#cQuents, cracked by Mayube

#|1,1:A

This should be fairly easy, but you never know.

The "problem" was that without C in your code, you got an error.

Mayube's solution:

#|1,1:A+BC

Each item in the sequence is the first input plus the second times the third (aka 1)

My solutions:

#1,1:A+B,C

The sequence cycles between the first input plus the second input, and the third input (1). The first item in the second is A+B.

#1,1:A+B+C-C

Similar to Mayube's solution - instead of multiplying B*C, just adds C and then subtracts it.

Try it online!

###Explanation

#|1,1      Append 1 and 1 to the end of the user's input
     :     Set mode to : (sequence 1: if given n, output nth term in sequence; if given no n, output whole sequence)
      A    Each item in the sequence equals the first input

Currently, this program outputs 1, since with no user input, the first input is the first 1 in the default input (#).

cQuents, cracked by Mayube

#|1,1:A

This should be fairly easy, but you never know.

The "problem" was that without C in your code, you got an error.

Mayube's solution:

#|1,1:A+BC

Each item in the sequence is the first input plus the second times the third (aka 1)

My solutions:

#1,1:A+B,C

The sequence cycles between the first input plus the second input, and the third input (1). The first item in the second is A+B.

#1,1:A+B+C-C

Similar to Mayube's solution - instead of multiplying B*C, just adds C and then subtracts it.

Try it online!

Explanation

#|1,1      Append 1 and 1 to the end of the user's input
     :     Set mode to : (sequence 1: if given n, output nth term in sequence; if given no n, output whole sequence)
      A    Each item in the sequence equals the first input

Currently, this program outputs 1, since with no user input, the first input is the first 1 in the default input (#).

#cQuents

#|1,1:A

This should be fairly easy, but you never know.

Try it online!

###Explanation

#|1,1      Append 1 and 1 to the end of the user's input
     :     Set mode to : (sequence 1: if given n, output nth term in sequence; if given no n, output whole sequence)
      A    Each item in the sequence equals the first input

Currently, this program outputs 1, since with no user input, the first input is the first 1 in the default input (#).

#cQuents, cracked by Mayube

#|1,1:A

This should be fairly easy, but you never know.

The "problem" was that without C in your code, you got an error.

Mayube's solution:

#|1,1:A+BC

Each item in the sequence is the first input plus the second times the third (aka 1)

My solutions:

#1,1:A+B,C

The sequence cycles between the first input plus the second input, and the third input (1). The first item in the second is A+B.

#1,1:A+B+C-C

Similar to Mayube's solution - instead of multiplying B*C, just adds C and then subtracts it.

Try it online!

###Explanation

#|1,1      Append 1 and 1 to the end of the user's input
     :     Set mode to : (sequence 1: if given n, output nth term in sequence; if given no n, output whole sequence)
      A    Each item in the sequence equals the first input

Currently, this program outputs 1, since with no user input, the first input is the first 1 in the default input (#).

#cQuents

#|1,1:A

This should be fairly easy, but you never know.

Try it online!

#cQuents

#|1,1:A

This should be fairly easy, but you never know.

Try it online!

###Explanation

#|1,1      Append 1 and 1 to the end of the user's input
     :     Set mode to : (sequence 1: if given n, output nth term in sequence; if given no n, output whole sequence)
      A    Each item in the sequence equals the first input

Currently, this program outputs 1, since with no user input, the first input is the first 1 in the default input (#).