Timeline for Chicken McNugget Numbers
Current License: CC BY-SA 3.0
25 events
| when toggle format | what | by | license | comment | |
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| Jul 16, 2017 at 20:48 | comment | added | David Z | Ah, true. But still the function currently gives an incorrect result for input 0. | |
| Jul 16, 2017 at 20:47 | comment | added | Leaky Nun |
@DavidZ The 0 is still needed for 20 and 40.
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| Jul 16, 2017 at 20:38 | comment | added | David Z | Looks like the post has been updated to exclude 0; I think that saves you a byte? | |
| Jul 16, 2017 at 20:37 | comment | added | Jonah | @LeakyNun that'll do just fine. ty. | |
| Jul 16, 2017 at 20:26 | comment | added | Leaky Nun | @Jonah Chinese Remainder Theorem? | |
| Jul 16, 2017 at 20:21 | comment | added | Jonah | i'm assuming there is a general mathematical theory similar to the technique used here, for solving generalized versions of the same problem. do you know what it's called? | |
| Jul 16, 2017 at 19:29 | history | edited | Leaky Nun | CC BY-SA 3.0 |
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| Jul 16, 2017 at 19:29 | comment | added | xnor | Yes, checked it. Nice method! | |
| Jul 16, 2017 at 19:27 | comment | added | notjagan | Ah, you ninja'd me! I was about to suggest this, but yours is shorter anyhow. | |
| Jul 16, 2017 at 19:27 | comment | added | Leaky Nun | @xnor Is it ok now? | |
| Jul 16, 2017 at 19:23 | history | edited | Leaky Nun | CC BY-SA 3.0 |
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| Jul 16, 2017 at 19:18 | history | edited | Leaky Nun | CC BY-SA 3.0 |
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| Jul 16, 2017 at 19:13 | comment | added | notjagan |
You can remove the f= now since it's not recursive.
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| Jul 16, 2017 at 19:09 | history | edited | Leaky Nun | CC BY-SA 3.0 |
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| Jul 16, 2017 at 18:47 | comment | added | Leaky Nun | @notjagan wow, I didn't know that chaining is short-circuiting. | |
| Jul 16, 2017 at 18:47 | history | edited | Leaky Nun | CC BY-SA 3.0 |
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| Jul 16, 2017 at 18:46 | comment | added | notjagan | 37 bytes. | |
| Jul 16, 2017 at 18:45 | comment | added | Leaky Nun | @Zacharý thanks, updated. | |
| Jul 16, 2017 at 18:45 | history | edited | Leaky Nun | CC BY-SA 3.0 |
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| Jul 16, 2017 at 18:43 | comment | added | Adalynn |
f=lambda n:n%3<1<n-2or n>20and f(n-20) does that work?
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| Jul 16, 2017 at 18:43 | comment | added | Leaky Nun | @Mr.Xcoder updated. | |
| Jul 16, 2017 at 18:43 | history | edited | Leaky Nun | CC BY-SA 3.0 |
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| Jul 16, 2017 at 18:41 | comment | added | Mr. Xcoder | 39 bytes | |
| Jul 16, 2017 at 18:40 | history | edited | Leaky Nun | CC BY-SA 3.0 |
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| Jul 16, 2017 at 18:35 | history | answered | Leaky Nun | CC BY-SA 3.0 |