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hyperneutrino
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Jelly: CRACKED

This will be insanely easy compared to Wheat Wizard's awesome Python answer, but here we go :P

“for c in code_page:
 if c in atoms:atoms[c].call=None”ŒVø<insert code snippet here>

The sha256 hexdigest of my workaround solution, including the first snippet, is cfeb1e193ad77f66f039c0d6a792a3e4c311490f6412698e019ca1fae10c0e0a.

Note

You may not have any newlines in the code except for strings otherwise this code will not even be run, which defeats the purpose of this challenge.

Cracked by DJMcMayhem

To be fair, this uses a newline, so I'd like to see a solution that doesn't use a newline.

Also a solution by Jonathan Allan

This doesn't use a newline, so it's been cracked. :P

My solution is this:

“for c in code_page:
 if c in atoms:atoms[c].call=None”ŒVø“print(int(input())+int(input()))”ŒV

The first snippet only deletes single character atoms which means that Python eval still works :)))

Jelly

This will be insanely easy compared to Wheat Wizard's awesome Python answer, but here we go :P

“for c in code_page:
 if c in atoms:atoms[c].call=None”ŒVø<insert code snippet here>

The sha256 hexdigest of my workaround solution, including the first snippet, is cfeb1e193ad77f66f039c0d6a792a3e4c311490f6412698e019ca1fae10c0e0a.

Note

You may not have any newlines in the code except for strings otherwise this code will not even be run, which defeats the purpose of this challenge.

Jelly: CRACKED

This will be insanely easy compared to Wheat Wizard's awesome Python answer, but here we go :P

“for c in code_page:
 if c in atoms:atoms[c].call=None”ŒVø<insert code snippet here>

The sha256 hexdigest of my workaround solution, including the first snippet, is cfeb1e193ad77f66f039c0d6a792a3e4c311490f6412698e019ca1fae10c0e0a.

Note

You may not have any newlines in the code except for strings otherwise this code will not even be run, which defeats the purpose of this challenge.

Cracked by DJMcMayhem

To be fair, this uses a newline, so I'd like to see a solution that doesn't use a newline.

Also a solution by Jonathan Allan

This doesn't use a newline, so it's been cracked. :P

My solution is this:

“for c in code_page:
 if c in atoms:atoms[c].call=None”ŒVø“print(int(input())+int(input()))”ŒV

The first snippet only deletes single character atoms which means that Python eval still works :)))

Post Undeleted by hyperneutrino
Post Deleted by hyperneutrino
added 161 characters in body
Source Link
hyperneutrino
  • 42.6k
  • 5
  • 68
  • 224

Jelly

This will be insanely easy compared to Wheat WizardsWizard's awesome Python answer, but here we go :P

“for c in code_page:
 if c in atoms:atoms[c].call=None”ŒVø<insert code snippet here>

The sha256 hexdigest of my workaround solution, including the first snippet, is cfeb1e193ad77f66f039c0d6a792a3e4c311490f6412698e019ca1fae10c0e0a.

Note

You may not have any newlines in the code except for strings otherwise this code will not even be run, which defeats the purpose of this challenge.

Jelly

This will be insanely easy compared to Wheat Wizards awesome Python answer, but here we go :P

“for c in code_page:
 if c in atoms:atoms[c].call=None”ŒVø<insert code snippet here>

The sha256 hexdigest of my workaround solution, including the first snippet, is cfeb1e193ad77f66f039c0d6a792a3e4c311490f6412698e019ca1fae10c0e0a.

Jelly

This will be insanely easy compared to Wheat Wizard's awesome Python answer, but here we go :P

“for c in code_page:
 if c in atoms:atoms[c].call=None”ŒVø<insert code snippet here>

The sha256 hexdigest of my workaround solution, including the first snippet, is cfeb1e193ad77f66f039c0d6a792a3e4c311490f6412698e019ca1fae10c0e0a.

Note

You may not have any newlines in the code except for strings otherwise this code will not even be run, which defeats the purpose of this challenge.

Post Undeleted by hyperneutrino
Post Deleted by hyperneutrino
Source Link
hyperneutrino
  • 42.6k
  • 5
  • 68
  • 224

Jelly

This will be insanely easy compared to Wheat Wizards awesome Python answer, but here we go :P

“for c in code_page:
 if c in atoms:atoms[c].call=None”ŒVø<insert code snippet here>

The sha256 hexdigest of my workaround solution, including the first snippet, is cfeb1e193ad77f66f039c0d6a792a3e4c311490f6412698e019ca1fae10c0e0a.