops through the string backwards placing all the letters that were in the glass at the bottom of the glass.

Try it online!

Unrolled:

i,k,t,s;
f(char*g)
{
    char l[strlen(g)], *p=g;
    for (s=t=0; *p; *p>35&&(t?l[i++]=*p:1)?*p=32:0, *p++-35&t&&++s)
        t ^= *p==35;
    for (k=i; i; t&*p==32?*p=l[--i]:0)
        t ^= *--p==35;
    printf("%s\n%d", g, k?k-s?k*2<s?1:2:3:0);
}

deleted 3 characters in body

Source Link

edited Dec 3, 2017 at 0:50

Steadybox

16.5k
5
41
84

C, 210 195192 bytes

Thanks to @l4m2 for saving 1517 bytes!

i,k,t,s;f(char*g){char char*p=g,l[strlen(g)],*p=g;for];for(s=t=0;*p;*p>35&&(t?l[i++]=*p:1)&&(?*p=32):0,*p++-35&t&&++s)t^=*p==35;for(k=i;i;t&*p==32&&(k=i;i;t&*p==32?*p=l[--i]):0)t^=*--p==35;printf("%s\n%d",g,k?k-s?k*2<s?1:2:3:0);}

Outputs 0 for empty glass, 1 for mostly empty, 2 for mostly full, and 3 for full.

First loops through the input string counting the space inside the glass, marking down letters that are inside the glass, and changing all letters to spaces. Then loops through the string backwards placing all the letters that were in the glass at the bottom of the glass.

Try it online!Try it online!

Unrolled:

i,k,t,s;
f(char*g)
{
    char l[strlen(g)], *p=g;
    for (s=t=0; *p; *p>35&&(t?l[i++]=*p:1)&&(?*p=32):0, *p++-35&t&&++s)
        t ^= *p==35;
    for (k=i; i; t&*p==32 && (*p=l[--i]))
        t ^= *--p==35;
    printf("%s\n%d", g, k?k-s?k*2<s?1:2:3:0);
}

C, 210 195 bytes

Thanks to @l4m2 for saving 15 bytes!

i,k,t,s;f(char*g){char l[strlen(g)],*p=g;for(s=t=0;*p;*p>35&&(t?l[i++]=*p:1)&&(*p=32),*p++-35&t&&++s)t^=*p==35;for(k=i;i;t&*p==32&&(*p=l[--i]))t^=*--p==35;printf("%s\n%d",g,k?k-s?k*2<s?1:2:3:0);}

Outputs 0 for empty glass, 1 for mostly empty, 2 for mostly full, and 3 for full.

First loops through the input string counting the space inside the glass, marking down letters that are inside the glass, and changing all letters to spaces. Then loops through the string backwards placing all the letters that were in the glass at the bottom of the glass.

Try it online!

Unrolled:

i,k,t,s;
f(char*g)
{
    char l[strlen(g)], *p=g;
    for (s=t=0; *p; *p>35&&(t?l[i++]=*p:1)&&(*p=32), *p++-35&t&&++s)
        t ^= *p==35;
    for (k=i; i; t&*p==32 && (*p=l[--i]))
        t ^= *--p==35;
    printf("%s\n%d", g, k?k-s?k*2<s?1:2:3:0);
}

C, 210 192 bytes

Thanks to @l4m2 for saving 17 bytes!

i,k,t,s;f(char*g){char*p=g,l[strlen(g)];for(s=t=0;*p;*p>35&&(t?l[i++]=*p:1)?*p=32:0,*p++-35&t&&++s)t^=*p==35;for(k=i;i;t&*p==32?*p=l[--i]:0)t^=*--p==35;printf("%s\n%d",g,k?k-s?k*2<s?1:2:3:0);}

Outputs 0 for empty glass, 1 for mostly empty, 2 for mostly full, and 3 for full.

First loops through the input string counting the space inside the glass, marking down letters that are inside the glass, and changing all letters to spaces. Then loops through the string backwards placing all the letters that were in the glass at the bottom of the glass.

Try it online!

Unrolled:

i,k,t,s;
f(char*g)
{
    char l[strlen(g)], *p=g;
    for (s=t=0; *p; *p>35&&(t?l[i++]=*p:1)?*p=32:0, *p++-35&t&&++s)
        t ^= *p==35;
    for (k=i; i; t&*p==32 && (*p=l[--i]))
        t ^= *--p==35;
    printf("%s\n%d", g, k?k-s?k*2<s?1:2:3:0);
}

deleted 8 characters in body

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edited Dec 2, 2017 at 20:35

Steadybox

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added 49 characters in body

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edited Dec 2, 2017 at 18:29

Steadybox

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added 276 characters in body

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edited Dec 2, 2017 at 18:01

Steadybox

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added 276 characters in body

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edited Dec 2, 2017 at 17:55

Steadybox

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deleted 5 characters in body

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edited Dec 2, 2017 at 17:46

Steadybox

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added 40 characters in body

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edited Dec 2, 2017 at 17:41

Steadybox

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created Dec 2, 2017 at 17:29

Steadybox

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C, 210 192190 bytes

C, 210 192 bytes

C, 190 bytes

C, 210 192 bytes

C, 210 192 bytes

C, 210 192 bytes

C, 210 195192 bytes

C, 210 195 bytes

C, 210 192 bytes